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Coloring k-colorable graphs using smaller palettes Eran Halperin Ram Nathaniel Uri Zwick Tel Aviv University
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New coloring results Coloring k-colorable graphs of maximum degree using -2/k log 1/k colors (instead of -2/k log 1/2 colors [KMS])
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New coloring results Coloring k-colorable graphs using n (k) colors (instead of n (k) colors [KMS])
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An extension of Alon-Kahale AK: If a graph contains an independent set of size n/k+m, k integer, then an independent set of size m 3/(k+1) can be found in polynomial time. Extension: If a graph contains an independent set of size n then an independent set of size n f( can be found in polynomial time, where
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Graph coloring basics If in any k-colorable graph on n vertices we can find, in polynomial time, one of Two vertices that have the same color under some valid k-coloring ; An independent set of size (n 1- ) ; then we can color any k-colorable graph using O(n ) colors.
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Coloring 3-colorable graphs using O(n 1/2 ) colors [Wigderson] A graph with maximum degree can be easily colored using colors. If < n 1/2, color using colors. Otherwise, let v be a vertex of degree hen, N(v) is 2-colorable and contains an independent set of size n 1/2 /2
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Vector k-Coloring [KMS] A vector k-coloring of a graph G=(V,E) is a sequence of unit vectors v 1,v 2,…,v n such that if (i,j) in E then =-1/(k-1).
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Finding large independent sets Let G=(V,E) be a 3-colorable graph. Let r be a random normally distributed vector in R n. Let. I’ is obtained from I by removing a vertex from each edge of I.
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Constructing the sets I and I’
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Analysis
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Analysis (Cont.)
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A simple observation Either G[N(u,v)] is (k-2)-colorable, or u and v get the same color under any a k-coloring of G. Suppose G=(V,E) is k-colorable.
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A lemma of Blum Let G=(V,E) be a k-colorable graph with minimum degree for every Then, it is possible to construct, in polynomial time, a collection {T i } of about n subsets of V such that at least one T i satisfies: |T i |= s) T i has an independent subset of size
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A lemma of Blum
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Graph coloring techniques Wigderson Karger Motwani Sudan Blum Alon Kahale Our Algorithm Blum Karger
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The new algorithm Step 0: If k=2, color the graph using 2 colors. If k=3, color the graph using n 3/14 colors using the algorithm of Blum and Karger.
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The new algorithm Step 1: Repeatedly remove from the graph vertices of degree at most n (k)/(1-2/k). Let U be the set of vertices removed, and W=V-U. Average degree of G[U] is at most n (k)/(1-2/k). Minimum degree of G[W] at least n (k)/(1-2/k). If |U|>n/2, use [KMS] to find an independent set of size n/D 1-2/k = n 1- k).
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Step 1 Average degree of G[U] is at most . Minimum degree of G[W] at least . Let n (k)/(1-2/k).
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The new algorithm Step 2: For every u,v such that N(u,v)>n (1- (k)/(1- (k-2)), apply the algorithm recursively on G[N(u,v)] and k-2. If G[N(u,v)] is (k-2)-colorable, we get an independent set of size |N(u,v)| 1- (k-2) >n 1- (k). Otherwise, we can infer * that u and v must be assigned the same color.
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The new algorithm Step 3: If we reach this step then |W|>n/2, the minimum degree of G[W] is at least n (k)/(1-2/k), and for every u,v in W, N(u,v)>n (1- (k)/(1- (k-2)). By Blum’s lemma, we can find a collection {T i } of about n subsets of W such that at least one T i satisfies |T i |= s) and T i has an independent subset of size. By the extension of the Alon-Kahale result, we can find an IS of size
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The recurrence relation
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Hardness results It is NP-hard to 4-color 3-colorable graphs [Khanna,Linial,Safra ‘93] [Guruswami,Khanna ‘00] For any k, it is NP-hard to k-color 2-colorable hypergraphs [Guruswami,Hastad,Sudan ‘00]
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