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1 Civil Systems Planning Benefit/Cost Analysis Scott Matthews Courses: 12-706 and 73-359 Lecture 9 - 9/29/2002
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12-706 and 73-3592 Common Monetary Units Often face problems where benefits and costs occur at different times Need to adjust values to common units to compare them Recall photo sensor example from last lecture - could look at values over several years...
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12-706 and 73-3593 Admin Issues Number/size of groups? Need to plan. Usually 4 ‘groups’ per class session, at end of course
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12-706 and 73-3594 General Terms Three methods: PV, FV, NPV FV = $X (1+i) n X : present value, i:interest rate and n is number of periods (eg years) of interest Rule of 72 PV = $X / (1+i) n NPV=NPV(B) - NPV(C) (over time) Real vs. Nominal values
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12-706 and 73-3595 Minimum Attractive Rate of Return MARR usually resolved by top management in view of numerous considerations. Among these are: Amount of money available for investment, and the source and cost of these funds (i.e., equity or borrowed funds). Number of projects available for investment and purpose (i.e., whether they sustain present operations and are essential, or expand present operations)
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12-706 and 73-3596 MARR part 2 The amount of perceived risk associated with investment opportunities available to the firm and the estimated cost of administering projects over short planning horizons versus long planning horizons. The type of organization involved (i.e., government, public utility, or competitive industry) In the end, we are usually given MARR
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12-706 and 73-3597 Notes on Notation PV = $FV / (1+i) n = $FV * [1 / (1+i) n ] But [1 / (1+i) n ] is only function of i,n $1, i=5%, n=5, [1/(1.05) 5 ]= 0.784 = (P|F,i,n) As shorthand: Future value of Present: (P|F,i,n) So PV of $500, 5%,5 yrs = $500*0.784 = $392 Present value of Future: (F|P,i,n) And similar notations for other types
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12-706 and 73-3598 Timing of Future Values Noted last time that we assume ‘end of period’ values What is relative difference? Consider comparative case: $1000/yr Benefit for 5 years @ 5% Assume case 1: received beginning Assume case 2: received end
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12-706 and 73-3599 Timing of Benefits Draw 2 cash flow diagrams NPV 1 = 1000 + 1000/1.05 + 1000/1.05 2 + 1000/1.05 3 + 1000/1.05 4 NPV 1 =1000 + 952 + 907 + 864 + 823 = $4,545 NPV 2 = 1000/1.05 + 1000/1.05 2 + 1000/1.05 3 + 1000/1.05 4 + 1000/1.05 5 NPV 2 = 952 + 907 + 864 + 823 + 784 = $4,329 NPV 1 - NPV 2 ~ $216 Notation: (P|U,i,n)
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12-706 and 73-35910 Relative NPV Analysis If comparing, can just find ‘relative’ NPV compared to a single option E.g. beginning/end timing problem Net difference was $216 Alternatively consider ‘net amounts’ NPV 1 =1000 + 952 + 907 + 864 + 823 = $4,545 NPV 2 = 952 + 907 + 864 + 823 + 784 = $4,329 ‘Cancel out’ intermediates, just find ends NPV 1 is $216 greater than NPV 2
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12-706 and 73-35911 Uniform Values - Theory Assume end of period values Stream = F/(1+i) +F/(1+i) 2 +..+ F/(1+i) n (P|U,i,n) = $1[(1+i) -1 +(1+i) -2 +..+ (1+i) -n ] [(1+i) -1 +(1+i) -2 +..+ (1+i) -n ] = “A” [1+(1+i) -1 +(1+i) -2 +..+ (1+i) 1-n ] = A(1+i) A(1+i) - A = [1 - (1+i) -n ] A = [1 - (1+i) -n ] / i Stream = F*(P|U,i,n) = F*[1 - (1+i) -n ] / i
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12-706 and 73-35912 Uniform Values - Application Recall $1000 / year for 5 years example Stream = F*(P|U,i,n) = F*[1 - (1+i) -n ] / I (P|U,5%,5) = 4.329 Stream = 1000*4.329 = $4,329 = NPV 2
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12-706 and 73-35913 Why Finance? Time shift revenues and expenses - construction expenses paid up front, nuclear power plant decommissioning at end. “Finance” is also used to refer to plans to obtain sufficient revenue for a project.
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12-706 and 73-35914 Borrowing Numerous arrangements possible: bonds and notes bank loans and line of credit municipal bonds (with tax exempt interest) Lenders require a real return - borrowing interest rate exceeds inflation rate.
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12-706 and 73-35915 Issues Security of loan - piece of equipment, construction, company, government. More security implies lower interest rate. Project, program or organization funding possible. (Note: role of “junk bonds” and rating agencies. Variable versus fixed interest rates: uncertainty in inflation rates encourages variable rates.
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12-706 and 73-35916 Issues (cont.) Flexibility of loan - can loan be repaid early (makes re-finance attractive when interest rates drop). Issue of contingencies. Up-front expenses: lawyer fees, taxes, marketing bonds, etc.- 10% common Term of loan Source of funds
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12-706 and 73-35917 Sinking Funds Act as reverse borrowing - save revenues to cover end-of-life costs to restore mined lands or decommission nuclear plants. Low risk investments are used, so return rate is lower.
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12-706 and 73-35918 Borrowing Sometimes we don’t have the money to undertake - need to get loan i=specified interest rate A t =cash flow at end of period t (+ for loan receipt, - for payments) R t =loan balance at end of period t I t =interest accrued during t for R t-1 Q t =amount added to unpaid balance At t=n, loan balance must be zero
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12-706 and 73-35919 Equations i=specified interest rate A t =cash flow at end of period t (+ for loan receipt, - for payments) I t =i * R t-1 Q t = A t + I t R t = R t-1 + Q t R t = R t-1 + A t + I t R t = R t-1 + A t + (i * R t-1 )
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12-706 and 73-35920 Uniform payments Assume a payment of U each year for n years on a principal of P R n =-U[1+(1+i)+…+(1+i) n-1 ]+P(1+i) n R n =-U[( (1+i) n -1)/i] + P(1+i) n Uniform payment functions in Excel Same basic idea as earlier slide
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12-706 and 73-35921 Example Borrow $200 at 10%, pay $115.24 at end of each of first 2 years R 0 =A 0 =$200 A 1 = - $115.24, I 1 =R 0 *i = (200)(.10)=20 Q 1 =A 1 + I 1 = -95.24 R 1 =R 0 +Q t = 104.76 I 2 =10.48; Q 2 =-104.76; R 2 =0
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12-706 and 73-35922 Repayment Options Single Loan, Single payment at end of loan Single Loan, Yearly Payments Multiple Loans, One repayment
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