13. Time rate of energy change of particle with v by a force F is: for a charge particle with added field E': Summing all the electron in a circuit, we find that the sources do work to maintain the current at the rate - sign is the Lenz's law. This is in addition to the Ohmic losses in the circuit, which should be excluded from the magnetic energy content

14. Thus, if the flux change is δF, the work done by sources is: The problem of the work done in establishing a general steady-state distribution of currents and fields is shown in Fig.5.20

15. The current distribution can be broken up into small current loops.A loop of current of cross-section area Δσ following a closed path C and spanned by a surface S with normal n as shown in Fig. 5.20. The work done against the induced EMF in terms of the change in magnetic induction through the loop is: Express B in terms of the vector potential A, we have

16. Since J∆σdl =Jd 3 x, the sum over all loops gives: Stokes’s theorem implies that Ampère’s law implies that:

17. The identity with P→A ; Q→H gives: Assuming that the field distribution is localized, the second term (surface integral) vanishes. Hence we have This is the magnetic equivalent of the electrostatic equation (5.147)‏

18. Assuming that the medium is para- or diamagnetic, such that a linear relation exists between H and B, then Hence the total magnetic energy will be This is the magnetic analog of electrostatic equation

19. If we assume that a linear relation exists btwn J and A, (5.144) implies that the total magnetic energy is: This is magnetic analog of If an object of permeability μ 1 is placed in a magnetic field whose current source are fixed, the change in energy can be treated in close analogy with the electrostatic discussions of section 4.7 by replacing D→H; E→B. H٠B-H 0 ٠B 0 =B٠H 0 - H٠B 0 + surface terms

20. Hence we have: This can also be written as Both μ 0 and μ 1 can be functions of position, but they are assumed independent of the field strength.

21. If the object is in otherwise free space, the change in energy can be written as: This is equivalent to the electrostatic equation (5.81)‏ (5.84)‏ pf/

22. The force acting on a body can be derived from a generalized displacement and calculate with respect to displacement.

23. From (5.149) the total energy of N distinct circuits can be expressed as : by converting (5.149) to with the help of (5.32).

24. Breaking up the integrals into sums of separate integrals over each circuit, we have: Hence the coefficients L,M of inductance are given by

25. Note that (5.32) reads: The integral over d 3 x' (5.14) can be written as integral of A. If the cross-section of the ith circuit is negligible, then mutual inductance becomes: A i induced by J j

26. Since curl of A = B, the mutual inductance is: Flux at i induced by J j

27. The self inductance is :

28. If the current density is uniform throughout the interior, from Ampère’s law: the magnetic induction, close to the circuit, is: The inductance per unit length inside and outside the wire out to ρ max is: 2 πρdρ

29. Because the expression B Φ fails at ρ> At distances large compared to A 1/2, the 1/ρ magnetic induction can be replaced by a dipole field pattern Thus the magnetic induction can be estimated to be: If we set Hence

30. Upon combining the different contributions, the inductance of the loop can be estimated to be:

31. Consider quasi-static magnetic field in conducting media, the relevant equations are: for uniform, frequency-independent permeable media. Laplace equation gives Φ=0

32. We can estimate the time τ for decay of an initial configuration with typical spatial variation defined by length L, then (5.161) can be used to estimate the distance L over which fields exist in a conductor, subjected externally to fields with harmonic variation at frequency hence

33. For copper sphere of radius 1 cm, τ~5-10 m sec molten iron core of the earth τ~10 5 years Evidence: earth magnetic field reverse ~10 6 years ago, 0.5*10 4 years, B goes to 0

34. Consider a semi-infinite conductor of uniform permeability and conductivity occupies the space z>0 :

35. Because the diffusion equation (5.160) is second order in spatial derivatives and first order in time, the steady- state solution for H x (z,t) can be written as the real part of By eq(5.160), h(z) satisfies : A trial solution gives

36. Dim[ k ]~ 1/length 1/δ. This length is the skin depth δ: Ex: Seawater Copper at room temperature

37. With the boundary condition at z→∞, for z>0, Since H varies in time, there is an electric field: Hence the solution of H x (z,t) is real part of Taking the real part, together with (5.165),,

38. To compare the magnitude of electric field and magnetic induction, the dimensionless ratio is by quasi-static assumption. The small tangential electric field is associated with a localized current density The integral in z is an effective surface current:

39. The time-averaged power input, for the resulting resistive heating (P=IV), per unit volume is With (5.167),(5.168), we have

40. A simple example: Two infinite uniform current sheets, parallel to each other and located a distance 2a apart, at z=±a. The current density J is in the y direction: z=a z=-a

41. At time t=0, the current is suddenly turned off. The vector potential and magnetic field decay according to (5.160), with variation only in z and t. Let, from Laplace transform, z=a z=-a, we have From (5.160),

42. With a change of variable from p to k: The initial condition can be used to determine h(k): ==> partial_z H_x = J_y

43. The initial condition can be used to determine h(k): Exploiting the symmetry in z, we can express cosine in terms of exponentials: Inversion of the Fourier integral yields h(k),

44. Hence the solution for the magnetic field at all t>0 is: The integral can be expressed in terms of the error function: κ=ka; ν=1/μσaa Hence

46. Error function can be expanded in Taylor series, the result is: