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Born-Haber cycles, and lattice energy
Mr Michael (Hamzah) Allan ( ) KYUEM
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5. Chemical energetics (p23)
b) explain and use the term: iii) lattice energy (ΔH negative, i.e. gaseous ions to solid lattice)
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Lattice energy (enthalpy) is the
Definition: Lattice energy (enthalpy) is the enthalpy change when one mole of an ionic crystal (lattice) is formed from its constituent gaseous ions under standard conditions ...
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(Ionic) Bond forming Crystal (lattice) forms
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(Ionic) Bond forming DHLE = -’ve DHLE = -x kJmol-1
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(Ionic) Bond --breaking--
DH = +’ve DH = +x kJmol-1 i.e. DH = - LE
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Examples (1/4)…. Na+(g) + Cl-(g) NaCl(s) DHLE = -781 kJmol-1 sign
gaseous ions Remember to state the units Standard state for the product
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Examples (2/4)…. K+(g) + O2-(g) KO2(s) DHLE = -1540 kJmol-1
Potassium superoxide K+(g) + O2-(g) KO2(s) DHLE = kJmol-1 sign gaseous ions Remember to state the units Standard state for the product
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Examples (3/4) – D.I.Y. Write a thermochemcial equation for the lattice energy of barium chloride given that the 0.1 moles of the salt formed (in the appropriate manner) liberates kJ of energy Answer = Ba2+(g) + 2 Cl-(g) BaCl2(s) DHLE = kJmol-1
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Examples (4/4) 2K+(g) + O22-(g) K2O2(s) DHLE = -1980 kJmol-1
Potassium peroxide 2K+(g) + O22-(g) K2O2(s) DHLE = kJmol-1 sign gaseous ions Remember to state the units Standard state for the product
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Points of significance about Lattice energy
It assumes a purely IONIC MODEL Can be expressed as an equation (based on Coulombs law): 𝐿.𝐸.=𝑘 𝑄1 𝑄2 𝑑2 k is a constant ×109 N·m2/C2 Q1 and Q2 are the charges on the ions in coulombs (each charge = × C, (can include -ve for anions, + for cations) d = distance between charges in metres.
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5. (e) (iv) Born-Haber cycles (P23) (including ionization energy and electron affinity)
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Uses of Lattice energy. Born-Haber cycles, which shows the step-wise process of lattice formation from elements. Born-Haber cycles have numerous uses, e.g. predicting the stability of an ionic compound.
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Other definitions to learn (1/3)…
Enthalpy of formation (DHf): 1 mole of a compound is formed from its elements in their standard states under standard conditions. Enthalpy of atomization (DHat): 1 mole of gaseous atoms is formed from its element under standard conditions.
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Other definitions to learn (2/3)…
Ionization energy (DHIE): 1 mole of electrons is removed from 1 mole of gaseous atoms under standard conditions. NOTE: Removing e- from atoms is always an endothermic process. Energy must be supplied to overcome the attraction of the e- to the nucleus. The more e- that are removed, the more endothermic the process will be.
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Other definitions to learn (3/3)…
Electron affinity enthalpy (DHea): One mole of electrons is added to one mole of gaseous atoms under standard conditions. Note: The first ea’s are almost always negative. (noble gasses excepted). 2nd and later ea’s are ALWAYS positive (adding an electron to an already negative ion = repulsion to overcome)
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Standard conditions (1/2).
To keep all data comparable (therefore easy to use and easily transferable), measurements are usually taken under standard conditions. 1 atmosphere (101 kPa, 760mmHg, 1 barr) 298K (25oC – but must use K temperatures in equations) 1 Molar solution (see electrochemistry etc)
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Standard conditions (2/2).
The symbol DH is accompanied with a “ ” symbol to donate standard conditions, i.e. DH If no symbol is present, assume standard conditions are used, unless stated otherwise (and mention them in definitions, e.g. “Standard enthalpy of atomization”)
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NaCl(s) product Na(s) + ½ Cl2(g) Na+(g) + Cl (g) Na(g) + ½ Cl2(g)
Born-Haber cycle for NaCl (step by step) Na+(g) + Cl (g) ½ Cl2(g) Cl(g) DHat = kJ mol-1 Cl (g) Cl -(g) DHea = kJ mol-1 Na(g) + ½ Cl2(g) Na+(g) + Cl - (g) Na(g) Na+(g) DHIE = +496 kJ mol-1 Lattice energy Na(g) + ½ Cl2(g) Na+(g) + Cl -(g) NaCl(s) DHLE = kJ mol-1 Na(s) Na(g) DHat = +107 kJ mol-1 Na(s) + ½ Cl2(g) Datum line (zero energy line) <<< Elements Na(s) + ½ Cl2(g) NaCl(s) DHf = kJ mol-1 NaCl(s) product << Lattice
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Practice (revision guide)
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AgCl(s) product Ag(s) + ½ Cl2(g) Ag+(g) + Cl (g) Ag(g) + ½ Cl2(g)
Born-Haber cycle for AgCl (step by step) Ag+(g) + Cl (g) ½ Cl2(g) Cl(g) DHat = kJ mol-1 Cl (g) Cl -(g) DHea = kJ mol-1 Ag(g) + ½ Cl2(g) Ag+(g) + Cl - (g) Ag(g) Ag+(g) DHIE = +731 kJ mol-1 Lattice energy Ag(g) + ½ Cl2(g) Ag+(g) + Cl -(g) AgCl(s) DHLE = kJ mol-1 Ag(s) Ag(g) DHat = +285 kJ mol-1 Ag(s) + ½ Cl2(g) Datum line (zero energy line) <<< Elements Ag(s) + ½ Cl2(g) AgCl(s) DHf = kJ mol-1 AgCl(s) product << Lattice
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References: Formation of crystal lattice from ions: NaHalide LE’s figure: The LiF Born Haber cycle : Scaled Born-Haber diagram for NaCl and practice question: CAMBRIDGE INTERNATIONAL AS AND A LEVEL CHEMISTRY REVISION GUIDE - David Bevan. Pub: Hodder. ISBN
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