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CS-240 Operator Overloading Dick Steflik
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Operator Overloading What is it? –assigning a new meaning to a specific operator when used in the context of a specific class ex. << is normally the shift left operator; but when used in conjunction with the class iostream it becomes the operator insertion; this is because the writers of the iostream class overloaded << to be insertion –cout << “some string” << endl; remember cout is a predefined object of class iostream –in another class, << could be overloaded to mean something.
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Operator Overloading Why do we do it? –the c++ developers felt that it made more sense to overload an operator than to come up with some name for a function than meant the same thing as the operator. –using an overloaded operator takes fewer keystrokes –many people feel that an overloaded operator is more self documenting
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Operator Overloading Three basic ways: –as a free function (not part of a class) –as a member function –as a friend function
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Operator Overloading class Rational { Rational (int, int); const Rational & operator = (const Rational & rhs); const Rational & operator + (const Rational & rhs); bool operator == (const Rational & rhs); int getNumer() const { return numer; } int getDenom() const { return denom; } private: int numer; int denom; }
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Overloading = as a member const Rational & Rational :: operator = (const Rational & rhs) { if (this != &rhs) { numer = rhs.numer; denom = rhs.denom; } return *this } Rational r1, r2; r1 = r2; -note: the if statement catches the special case where someone is trying r1=r1, the if statement makes the code faster
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Overloading + as a member const Rational Rational::operator + (const Rational & rhs) { Rational answer ( *this); // initialize the answer with the current object answer += rhs; // add the second operand (assumes += has been overloaded) return answer; // return the answer via the copy constructor }
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Overloading == as a free function // not defined in the Rational class bool operator == (const & Rational lhs, const & Rational rhs) { return (lhs.getDenom() * rhs.getNumer() == lhs.getNumer() * rhs.getDenom()); } Rational r1, r2; if ( r1 == r2 ) cout……… else cout
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Overloading == as a member const bool Rational::operator == (const Rational & rhs ) { return ( numer * rhs.denom == denom * rhs.numer); } Rational r1, r2 ; if (r1 == r2 ) cout ……. else cout ……
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Friend Functions not a member function has access to private data member functions work with the current (named object) friend functions work with multiple objects of the same class tag as a friend of the class –as part of class definition identify, by prototype, each friend of the class
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Friend Functions (cont.) Friend functions are needed in C++ due to C++’s flawed object model, Java has a better model (all objects are derived from a single object). define the prototype in the public section of the class definition precede the prototype with the keyword “friend”
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Friend Functions (more) define the friend implementation in the.cpp file with the member functions do not precede the function name with the class name and the scoping operator (ex. classname::)
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Overloading == as a friend class Rational { Rational (int, int); const Rational & operator = (const Rational & rhs); const Rational & operator + (const Rational & rhs); friend bool operator == (const Rational & lhs, const Rational & rhs); private: int numer; int denom; } bool operator == (const Rational & lhs, const Rational & rhs) { return ( lhs.numer * rhs.denom == lhs.denom * rhs.numer); }
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Overloading << as a friend class Rational { Rational (int, int); const Rational & operator = (const Rational & rhs); const Rational & operator + (const Rational & rhs); friend ostream & operator << (ostream & ostr, const Rational * rhs); private: int numer; int denom; } ostream & operator << (ostream & ostr, const Rational * rhs) { ostr << “numerator = “ << rhs.numer << “ denominator = “ << rhs.denom; }
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More Overloading Thoughts = overload as a member function == != = overload as a member >> << (insertion and extraction) overload as non-members (friends) returning type iostream +-*/% (arithmetics) overload as members += -=... overload same as + and -
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Please note: The only operators that cannot be overloaded are –. (dot operator) –.* (pointer-to-member) –sizeof –?: (three operands)
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Only existing operators can be overloaded. new operators cannot be created (have to be made a named function member)
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