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Chemical Equations Chemistry Mrs. Coyle. Chemical Equations: represent chemical reactions Word Equations Skeleton Chemical Equations Balanced Chemical.

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Presentation on theme: "Chemical Equations Chemistry Mrs. Coyle. Chemical Equations: represent chemical reactions Word Equations Skeleton Chemical Equations Balanced Chemical."— Presentation transcript:

1 Chemical Equations Chemistry Mrs. Coyle

2 Chemical Equations: represent chemical reactions Word Equations Skeleton Chemical Equations Balanced Chemical Equations

3 Reactants  Products Methane + Oxygen  Carbon Dioxide + Water The arrow (yield sign) and indicates that a reaction took place. Word Equations: show the names of the reactants and the products

4 Skeleton Chemical Equations The formulas of the reactants and products are written without indicating their relative amounts. Example: CH 4 + O 2  CO 2 +H 2 O

5 Balanced Chemical Equations The chemical formulas and the relative amounts of the reactants and products are written. Example: CH 4 + 2O 2  CO 2 + 2H 2 O The coefficients indicate the relative amounts of each substance. Equal number of atoms of each element must appear on both sides of the balanced equation.

6 Why does a chemical reaction have to be balanced? In any chemical or physical change, mass is neither created or destroyed Mass is CONSTANT Law of Conservation of Mass (Antoine Lavoisier)

7 Combustion of Methane CH 4 + 2O 2  CO 2 + 2H 2 O Atoms are rearranged!

8 Example: Decomposition of hydrogen peroxide in the presence of a catalyst. Word equation: hydrogen peroxide  water + oxygen

9 Example: Decomposition of hydrogen peroxide in the presence of a catalyst. Skeleton equation: H 2 O 2  H 2 O + O 2

10 Example: Decomposition of hydrogen peroxide in the presence of a catalyst. Balanced Equation: 2H 2 O 2  2H 2 O + O 2

11 Example: Decomposition of hydrogen peroxide in the presence of a catalyst. Balanced equation showing the catalyst (MnO 2 ) the state of the reactants and products: MnO 2 2H 2 O 2 ( l )  2H 2 O ( l ) + O 2 ( g )


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