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Finding “the gene” for cystic fibrosis
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Why is this in quotes? A.CF is not caused by a gene, it’s caused by multiple genes. B.CF is not caused by genetic factors. C.CF is not caused by a gene, it’s caused by a mutation.
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How to find genetic determinants of naturally varying traits?
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Genetic markers Fig. 10.3 (microsatellite)
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Genetic markers Fig. 10.3 (microsatellite) Table 11.1
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Lots of benign variation between us.
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How do you find polymorphisms? Fig. 11.6
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How do you find polymorphisms? Fig. 11.6 Introduced in lecture 9/15.
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How do you find polymorphisms? Fig. 11.6
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How do you find polymorphisms? Fig. 11.6
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How do you find polymorphisms? Fig. 11.6
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How do you find polymorphisms? Fig. 11.6
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How do you find polymorphisms? Fig. 11.6
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Hybrid mapping: location of probe www3.mdanderson.org/depts/cellab/fish1.htm mousehuman/mouse hybrid
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Hybrid mapping: location of probe Back then, no technique to see 6kb at cytological resolution.
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Who cares about benign polymorphisms? Remember Sturtevant? Fig. 5.10
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Who cares about benign polymorphisms? We are going to do a two- point cross. One of our genetic loci is represented by phenotype; the other is a DNA marker.
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Mapping a disease locus Fig. 11.A (Autosomal dom) A1 A2
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Mapping a disease locus Fig. 11.A (Autosomal dom) phenotype (variation in locus 1) A1 A2
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Mapping a disease locus Fig. 11.A (Autosomal dom) phenotype (variation in locus 1) marker genotype (variation in locus 2) A1 A2
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Mapping a disease locus Fig. 11.A (Autosomal dom) phenotype (variation in locus 1) marker genotype (variation in locus 2) How close are they in genetic distance? A1 A2
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Mapping a disease locus Fig. 11.A A1D A2d (Autosomal dom) A1 A2
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Mapping a disease locus Fig. 11.A A1D A2d (Autosomal dom) A1 A2 (assume phase)
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Mapping a disease locus Fig. 11.A A1D A2d A1d d A2
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Mapping a disease locus Fig. 11.A A1D A2d A1d d A2d A1 A2
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Mapping a disease locus Fig. 11.A A1D A2d A1d d D A2
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Mapping a disease locus Fig. 11.A A1D A2d A1d d A2d A1 A2
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Mapping a disease locus Fig. 11.A A1D A2d A1d d ? A2
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Mapping a disease locus Fig. 11.A A1d d ? D A2d (sperm) A1 A2
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Mapping a disease locus Fig. 11.A A1d d A2D A1D A2d (sperm) A1 A2
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Mapping a disease locus Fig. 11.A A1d d D A2d A1 A2 In total, 7 of the kids are non-recombinants and 1 is a recombinant.
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Mapping a disease locus Fig. 11.A What is the apparent RF between the DNA marker and the disease mutation? A.1/10 B.1/8 C.1/20 A1 A2 In total, 7 of the kids are non-recombinants and 1 is a recombinant.
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Mapping a disease locus Fig. 11.A What is the apparent RF between the DNA marker and the disease mutation? 1/8 = 12.5 m.u. A1 A2 A.1/10 B.1/8 C.1/20 In total, 7 of the kids are non-recombinants and 1 is a recombinant.
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Why do I say “apparent RF?”
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What if… observed recombination fraction = 1/8 = 12.5 cM Disease- causing mutation Restriction fragment length polymorphism True distance 30 cM
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What if… observed recombination fraction = 1/8 = 12.5 cM Disease- causing mutation Restriction fragment length polymorphism True distance 30 cM You could say this will never happen. But…
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What if… observed recombination fraction = 1/8 = 12.5 cM Disease- causing mutation Restriction fragment length polymorphism True distance 30 cM this is our observation
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What if… observed recombination fraction = 1/8 = 12.5 cM Disease- causing mutation Restriction fragment length polymorphism True distance 30 cM The observed number of recombinants is just a point estimate, with some error associated. this is our observation
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12 cM, 18 cM…who cares? Further experiments need to find the causal variant, not just a marker. If distances are wrong, could be hunting for years.
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Mapping a disease locus Fig. 11.A We now know the mutation is near (linked to) the marker. 1/8 = 12.5 m.u. A1 A2
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Mapping a disease locus We now know the mutation is near (linked to) the marker. marker (known) 1/8 = 12.5 m.u. A1 A2
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Mapping a disease locus We now know the mutation is near (linked to) the marker. window containing causative mutation 1/8 = 12.5 m.u. marker (known) A1 A2
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Mapping a disease locus 1/8 = 12.5 m.u. How significant? A1 A2
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Mapping a disease locus 1/8 = 12.5 m.u. How significant? If RF = 0.5 (unlinked), would be like flipping a coin 8 times. How likely would you be to get 7 heads and 1 tail? A1 A2
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If RF = 0.5 (unlinked), would be like flipping a coin 8 times. How likely would you be to get 7 heads and 1 tail? How much MORE likely is a model of RF < 0.5?
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If RF = 0.5 (unlinked), would be like flipping a coin 8 times. How likely would you be to get 7 heads and 1 tail? How much MORE likely is a model of RF < 0.5? For large cross between known parents, would use 2 to evaluate significance. Here we can’t.
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LOD scores 1 recomb, 7 non-recomb. r = genetic distance between marker and disease locus A1 A2
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LOD scores 1 recomb, 7 non-recomb. Odds = P(pedigree | r) P(pedigree | r = 0.5) r = genetic distance between marker and disease locus A1 A2
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LOD scores 1 recomb, 7 non-recomb. Odds = P(pedigree | r) P(pedigree | r = 0.5) r = genetic distance between marker and disease locus “How likely are the data given our model?” A1 A2
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LOD scores k = 1 recomb, n = 7 non-recomb. Odds = P(pedigree | r) P(pedigree | r = 0.5) r = genetic distance between marker and disease locus Odds = (1-r) n r k 0.5 n 0.5 k A1 A2
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LOD scores Odds = P(pedigree | r) P(pedigree | r = 0.5) r = genetic distance between marker and disease locus Odds = (1-r) n r k 0.5 (total # meioses) A1 A2 k = 1 recomb, n = 7 non-recomb.
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LOD scores Odds = P(pedigree | r) P(pedigree | r = 0.5) r = genetic distance between marker and disease locus Odds = (1-r) n r k 0.5 (total # meioses) We have an idea of true r, but it is imprecise. k = 1 recomb, n = 7 non-recomb. A1 A2
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Remember? observed recombination fraction = 1/8 = 12.5 cM Disease- causing mutation Restriction fragment length polymorphism True distance 30 cM The observed number of recombinants is just a point estimate, with some error associated. this is our observation
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LOD scores Odds = P(pedigree | r) P(pedigree | r = 0.5) r = genetic distance between marker and disease locus Odds = (1-r) n r k 0.5 (total # meioses) k = 1 recomb, n = 7 non-recomb. A1 A2 This formalism allows any r value. Let’s guess r = 0.3.
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LOD scores Odds = P(pedigree | r) P(pedigree | r = 0.5) r = genetic distance between marker and disease locus Odds = (1-r) n r k 0.5 (total # meioses) Odds = 0.7 7 0.3 1 0.5 8 k = 1 recomb, n = 7 non-recomb. A1 A2 This formalism allows any r value. Let’s guess r = 0.3.
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LOD scores Odds = P(pedigree | r) P(pedigree | r = 0.5) r = genetic distance between marker and disease locus Odds = (1-r) n r k 0.5 (total # meioses) Odds = 0.7 7 0.3 1 0.5 8 = 6.325 k = 1 recomb, n = 7 non-recomb. A1 A2 This formalism allows any r value. Let’s guess r = 0.3.
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LOD scores Odds = P(pedigree | r) P(pedigree | r = 0.5) r = genetic distance between marker and disease locus Odds = (1-r) n r k 0.5 (total # meioses) Odds = 0.7 7 0.3 1 0.5 8 = 6.325 Data >6 times more likely under LINKED hypothesis than under UNLINKED hypothesis. k = 1 recomb, n = 7 non-recomb. A1 A2
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LOD scores rodds 0.112.244 0.210.737 0.36.325 0.42.867 0.5?? Odds = P(pedigree | r) P(pedigree | r = 0.5) Odds = (1-r) n r k 0.5 (total # meioses) k = 1 recomb, n = 7 non-recomb.
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LOD scores Odds = P(pedigree | r) P(pedigree | r = 0.5) Odds = (1-r) n r k 0.5 (total # meioses) Odds at r=0.5? A.2.5 B.0 C.1 D.10 rodds 0.112.244 0.210.737 0.36.325 0.42.867 0.5??
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LOD scores What’s the best (most likely) value of r? A.0.1 B.0.2 C.0.3 D.0.4 E.0.5 rodds 0.112.244 0.210.737 0.36.325 0.42.867 0.51
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What problems will look like 1,2 1,11,21,11,21,11,2 1,1 A1 A2
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What problems will look like 1,2 1,11,21,11,21,11,2 1,1
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What problems will look like 1,2 1,11,21,11,21,11,2 1,1 Count number of recombinants, calculate odds.
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Reading and chapter problems on web site.
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