Download presentation
Presentation is loading. Please wait.
1
Using the IBA on Titan
2
Nuclear Model Codes at Yale Computer name: Titan Connecting to SSH: Quick connect Host name: titan.physics.yale.edu User name: phy664 Port Number 22 Password: nuclear_codes cd phintm pico filename.in (ctrl x, yes, return) runphintm filename (w/o extension) pico filename.out (ctrl x, return)
3
Sph. Deformed Lets first do the three symmetries. Okey, dokey?
4
Relation of IBA Hamiltonian to Group Structure
5
+2.9 +2.0 +1.4 +0.4 +0.1 -0.1 -0.4 -2.0-3.0 3.3 3.1 2.9 2.7 2.5 2.2 R 4/2 N = 10 Now some calculations for real nuclei
6
Lets do some together Pick a nucleus, any collective nucleus 152-Gd (N=10) 186-W (N=11) Data 0+ 0 keV 0 keV 2+ 344 122 4+ 755 396 6+ 1227 809 0+ 615 883 2+ 1109 737 R 4/2 = 2.19 ~ 0.4 3.24 ~ 0.7 R 0/2 = -1.43 ~ -1.32 +1.2 ~ -0.7 For N = 10 and = - 0.02 MeV = 4 x 0.02 x 10 [ (1 – )/ ] = 0.8 x [0.6 /0.4] ~ 1.2 MeV = 0.8 x [0.3/0.7] ~ 0.33 MeV At the end, need to normalize energies to first J = 2 state. For now just look at energy ratios. These parameters are starting points.
7
Mapping the Entire Triangle with a minimum of data Mapping the Entire Triangle with a minimum of data 2 parameters 2-D surface H = ε n d - Q Q Parameters: , (within Q) varies from 0 to infinity /ε
8
Spanning the Triangle H = c [ ζ ( 1 – ζ ) nd 4NB Q χ ·Q χ - ] ζ χ U(5) 0+0+ 2+2+ 0+0+ 2+2+ 4+4+ 0 2.0 1 ζ = 0 O(6) 0+0+ 2+2+ 0+0+ 2+2+ 4+4+ 0 2.5 1 ζ = 1, χ = 0 SU(3) 2γ+2γ+ 0+0+ 2+2+ 4+4+ 3.33 1 0+0+ 0 ζ = 1, χ = -1.32
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.