Presentation is loading. Please wait.

Presentation is loading. Please wait.

The 4 quadrants 90 2nd quadrant 1st quadrant 0 180 360

Similar presentations


Presentation on theme: "The 4 quadrants 90 2nd quadrant 1st quadrant 0 180 360"— Presentation transcript:

1 The 4 quadrants 90 2nd quadrant 1st quadrant 0 180 360 3rd quadrant 4th quadrant 270

2 Representing Angles 45° Measure from + x-axis
Anti Clockwise Direction for +ve angles CW Direction for –ve angles

3 Representing Angles 45° −45° Measure from + x-axis
Anti Clockwise Direction for +ve angles CW Direction for –ve angles

4 Representing Angles 135° −135° Measure from + x-axis
Anti Clockwise Direction for +ve angles CW Direction for –ve angles

5 Representing Angles 225° −225° Measure from + x-axis
Anti Clockwise Direction for +ve angles CW Direction for –ve angles

6 Special Angles 2 1 Equilateral Δ - equal lengths - equal angles 30
60 1 Assume each length is 2 units, look at half of the Δ.

7 Special Angles 60 30 1 2

8 Special Angles 1 1 isosceles Δ - equal arms - equal base angles 45
Assume each arm is 1 unit.

9 The 4 quadrants 90 2nd quadrant 1st quadrant 0 180 360
sin + cos − tan − sin + cos + tan + 0 180 360 sin − cos − tan + sin − cos + tan − 3rd quadrant 4th quadrant 270

10 S sin + A all + T tan + C cos + The 4 quadrants 90 2nd quadrant
1st quadrant S sin + A all + 0 180 360 T tan + C cos + 3rd quadrant 4th quadrant 270

11 1st quadrant 90 1 2 0 30°

12 2nd quadrant 90 2 1 30° 180

13 3rd quadrant 180 30° −1 2 270

14 4th quadrant 360 30° −1 2 270

15 Example 1 60° 1 2 Step 1: Find the unknown length and determine sin 60° and tan 60 ° 240° B.A = 60° Step 2: Find the basic angle for 240° and determine the quadrant its in.

16 Example 2 45° 1 Step 1: Find the unknown length and determine sin 45° and cos 45 ° 315° B.A = 45° Step 2: Find the basic angle for 315° and determine the quadrant its in.

17 Exercise Q1

18 Exercise Q2

19 Find the angles between 0 and 360 inclusive which satisfy
sin x = Answer: sin x = basic angle = 47.94  x = 47.9 or x = 180  =  or 

20 Find the angles between 0 and 360 inclusive which satisfy
tan x = −1.37 Answer: (1st step: find B.A for tan x = 1.37) basic angle = 53.87 x = 180 − 53.87 =  or x = 360 − 53.87 =   x = 126.1 or 

21 Find the angles between 0 and 360 inclusive which satisfy
cos (x − 27) = − 0.145 Answer: 0 < x < 360 − 27 < x − 27 < 333 basic angle = 81.66 x − 27 = 180 − 81.66 = 98.34  x =  or x − 27 = 180  =   x =   x = 125.3 or 


Download ppt "The 4 quadrants 90 2nd quadrant 1st quadrant 0 180 360"

Similar presentations


Ads by Google