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1 Call Admission Control Carey Williamson Department of Computer Science University of Calgary
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2 The CAC Function: Everything you ever wanted to know but were afraid to ask Carey Williamson Department of Computer Science University of Saskatchewan
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3 Introduction u The purpose of an admission control algorithm is to decide, at the time of call arrival, whether or not a new call should be admitted into the network u A new call is admitted if and only if its Quality of Service (QOS) constraints can be satisfied without jeapordizing the QOS constraints of existing calls in the network
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4 Call Admission Control u Admission control decision is made using a traffic descriptor that specifies traffic characteristics and QOS requirements u Traffic characteristics: –peak cell rate (PCR), sustained cell rate (SCR), maximum burst size (MBS),... u QOS requirements: –tolerable cell loss, cell delay, delay variation
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5 Issues u Want to make efficient use of the network (i.e., accommodate as many calls as possible, and maintain a reasonably high level of network utilization) u Want to guarantee quality of service for all calls that get into the network u Tradeoff: can’t always have both!
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6 Why is it Difficult? u ATM is completely based on the idea of statistical multiplexing of VBR sources u No assignment of specific slots to users, but statistical assignment of capacity based on expected traffic characteristics u Providing guarantees requires conservatism u High utilization requires aggressiveness
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7 Why is it Difficult? (Cont’d) u Typical traffic sources are bursty u Some traffic sources are VERY bursty u Traffic can be highly unpredictable u Accurate traffic descriptors may not be known in advance u Traffic may not conform to its descriptor
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Least Understood Most Understood Traffic Characterization
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Least Understood Most Understood Voice Traffic Characterization
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Least Understood Most Understood Voice CBR video Traffic Characterization
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Least Understood Most Understood Voice CBR video Packet data Traffic Characterization
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Least Understood Most Understood Voice CBR video Packet data Traffic Characterization Image
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Least Understood Most Understood Voice CBR video Packet data Image VBR video Traffic Characterization
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14 Multiplexing u Two basic approaches u Deterministic multiplexing u Statistical multiplexing
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15 Deterministic Multiplexing u The traditional means of bandwidth allocation in telecommunications networks u Each traffic type has an inherent bit rate (e.g., voice traffic = 64 kilobits per second) u Allocate precisely that bandwidth for each call, for the duration of the call
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16 Deterministic Multiplexing (Cont’d) u Advantages: –Simple –Works great for CBR traffic (PCR = SCR) u Disadvantages: –Inefficient for VBR traffic (PCR !=SCR) u Allocating PCR can waste lots of capacity
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Deterministic versus Statistical Multiplexing Bit rate Source 1: peak 12 Mbps, mean 8 Mbps
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Deterministic versus Statistical Multiplexing Bit rate 12 Mbps
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Deterministic versus Statistical Multiplexing Bit rate Source 2: peak 10 Mbps, mean 6 Mbps
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Deterministic versus Statistical Multiplexing Bit rate 22 Mbps (12 + 10)
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Deterministic versus Statistical Multiplexing Bit rate 22 Mbps (12 + 10) Average utilization will be 14/22 = 64%
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Deterministic versus Statistical Multiplexing Bit rate
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Deterministic versus Statistical Multiplexing Bit rate
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Deterministic versus Statistical Multiplexing Bit rate
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Deterministic versus Statistical Multiplexing Bit rate
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Deterministic versus Statistical Multiplexing Bit rate
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Deterministic versus Statistical Multiplexing Bit rate
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Deterministic versus Statistical Multiplexing Bit rate
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Deterministic versus Statistical Multiplexing Bit rate
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Deterministic versus Statistical Multiplexing Bit rate
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Deterministic versus Statistical Multiplexing Bit rate Bandwidth saving with Statistical Multiplexing
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32 Statistical Multiplexing u Basic idea: ‘‘pack in’’ more than would be able to fit with deterministic multiplexing u Takes advantage of the variable bit rate bursty nature of traffic u Not all traffic sources will need their peak rate at the same time (hopefully) u Peaks and valleys should balance out
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33 Statistical Multiplexing (Cont’d) u Advantages: –More calls can fit in the network –Increases utilization, efficiency of network –Statistical gain can be significant u Disadvantages: –QOS is hard to guarantee (100% guarantee) u Always an element of risk, however slight
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34 Simple CAC Schemes int CAC_Function(TrafficDescriptor *TD) { return( YES ); }
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35 Simple CAC Schemes int CAC_Function(TrafficDescriptor *TD) { return( YES ); }
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36 Simple CAC Schemes (Cont’d) int CAC_Function(TrafficDescriptor *TD) { return( NO ); }
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37 Simple CAC Schemes (Cont’d) int CAC_Function(TrafficDescriptor *TD) { return( NO ); }
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38 Possible CAC Schemes u Peak rate allocation u Mean rate allocation u (Peak + Mean) / 2 u Virtual Bandwidth [Murase 90] u Schedulable Region [Lazar 91] u Effective Bandwidth [Elwalid 93]
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39 Peak Rate Allocation u Allocate the peak cell rate for the source u Same as Deterministic Multiplexing u Guarantees that no cell loss occurs u Guarantees that bandwidth is wasted if source is at all bursty (peak > mean) u The amount of wasted bandwidth depends on the peak-to-mean ratio
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40 Mean Rate Allocation u Allocate bandwidth based on the mean rate (SCR) u By definition, this is adequate over a long enough time duration u Drawback is the delay for traffic bursts u May not be enough capacity to handle bursts within a tolerable delay
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41 (Peak + Mean) / 2 u Peak rate is the most that is needed u Mean rate is the least that is needed u ‘‘Correct’’ allocation must be in between u But where is the real question! u (Peak + Mean) / 2 is one guess u Suitability depends on characteristics of source (e.g., time spent at or near each)
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42 Can you do better? u Of course! u Effective Bandwidth: [Elwalid 93] u Virtual Bandwidth: [Murase 90] u Schedulable Region: [Lazar 91] u We’ll look at some of these in more detail in just a moment...
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43 Summary u Call Admission Control is one of the most difficult problems to deal with in ATM networks u Difficult problem, no standard solution u Lots of research activity u Impossible to find a single ‘‘best’’ answer
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