1. 10/28/2003-10/30/2003 Network Layer, Routing, IP October 28-30, 2003

2. 10/28/2003-10/30/2003 Assignments Homework 4 Project 2 Read Chapter 4 sections 4.1-4.4 for this week

3. 10/28/2003-10/30/2003 Network Layer Move packet from sender to receiver Network layer protocols in every host, router Three Functions: –path determination: route taken by packets from source to dest. Routing algorithms –forwarding: move packets from router’s input to appropriate router output –call setup: some network architectures require router call setup along path before data flows network data link physical network data link physical network data link physical network data link physical network data link physical network data link physical network data link physical network data link physical application transport network data link physical application transport network data link physical

4. 10/28/2003-10/30/2003 Service Model End-to-end transport of data between sending and receiving systems –How is this different than the transport layer services? Datagram versus Virtual Circuit

5. 10/28/2003-10/30/2003 Virtual Circuit Call setup, teardown for each call Each packet carries VC identifier (not destination host ID) Every router on source-dest path maintains “state” for each passing connection –transport-layer connection only involved two end systems Link, router resources (bandwidth, buffers) may be allocated to VC –to get circuit-like performance

6. 10/28/2003-10/30/2003 Datagram Networks Routers: no state about end-to-end connections Packets forwarded using destination host address Best-effort service –No guarantees with respect to delay, in-order delivery application transport network data link physical application transport network data link physical 1. Send data 2. Receive data

7. 10/28/2003-10/30/2003 Datagram and the Internet Why is datagram service okay for the Internet?

8. 10/28/2003-10/30/2003 Routing Routing Protocol –Find route from default/first hop/source router to destination router Job of the algorithm – find a “good path” –Use graph abstraction to represent the network –Where do the numbers come from? A E D CB F 2 2 1 3 1 1 2 5 3 5

9. 10/28/2003-10/30/2003 Routing Algorithm Classification Global or decentralized information? Global: –all routers have complete topology, link cost info –“link state” algorithms Decentralized: –router knows physically- connected neighbors, link costs to neighbors –iterative process of computation, exchange of info with neighbors –“distance vector” algorithms Static or dynamic? Static: –routes change slowly over time Dynamic: –routes change more quickly periodic update in response to link cost changes Load sensitive/insensitive

10. 10/28/2003-10/30/2003 A Link-State Routing Algorithm Global – every router knows about all others How does a node find out about all other nodes? Once a node has the complete topology, it runs Dijkstra’s algorithm to generate the routing table

11. 10/28/2003-10/30/2003 Notation c(i,j): link cost from node i to j. cost infinite if not direct neighbors D(v): current value of cost of path from source to dest. v p(v): predecessor node along path from source to v, that is next v N: set of nodes whose least cost path definitively known

12. 10/28/2003-10/30/2003 Dijsktra’s Algorithm 1 Initialization: 2 N = {A} 3 for all nodes v 4 if v adjacent to A 5 then D(v) = c(A,v) 6 else D(v) = infinity 7 8 Loop 9 find w not in N such that D(w) is a minimum 10 add w to N 11 update D(v) for all v adjacent to w and not in N: 12 D(v) = min( D(v), D(w) + c(w,v) ) 13 /* new cost to v is either old cost to v or known 14 shortest path cost to w plus cost from w to v */ 15 until all nodes in N

13. 10/28/2003-10/30/2003 Dijkstra’s algorithm: example Step 0 1 2 3 4 5 start N A AD ADE ADEB ADEBC ADEBCF D(B),p(B) 2,A D(C),p(C) 5,A 4,D 3,E D(D),p(D) 1,A D(E),p(E) infinity 2,D D(F),p(F) infinity 4,E A E D CB F 2 2 1 3 1 1 2 5 3 5

14. 10/28/2003-10/30/2003 Discussion Algorithm complexity –n nodes –each iteration: need to check all nodes, w, not in N –n*(n+1)/2 comparisons: O(n**2) –more efficient implementations possible: O(nlogn) Oscillations possible: –e.g., link cost = amount of carried traffic –Solution? A D C B 1 1+e e 0 e 1 1 0 0 A D C B 2+e 0 0 0 1+e 1 A D C B 0 2+e 1+e 1 0 0 A D C B 2+e 0 e 0 1+e 1 initially … recompute routing … recompute

15. 10/28/2003-10/30/2003 Distance Vector Routing Algorithm Iterative, asynchronous, and distributed Distance table –all nodes have one –row for all destinations and a column for neighbors D (Y,Z) X distance from X to Y, via Z as next hop c(X,Z) + min {D (Y,w)} Z w = =

16. 10/28/2003-10/30/2003 Distance Table: Example A E D CB 7 8 1 2 1 2 D () A B C D A1764A1764 B 14 8 9 11 D5542D5542 E cost to destination via destination D (C,D) E c(E,D) + min {D (C,w)} D w = = 2+2 = 4 D (A,D) E c(E,D) + min {D (A,w)} D w = = 2+3 = 5 D (A,B) E c(E,B) + min {D (A,w)} B w = = 8+6 = 14 loop!

17. 10/28/2003-10/30/2003 Routing Table D () A B C D A1764A1764 B 14 8 9 11 D5542D5542 E cost to destination via destination ABCD ABCD A,1 D,5 D,4 Outgoing link to use, cost destination Distance table Routing table

18. 10/28/2003-10/30/2003 DV Overview wait for (change in local link cost of msg from neighbor) recompute distance table if least cost path to any dest has changed, notify neighbors Each node:

19. 10/28/2003-10/30/2003 Distance Vector Algorithm 1 Initialization: 2 for all adjacent nodes v: 3 D (*,v) = infinity /* the * operator means "for all rows" */ 4 D (v,v) = c(X,v) 5 for all destinations, y 6 send min D (y,w) to each neighbor /* w over all X's neighbors */ X X X w At all nodes, X:

20. 10/28/2003-10/30/2003 Distance Vector Algorithm 8 loop 9 wait (until I see a link cost change to neighbor V 10 or until I receive update from neighbor V) 11 12 if (c(X,V) changes by d) 13 /* change cost to all dest's via neighbor v by d */ 14 /* note: d could be positive or negative */ 15 for all destinations y: D (y,V) = D (y,V) + d 16 17 else if (update received from V wrt destination Y) 18 /* shortest path from V to some Y has changed */ 19 /* V has sent a new value for its min DV(Y,w) */ 20 /* call this received new value is "newval" */ 21 for the single destination y: D (Y,V) = c(X,V) + newval 22 23 if we have a new min D (Y,w)for any destination Y 24 send new value of min D (Y,w) to all neighbors 25 26 forever w X X X X X w w

21. 10/28/2003-10/30/2003 Example X Z 1 2 7 Y D (Y,Z) X c(X,Z) + min {D (Y,w)} w = = 7+1 = 8 Z D (Z,Y) X c(X,Y) + min {D (Z,w)} w = = 2+1 = 3 Y

22. 10/28/2003-10/30/2003 Example X Z 1 2 7 Y

23. 10/28/2003-10/30/2003 Link Cost Changes node detects local link cost change updates distance table (line 15) if cost change in least cost path, notify neighbors (lines 23,24) X Z 1 4 50 Y 1 algorithm terminates “good news travels fast”

24. 10/28/2003-10/30/2003 Link Cost Changes good news travels fast bad news travels slow - “count to infinity” problem! X Z 1 4 50 Y 60 algorithm continues on!

25. 10/28/2003-10/30/2003 Poisoned Reverse If Z routes through Y to get to X Z tells Y its (Z’s) distance to X is infinite (so Y won’t route to X via Z) will this completely solve count to infinity problem? X Z 1 4 50 Y 60 algorithm terminates

26. 10/28/2003-10/30/2003 Comparison of LS and DV Message Complexity Speed of Convergence Robustness

27. 10/28/2003-10/30/2003 Hierarchical Routing So far – all routers are equal, network is flat –Why is this view a problem?

28. 10/28/2003-10/30/2003 Hierarchical Routing Aggregate routers into autonomous systems ASs Intra-AS routing Each AS has a gateway –responsible for inter-AS routing

29. 10/28/2003-10/30/2003 Intra-AS and Inter-AS routing Gateways: perform inter-AS routing amongst themselves perform intra-AS routers with other routers in their AS inter-AS, intra-AS routing in gateway A.c network layer link layer physical layer a b b a a C A B d A.a A.c C.b B.a c b c

30. 10/28/2003-10/30/2003 Intra-AS and Inter-AS routing Host h2 a b b a a C A B d c A.a A.c C.b B.a c b Host h1 Intra-AS routing within AS A Inter-AS routing between A and B Intra-AS routing within AS B We’ll examine specific inter-AS and intra- AS Internet routing protocols shortly

31. 10/28/2003-10/30/2003 Assignments Continue work on Project 2Project 2 Finish reading chapter 4 for next week – we will not talk about 4.6 in class

32. 10/28/2003-10/30/2003 Network Layer forwarding table Routing protocols path selection RIP, OSPF, BGP IP protocol addressing conventions datagram format packet handling conventions ICMP protocol error reporting router “signaling” Transport layer: TCP, UDP Link layer physical layer Network layer

33. 10/28/2003-10/30/2003 IP Addressing IP address –32-bit identifier for host, router interface interface – connection between host/router and physical link –router’s typically have multiple interfaces –host may have multiple interfaces –IP addresses associated with each interface 223.1.1.1 223.1.1.2 223.1.1.3 223.1.1.4 223.1.2.9 223.1.2.2 223.1.2.1 223.1.3.2 223.1.3.1 223.1.3.27 223.1.1.1 = 11011111 00000001 00000001 00000001 223 111

34. 10/28/2003-10/30/2003 IP Addressing IP address: –network part (high order bits) –host part (low order bits) What’s a network ? (from IP address perspective) –device interfaces with same network part of IP address –can physically reach each other without intervening router 223.1.1.1 223.1.1.2 223.1.1.3 223.1.1.4 223.1.2.9 223.1.2.2 223.1.2.1 223.1.3.2 223.1.3.1 223.1.3.27 network consisting of 3 IP networks (for IP addresses starting with 223, first 24 bits are network address) LAN

35. 10/28/2003-10/30/2003 Classful Addressing 0 network host 10 network host 110 networkhost 1110 multicast address A B C D class 1.0.0.0 to 127.255.255.255 128.0.0.0 to 191.255.255.255 192.0.0.0 to 223.255.255.255 224.0.0.0 to 239.255.255.255 32 bits

36. 10/28/2003-10/30/2003 CIDR Classful addressing –inefficient use of address space, address space exhaustion –example? CIDR: Classless InterDomain Routing –network portion of address of arbitrary length –address format: a.b.c.d/x, where x is # bits in network portion of address 11001000 00010111 00010000 00000000 network part host part 200.23.16.0/23

37. 10/28/2003-10/30/2003 How do I get an IP address? Two options – what are they? Which is used when and why?

38. 10/28/2003-10/30/2003 What about the network part? ISP's block 11001000 00010111 00010000 00000000 200.23.16.0/20 Organization 0 11001000 00010111 00010000 00000000 200.23.16.0/23 Organization 1 11001000 00010111 00010010 00000000 200.23.18.0/23 Organization 2 11001000 00010111 00010100 00000000 200.23.20.0/23... ….. …. …. Organization 7 11001000 00010111 00011110 00000000 200.23.30.0/23

39. 10/28/2003-10/30/2003 Route Aggregation “Send me anything with addresses beginning 200.23.16.0/20” 200.23.16.0/23200.23.18.0/23200.23.30.0/23 Fly-By-Night-ISP Organization 0 Organization 7 Internet Organization 1 ISPs-R-Us “Send me anything with addresses beginning 199.31.0.0/16” 200.23.20.0/23 Organization 2...... Hierarchical addressing allows efficient advertisement of routing information:

40. 10/28/2003-10/30/2003 Constructing a Packet misc fields source IP addr dest IP addr data

41. 10/28/2003-10/30/2003 Determining the Next Hop Dest. Net. next router Nhops 223.1.1 1 223.1.2 223.1.1.4 2 223.1.3 223.1.1.4 2 misc fields 223.1.1.1223.1.1.3 data 223.1.1.1 223.1.1.2 223.1.1.3 223.1.1.4 223.1.2.9 223.1.2.2 223.1.2.1 223.1.3.2 223.1.3.1 223.1.3.27 A B E

42. 10/28/2003-10/30/2003 Determining the Next Hop Dest. Net. next router Nhops 223.1.1 1 223.1.2 223.1.1.4 2 223.1.3 223.1.1.4 2 misc fields 223.1.1.1223.1.2.3 data 223.1.1.1 223.1.1.2 223.1.1.3 223.1.1.4 223.1.2.9 223.1.2.2 223.1.2.1 223.1.3.2 223.1.3.1 223.1.3.27 A B E

43. 10/28/2003-10/30/2003 Router Forwarding Table misc fields 223.1.1.1223.1.2.3 data Dest. Net router Nhops interface 223.1.1 - 1 223.1.1.4 223.1.2 - 1 223.1.2.9 223.1.3 - 1 223.1.3.27 223.1.1.1 223.1.1.2 223.1.1.3 223.1.1.4 223.1.2.9 223.1.2.2 223.1.2.1 223.1.3.2 223.1.3.1 223.1.3.27 A B E

44. 10/28/2003-10/30/2003 Datagram Format ver length 32 bits data (variable length, typically a TCP or UDP segment) 16-bit identifier Internet checksum time to live 32 bit source IP address head. len type of service flgs fragment offset upper layer 32 bit destination IP address Options (if any)

45. 10/28/2003-10/30/2003 IP Fragmentation & Reassembly network links have MTU (max.transfer size) - largest possible link-level frame –different link types, different MTUs large IP datagram divided (“fragmented”) within net –one datagram becomes several datagrams –“reassembled” only at final destination –IP header bits used to identify, order related fragments fragmentation: in: one large datagram out: 3 smaller datagrams reassembly

46. 10/28/2003-10/30/2003 IP Fragmentation and Reassembly ID =x offset =0 fragflag =0 length =4000 ID =x offset =0 fragflag =1 length =1500 ID =x offset =1480 fragflag =1 length =1500 ID =x offset =2960 fragflag =0 length =1040 One large datagram becomes several smaller datagrams Example 4000 byte datagram MTU = 1500 bytes

47. 10/28/2003-10/30/2003 ICMP: Internet Control Message Protocol used by hosts, routers, gateways to communication network-level information –error reporting: unreachable host, network, port, protocol –echo request/reply (used by ping) network-layer “above” IP: –ICMP msgs carried in IP datagrams ICMP message: type, code plus first 8 bytes of IP datagram causing error Type Code description 0 0 echo reply (ping) 3 0 dest. network unreachable 3 1 dest host unreachable 3 2 dest protocol unreachable 3 3 dest port unreachable 3 6 dest network unknown 3 7 dest host unknown 4 0 source quench (congestion control - not used) 8 0 echo request (ping) 9 0 route advertisement 10 0 router discovery 11 0 TTL expired 12 0 bad IP header

48. 10/28/2003-10/30/2003 DHCP: Dynamic Host Configuration Protocol Goal: allow host to dynamically obtain its IP address from network server when it joins network –Can renew its lease on address in use –Allows reuse of addresses (only hold address while connected an “on” –Support for mobile users who want to join network (more shortly) DHCP overview: –host broadcasts “DHCP discover” msg –DHCP server responds with “DHCP offer” msg –host requests IP address: “DHCP request” msg –DHCP server sends address: “DHCP ack” msg

49. 10/28/2003-10/30/2003 DHCP client-server scenario 223.1.1.1 223.1.1.2 223.1.1.3 223.1.1.4 223.1.2.9 223.1.2.2 223.1.2.1 223.1.3.2 223.1.3.1 223.1.3.27 A B E DHCP server arriving DHCP client needs address in this network

50. 10/28/2003-10/30/2003 DHCP client-server scenario DHCP server: 223.1.2.5 arriving client time DHCP discover src : 0.0.0.0, 68 dest.: 255.255.255.255,67 yiaddr: 0.0.0.0 transaction ID: 654 DHCP offer src: 223.1.2.5, 67 dest: 255.255.255.255, 68 yiaddrr: 223.1.2.4 transaction ID: 654 Lifetime: 3600 secs DHCP request src: 0.0.0.0, 68 dest:: 255.255.255.255, 67 yiaddrr: 223.1.2.4 transaction ID: 655 Lifetime: 3600 secs DHCP ACK src: 223.1.2.5, 67 dest: 255.255.255.255, 68 yiaddrr: 223.1.2.4 transaction ID: 655 Lifetime: 3600 secs

51. 10/28/2003-10/30/2003 NAT: Network Address Translation 10.0.0.1 10.0.0.2 10.0.0.3 10.0.0.4 138.76.29.7 local network (e.g., home network) 10.0.0/24 rest of Internet Datagrams with source or destination in this network have 10.0.0/24 address for source, destination (as usual) All datagrams leaving local network have same single source NAT IP address: 138.76.29.7, different source port numbers

52. 10/28/2003-10/30/2003 NAT: Network Address Translation Implementation: NAT router must: –outgoing datagrams: replace (source IP address, port #) of every outgoing datagram to (NAT IP address, new port #)... remote clients/servers will respond using (NAT IP address, new port #) as destination addr. –remember (in NAT translation table) every (source IP address, port #) to (NAT IP address, new port #) translation pair –incoming datagrams: replace (NAT IP address, new port #) in dest fields of every incoming datagram with corresponding (source IP address, port #) stored in NAT table

53. 10/28/2003-10/30/2003 NAT 10.0.0.1 10.0.0.2 10.0.0.3 S: 10.0.0.1, 3345 D: 128.119.40.186, 80 1 10.0.0.4 138.76.29.7 1: host 10.0.0.1 sends datagram to 128.119.40, 80 NAT translation table WAN side addr LAN side addr 138.76.29.7, 5001 10.0.0.1, 3345 …… S: 128.119.40.186, 80 D: 10.0.0.1, 3345 4 S: 138.76.29.7, 5001 D: 128.119.40.186, 80 2 2: NAT router changes datagram source addr from 10.0.0.1, 3345 to 138.76.29.7, 5001, updates table S: 128.119.40.186, 80 D: 138.76.29.7, 5001 3 3: Reply arrives dest. address: 138.76.29.7, 5001 4: NAT router changes datagram dest addr from 138.76.29.7, 5001 to 10.0.0.1, 3345

54. 10/28/2003-10/30/2003 NAT 16-bit port-number field: –60,000 simultaneous connections with a single LAN-side address! NAT is controversial: –routers should only process up to layer 3 –violates end-to-end argument NAT possibility must be taken into account by app designers, e.g., P2P applications –address shortage should instead be solved by IPv6