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Chapter 5 Estimating Parameters From Observational Data Instructor: Prof. Wilson Tang CIVL 181 Modelling Systems with Uncertainties
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Estimating Parameters From Observation Data REAL WORLD “POPULATION” (True Characteristics Unknown) Sample {x 1, x 2, …, x n } Sampling (Experimental Observations) Real Line -∞ < x < ∞ With Distribution f X (x) Random Variable X Inference On f X (x) f X (x) Statistical Estimation Role of sampling in statistical inference
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Point Estimations of Parameters, e.g. , 2,, etc. a)Method of moments: equate statistical moments (e.g. mean, variance, skewness etc.) of the model to those of the sample. From Table 5.1 in pp 224 – 225 See e.g. 5.2 in p. 227
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Common Distributions and their Parameters
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Common Distributions and their Parameters (Cont’d)
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b) Method of maximum likelihood: Parameter = r.v. X with f x (x) Definition: L( ) = f X (x 1, ) f X (x 2, ) f X (x n, ), where x 1, x 2, x n are observed data Physical interpolation – the value of such that the likelihood function is maximized (i.e. likelihood of getting these data is maximized ) For practical purpose, the difference between the estimates obtained from these different methods would be small if sample size is sufficiently large.
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b)Method of maximum likelihood (Cont ’ d): = 1 = 2 e - x x f X (x) X1X1 X2X2 GivenX 1 = 2 more likely Similarly,X 2 = 1 more likely Likelihood of depends on f X (x i ) and the x i ’s
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X: , What would you expect the value of X to be? As n Var(X) Before collections of data, X 1 is a r.v. = X X is r.v.
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What is the distribution of X? n1n1 n2n2 n n 1 > n 2
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Confidence interval of We would like to establish P(? < < ?) = 0.95 0.95 k 0.025 = 1.96 -1.96 0.025
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Confidence interval of (Cont’d) Not a r.v. confidence interval /2 1 – k /2
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E5.5 Daily dissolved oxygen (DO) n = 30 observations s = 2.05 mg/l assume = x = 2.52 mg/l Determine 99% confidence interval of As confidence level interval <> n <>
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Confidence Interval of when is unknown Small f Large f N(0,1) 0 known
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/2 p t /2,f 0 (for known case)
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E5.9 Traffic survey on speed of vehicles. Suppose we would like to determine the mean vehicle velocity to within 2 kph with 99 % confidence. How many vehicles should be observed? Assume = 3.58 from previous study Scatter 2.58 What if not known, but sample std. dev. expected to s = 3.58 and desired to be with 2 ?
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E5.9 (Cont’d) Compare with n 21 for known
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Lower confidence limit Upper confidence limit 1 – kk Not /2 known unknown
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- Similar to estimations of
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What about an area? B C D
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In general, r1r1 r2r2 h
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Interval Estimation of 2 sample variance 2 statistics – confidence level n – no. of sample
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E 5.13 DO data: n = 30, s 2 = 4.2
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Estimation of proportions
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10 out of 50 specimens do not have pass CBR requirement. E 5.14
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Review on Chapter 5
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