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Published byJoy Robertson Modified over 9 years ago
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Predict the readings on the scales: ? 1030 20 0 ? 1030 20 0 0.5m 1.0 m M bar = 1.0 kg 1.0 kg
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Predict the readings on the scales: 1030 20 0 1030 20 0 0.5m 1.0 m M bar = 1.0 kg 1.0 kg 10 N
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Now predict the readings: ? 1030 20 0 ? 1030 20 0 0.8m 1.0 m M bar = 1.0 kg 1.0 kg a=0
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Which force is most effective in causing rotation? standard frictionless pond standard meter stick F1F1 F2F2 standard pivot point
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Now which force is most effective in causing rotation? standard frictionless pond standard meter stick F1F1 F2F2 standard pivot point
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Definition of torque rF perp
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In practice…. Pivot F = 200 N r = 3 m = r F = (3 m)(200 N) = 600 m - N
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Useful force method: only the component F perp causes torque. Fixed Pivot Point F r = r (F sin F sin = r F perp
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Torque A torque is produced when a force is applied with “leverage”. net torque causes angular acceleration Only the perpendicular force contributes to the Torque.
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Torque net torque causes angular acceleration if the force is applied “off center” If net torque = 0, angular velocity( ) = constant. Doubling the net torque doubles angular acceleration ( ).
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Let’s practice: 200 N ? 1030 20 0 1.0 m 200 N pivot
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Let’s practice: 200 N ? 1030 20 0 1.0 m 400 N pivot 0.5m
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Linear equilibrium: 150 N 100 N ??? N a = 0 F left = F right
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Rotational equilibrium 200 N ? 1030 20 0 1.0 m 800 N pivot 0.25m = 0 1 = 2
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Let’s solve the problem: ? 1030 20 0 ? 1030 20 0 0.8m 1.0 m M bar = 1.0 kg 1.0 kg a = 0 F net = 0 = 0 net = 0
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TLTL TRTR 0.8m 10 N 0.5m 10 N Pivot (10 N)(.5 m) + (10 N)(.8 m) = T R (1 m) T R = 13 NT L = 7 N 1 = 2
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Let’s solve the problem: ? 1030 20 0 ? 1030 20 0 0.6m 1.0 m M bar = 1.0 kg 1.0 kg a = 0 F net = 0 = 0 net = 0
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