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Slides for the discussion Cosmic ray density. Cosmic ray density. Cosmic ray is  useful for the alignment between plates. Decay search Momentum measurement.

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Presentation on theme: "Slides for the discussion Cosmic ray density. Cosmic ray density. Cosmic ray is  useful for the alignment between plates. Decay search Momentum measurement."— Presentation transcript:

1 Slides for the discussion Cosmic ray density

2 Cosmic ray density. Cosmic ray is  useful for the alignment between plates. Decay search Momentum measurement  not necessary for the location. Higher density  Fake (cosmic ray) interaction. Bern example.  Fake stop  Multi candidates in CS->ECC connection. Lower density  Momentum measurement accuracy?. Maximum measurable momentum.

3 ECC with black CS (current Nagoya strategy.)‏ 1.General scan the downstream plates(3~5). 2.search vertex candidates. 3.Scanback or Direct vertexing. Strong worry about the 2 nd, 3 rd, vertex by cosmic ray. --> no cosmic on the ECC with black CS. Next talker, Takahashi. ECC downstream

4 Momentum of mu from tau decay. Momentum measurement Strongest interest on the muon from tau decay. Most of them are below 5GeV. Or 10GeV.

5 Momentum measurement by angular method No need fine alignment Cell 1/2

6 dx Position resolution is sqrt(6)*  (x)‏ Momentum measurement by coordinate method Fine alignment is needed. Cell 3/2

7 Position resolution by current cosmic ray exposure. SUTS data by 24h cosmic exposure 1cm^2  0.9 micron for X  0.75 micron for Y  (momentum cut by angular method.) dx  (dx) = sqrt(3/2)*  (x)‏

8 1cm x 1cm x 12plates 226 tracks in scanning area (nseg>=5 theta<0.5)‏ dx  (dx) = sqrt(3/2)*  (x)‏

9 1.4cm x 1.4cm x 11plates 369 tracks in scanning area dx  (dx) = sqrt(3/2)*  (x)‏  From the point of alignment. Higher cosmic density doesn't give higher resolution. 1/3~1/5 of current exposure is enough to get same alignment accuracy(1micron).

10 Bigger scanning area give a number of track. It is competition between emulsion XY distortion and the scanning power.

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13 Alignment for long range (cell length >=3,5)‏ The accumulation of the alignment error is of the order of Cell 1/2 (in worst case). For example,  cell length = 3, sqrt(6)*1micron = 2.4micron.  Cell length = 5, sqrt(10)*1micron=3.2micron. On the other hand, the signal of the coordinate method is Cell 3/2, which is enough big. Cell 3/2

14 From the point of alignment.  Higher cosmic density doesn't give higher resolution.  1/3~1/5 of current exposure is enough to get same alignment accuracy(1micron).

15 Ntrack = 281 starting from first 2plate && nseg>=3

16 Angle resolution (including scattering.)‏ Rms = sqrt(rms(theta1)^2 + rms(theta2)^2)‏ rms(theta) = 1.2/sqrt(2) = 0.85mrad

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20 dx  (dx) = sqrt(3/2)*  (x)‏ Including scattering. theta^rms cut = 5mrad for each cell.


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