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Chem 1310: Introduction to physical chemistry Part 2: exercise 55, p662 Reaction of p-methylphenyl acetate with imidazole.

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Presentation on theme: "Chem 1310: Introduction to physical chemistry Part 2: exercise 55, p662 Reaction of p-methylphenyl acetate with imidazole."— Presentation transcript:

1 Chem 1310: Introduction to physical chemistry Part 2: exercise 55, p662 Reaction of p-methylphenyl acetate with imidazole

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3 Show the raw data T(°C)k (L mol -1 s -1 ) 102.34E-02 183.25E-02 254.50E-02 355.83E-02 427.50E-02 601.52E-01

4 Prepare data for the Arrhenius plot 1/T (K -1 )T(K)T(°C)k (L mol -1 s -1 )ln k 0.003532283.15102.34E-02-3.76 0.003435291.15183.25E-02-3.43 0.003354298.15254.50E-02-3.10 0.003245308.15355.83E-02-2.84 0.003173315.15427.50E-02-2.59 0.003002333.15601.52E-01-1.88

5 Extract the data 1/T (K -1 )T(K)T(°C)k (L mol -1 s -1 )ln k 0.003532283.15102.34E-02-3.76 0.003435291.15183.25E-02-3.43 0.003354298.15254.50E-02-3.10 0.003245308.15355.83E-02-2.84 0.003173315.15427.50E-02-2.59 0.003002333.15601.52E-01-1.88 slope = -3442.75 (K) R = 8.314 J mol -1 K -1 E a = -R*slope = 28.6 kJ/mol intercept = 8.39 A = e intercept = 4400 (L mol -1 s -1 ) Predict rate at 100°C: rate = 4400*e -28600/(8.314*373.15) = 0.43 L mol-1s-1

6 Extrapolation, very sensitive to errors! 1/T (K -1 )T(K)T(°C)k (L mol -1 s -1 )ln k 0.003532283.15102.34E-02-3.76 0.003435291.15183.25E-02-3.43 0.003354298.15254.50E-02-3.10 0.003245308.15355.83E-02-2.84 0.003173315.15427.50E-02-2.59 0.003002333.15601.32E-01-1.88 slope = -3442.75 (K) R = 8.314 J mol -1 K -1 E a = -R*slope = 26.8 kJ/mol (was 28.6) intercept = 8.39 A = e intercept = 2070 L mol -1 s -1 (was 4400)

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