1. Section 7.2 Solids of Revolution

2. 1 st Day Solids with Known Cross Sections

3. Method of Slicing 1 Find a formula for A ( x ) = the area of a cross section. (When you multiply A ( x ) by dx, you will have the third length necessary to find the volume) Sketch the solid and a typical cross section. 2 3 Find the limits of integration. 4 Integrate A ( x ) to find volume.

4. Examples

5. 1.Find the volume of the solid whose base is bounded by the circle x 2 + y 2 = 9 and each cross section perpendicular to the x-axis is a square.

6. x y side of each square = 2y Area = (2y) 2 = 4y 2

7. 2.Find the volume of the solid whose base is bounded by the graphs f(x) = x + 1 and g(x) = x 2 – 1 whose cross sections perpendicular to the x-axis are equilateral triangles. Area of an equilateral triangle is given by

8. Side of equilateral triangle = f(x) – g(x)

10. 3.The region bounded by the graph of y = 2x – x 2 and the x-axis is the base of a solid. For this solid each cross section perpendicular to the x-axis is a semicircle.

11. Diameter of semicircle = 2x – x 2

13. 2 nd Day Disk Method

14. Suppose I start with this curve. How did we first find the approximation for area under this curve? Drawing rectangles and finding the area of each rectangle and adding them together.

15. If I take the graph and rotate it about the x-axis, I will get a 3-dimensional solid that is cone shaped.

16. How could we find the volume of the cone? One way would be to cut it into a series of thin slices (flat cylinders) and add their volumes.

17. Where do these flat cylinders (disks) come from? They are created by rotating an infinitely many rectangles around the axis of revolution.

18. Volume of a Cylinder =  r 2 h What is the radius of each cylinder(disk) in the cone? What is the height of each cylinder(disk) in the cone? The radius of each cylinder(disk) is y coordinate of its rectangle. The height of each cylinder(disk) is Δx. Volume of each cylinder(disk) =  (y 2 )Δ x

19. How do we find the volume of the solid? Add the volume of all the cylinders(disks).

20. Examples

21. The region between the curve, and the y -axis is revolved about the y -axis. Find the volume. y x We use a horizontal disk. The thickness is dy. The radius is the x value of the function.

22. volume of disk

23. Find the volume of the solid formed by rotating the region bounded by the x-axis (0 ≤ x ≤  ) and the graph of about the x-axis.

27. Find the volume of the solid by revolving by f(x) = 2 – x 2 and g(x) = 1 about the line y = 1.

29. This application of the method of slicing is called the disk method. The shape of the slice is a disk, so we use the formula for the area of a circle to find the volume of the disk. Solid of Revolution Formula with a vertical axis: Solid of Revolution Formula with a horizontal axis: End of 2 nd Day

30. 3 rd Day Washer Method

31. The region bounded by and is revolved about the y-axis. Find the volume. The “disk” now has a hole in it, making it a “washer”. If we use a horizontal slice: The volume of the washer is: outer radius inner radius

32. The volume of the washer is: outer radius inner radius

34. This application of the method of slicing is called the washer method. The shape of the slice is a circle with a hole in it, so we subtract the area of the inner circle from the area of the outer circle. The washer method formula is:

35. If the same region is rotated about the line x = 2 : The outer radius is: R The inner radius is: r

38. Examples

39. Find the volume of the solid by revolving the region bounded by the graphs of about the x-axis.

43. Find the volume of the solid formed by the equations: rotated about the line x = 6.

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