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Diffraction Applications Physics 202 Professor Lee Carkner Lecture 28
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PAL #27 What is in the first side pattern in a double slit set-up with a = 0.08 mm and d = 0.25 mm and l = 650 nm? The first side pattern is between the m=1 and m=2 diffraction minima: sin = /a and sin = 2 /a sin 2 = (2)(650 X 10 -9 )/0.08 X 10 -3 =1.625 X 10 -2
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PAL #27 What interference maxima are between the two angles? d sin 1 =m 1 and d sin 2 = m 2 m 1 = (0.25 X 10 -3 )(8.125 X 10 -3 )/650 X 10 -9 = 3.13
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PAL #27 Middle interference fringe will be brightest (m = 5) sin = (5)( )/(d) = (5)(650 X 10 -9 )/ 0.25 X 10 -3 = 0.013 = ( d/ ) sin = [( )(0.25 X 10 -3 ) /(650 X 10 -9 )] (0.013) = 15.71 rad
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Spectroscopy In a hot material (e.g. a gas) composed of atoms will emit light due to electrons changing energy levels Gratings are used to separate light into its constituent wavelengths in order to identify this light as spectral lines The positions and strengths of these lines are unique for specific elements
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Spectroscope We want to pass the light through a grating This will produce a series of orders, each order containing lines (maxima) over a range of wavelengths We measure with a optical scope mounted on a vernier position scale Can also take an image of the pattern
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Spectroscope
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Grating Orders
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Spectral Type This is how the temperature of stars is determined Examples: Stars like the Sun (T~5500 K) can be identified by the Ca h and k doublet which is only produced at moderate temperatures
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Using Spectroscopy What properties do we want our spectroscope grating to have? How can we achieve this?
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Dispersion The size of the spectrum (from short to long ) produced by a grating is a function of the dispersion, D: The dispersion can also be written:
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Resolving Power The most important property of a grating is the resolving power, a measure of how well closely separated lines (in ) can be distinguished where av is the average wavelength of two lines
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Dispersion and Resolving Power
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Resolving Power of a Grating The resolving power depends on the number of rulings and the order: Note that large N means that d might be small which will increase D
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