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Having Fun with Geometry Cavalieri’s Principle

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1 Having Fun with Geometry Cavalieri’s Principle

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3 MAFS.912.G-GMD.1.1: Give an informal argument for the formulas for the circumference of a circle, area of a circle, volume of a cylinder, pyramid, and cone. Use dissection arguments, Cavalieri’s principle, and informal limit arguments.

4 Cavalieri’s Principle
Historical Note Bonventura Francesco Cavalieri (1598 – 1647) Cavalieri’s work with indivisibles was a precursor to the development of calculus. His method of indivisibles is what is now known as Cavalieri’s Principle.

5 Activity: Developing a Formula for the Volume of a Cone
Items needed A partner (let’s work in pairs!) Ruler Tape Scissors Bag of dry beans Cone stencil 2 x sheets of card stock 12” string

6 Step One: The Cone Cut out the cone stencil and create a cone by taping the solid edge to the dashed edge. Use the string to determine the circumference of the base of the cone in inches. Measure the slant height of the face of the cone in inches. Use these two measurements to determine the height of the cone in inches. (5 decimal places)

7 My Measurements and Solution
Round to five decimal places for accuracy. Slant height of the face of the cone: =3.375. Circumference of base: =10.125 Radius of base: =2 𝜋 𝑟 ⇒ 𝑟 ≈

8 My Measurements and Solution
Height of cone: − = ℎ 2 ℎ ≈ 3.375

9 Step Two: The Cylinder Construct a cylinder that has the same height and circumference as the cone. *** Remember to include an extra half of an inch for overlap before cutting out your cylinder stencil. ***

10 Step Two: The Cylinder Tape the cylinder to a piece of cardstock so that it won’t slide when being filled.

11 Step Three: The Beans Fill the cone completely and accurately with beans. Pour them into the cylinder. Repeat until the cylinder is full. What do you observe?

12 Creating the Formula What is the formula for the volume of a cylinder?
What is the formula, based on your experiment, for the volume of a cone?

13 Activity: Comparing the Volume of a Cone and a Pyramid with the Same Base Area and Height

14 Activity: Comparing the Volume of a Cone and a Pyramid with the Same Base Area and Height
Step One Using the radius of the base of the cone in the previous activity, construct a square that has the same area as the base of the cone.

15 Solution Based on My Measurements
Area of the base of the cone: 𝜋 𝑟 2 = 𝜋 ≈ Side length of the square: ≈

16 Step Two Visualize the pyramid that can be constructed with this square as its base, having the same height as the cone. Optional activity: Have students create the pyramid and confirm that the cone and the pyramid can hold the same volume of beans.

17 Question We know the base of the cone and the base of the pyramid have the same area, but if we slice the cone and pyramid at a different height in a plane parallel to the base, will these slices have the same area?

18 Let’s Experiment!

19 Comparing slices cut by a parallel plane

20 Comparing Slices Compare a slice of the cone to a slice of the pyramid at the following heights in planes parallel to the base. 1 5 ℎ, 2 5 ℎ, 1 2 ℎ, 3 5 ℎ, 4 5 ℎ * 1/5 h is 1/5th of the height from the top for this experiment.

21 Teamwork Table 1 = 1/5 h (from the top) Table 2 = 2/5 h
To save time, each table will compute the area of a slice of the cone and a slice of the pyramid at one height. Table 1 = 1/5 h (from the top) Table 2 = 2/5 h Table 3 = 1 /2 h Table 4 = 3/5 h Table 5 = 4/5 h (close to bottom)

22 Place your results on the board 

23 Solutions Based on My Measurements
Slice of the Cone 1/5 h from the top marked Slice of the Pyramid 1/5 h from the top marked

24 Cone 1/5 h from top To find the length of the
base of the smaller triangle, multiply the radius of the cone by 1/5. =

25 Cone 1/5 h from top Radius of slice = 0.32229
Area of slice = π ≈

26 Pyramid 1/5 h from the top To find the length of the
base of the smaller triangle, multiply the side length of the base of the pyramid by 1/5. =

27 Pyramid 1/5 h from the top Side length of slice =0.57124
Area of slice = ≈

28 Position Radius Area of Slice of Cone Side Area of Slice of Pyramid 1/5 2/5 1/2 3/5 4/5 base

29 Cavalieri’s Principle
In the three-dimensional case: If two regions are trapped between two parallel planes (imagine one at the top of the cone and pyramid, and one at the bottom), and every plane parallel to these two planes intersects both regions in cross-sections of equal area, then the two regions have equal volume. Reference: See Wikipedia – You will find some cool mathematics there.

30 Cavalieri’s Principle
Activity: Take your pennies and stack them neatly on your desk. Think about the volume of this stack of pennies. Change the stack so that it is disturbed. (i.e. Push it in the middle, but don’t knock it down.) Does this collection of pennies still have the same volume? Yes! This is Cavalieri’s Principle in action.

31 Cavalieri’s Principle

32 Cavalieri’s Principle
How does Cavalieri’s Principle apply to our cone and pyramid? What can we say about the formula for the volume of a pyramid given that the formula for the volume of a cone of equal height and base area is 1 3 𝐵ℎ ?

33 Calculus Connection: Cone Formula The Formal Proof
Consider a cone with a base of radius a and height h. The cone will be created by rotating the line 𝒂 𝒉 𝒙 about the 𝑥-axis.

34 Cone Formula To find the exact volume of the cone, start with the volume of one slice of the cone perpendicular to the x-axis of width Δ𝑥. For small Δ𝑥 this volume will be approximately 𝜋 𝑎 ℎ 𝑥 2 Δ𝑥, since the radius of an arbitrary slice is 𝑎 ℎ 𝑥. Next, integrate this formula from 0 to h (using the Fundamental Theorem of Calculus to move from a sum of volumes of slices to the exact volume), to capture the volume of the entire cone.

35 Cone Formula lim 𝑛→∞ 𝜋 𝑖=1 𝑛 𝑎 ℎ 𝑥 𝑖 2 Δ 𝑥 𝑖 =𝜋 0 ℎ 𝑎 2 ℎ 2 𝑥 2 𝑑𝑥
=𝜋 0 ℎ 𝑎 2 ℎ 2 𝑥 2 𝑑𝑥 = π a 2 ℎ x h = 𝜋 3 𝑎 2 ℎ

36 Pyramid Formula The formal proof of the formula for the volume of a pyramid is given in the notes for this lesson. The short story … Start with a step-pyramid and find its volume by computing the volume of each step.

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38 Pyramid Formula Then you refine the pyramid, giving it more steps. Each time the base area and height are the same.

39 Pyramid Formula In limit, as the number of steps goes to infinity, we have a pyramid with a volume formula equal to 𝐵ℎ.

40 Formal Proof Consider this structure, which is a pyramid made up of three steps. The top step has side length 𝑎 1 and the height is 𝑏 1 . The volume of this step is 𝑎 1 2 𝑏 1 .

41 Formal Proof The next step has four blocks the same size as the top step and the bottom step has nine. The formula for the volume of the entire shape is 𝒂 𝟏 𝟐 𝒃 𝟏 ( 𝟏 𝟐 + 𝟐 𝟐 + 𝟑 𝟐 ).

42 Now consider a refinement of the previous pyramid
Now consider a refinement of the previous pyramid. This step-pyramid has six steps, with the same base area as the previous pyramid, and the same height. The volume of the top step is 𝑎 2 2 𝑏 2 . The total volume of the figure is 𝒂 𝟐 𝟐 𝒃 𝟐 ( 𝟏 𝟐 + 𝟐 𝟐 +…+ 𝟔 𝟐 ).

43 If we continue this refinement, a pyramid with 𝑛 steps and a top block (the building block) with volume 𝑎 𝑛 2 𝑏 𝑛 , will have a total volume of 𝒂 𝒏 𝟐 𝒃 𝒏 ( 𝟏 𝟐 + 𝟐 𝟐 +…+ 𝒏 𝟐 ). Important Note: As 𝑛 increases, both the length of the standard building block, 𝑎 𝑛 , and its height, 𝑏 𝑛 , decrease. However, the base area and the height are fixed throughout the refinement process.

44 Three Important Equalities
1. The area of the base of the pyramid is 𝒂 𝒏 𝟐 𝒏 𝟐 =𝑩 regardless of the number of steps 𝑛. (i.e. The building blocks have a base area of 𝑎 𝑛 2 and there are 𝑛 2 building blocks on the bottom level.)

45 Three Important Equalities
The height of the pyramid is 𝒃 𝒏 𝒏=𝒉 regardless of the number of steps 𝑛.

46 Three Important Equalities
3. It is known that 𝟏 𝟐 + 𝟐 𝟐 +…+ 𝒏 𝟐 =𝒏 𝒏+𝟏 𝟐𝒏+𝟏 𝟔 . (Recall the story of Gauss adding the numbers from 1 to 100 when he was in elementary school by developing a formula.)

47 Our total volume formula may be transformed as follows:
𝑎 𝑛 2 𝑏 𝑛 …+ 𝑛 2 = 𝑎 𝑛 2 𝑏 𝑛 𝑛 𝑛+1 2𝑛 = 𝑎 𝑛 2 𝑏 𝑛 𝑛 𝑛 𝑛 6 = 𝑎 𝑛 2 𝑏 𝑛 𝑛 𝑛 𝑛 2 = 𝑎 𝑛 2 𝑛 2 𝑏 𝑛 𝑛 𝑛 𝑛 2 = 𝐵ℎ 𝑛 𝑛 2

48 Now we take the limit as 𝑛 goes to infinity, which mathematically represents the process of continuing to refine our step pyramid until it morphs into a smooth pyramid with a square base and triangular sides. 𝒍𝒊𝒎 𝒏→ ∞ 𝑩𝒉 ( 𝟏 𝟑 + 𝟏 𝟐𝒏 + 𝟏 𝟔 𝒏 𝟐 )= 𝟏 𝟑 𝑩𝒉

49 Rather Use Applets Than Beans?
Scrolling down this page you will see an animated demonstration of the cube with three pyramids being placed consecutively inside it. This is followed by a discussion with pictures of the cone and pyramid volumes being compared and Cavalieri’s Principle being used.

50 Rather Use Applets Than Beans?
This site shows the three pyramids that will fit into a cube and how these pyramids can be transformed into a right square pyramid with the same volume using Cavalieri’s Principle. This is followed by a comparison of a cone to the pyramid and the resulting formula.

51 Supplemental Material
The Napkin Ring Problem

52 Supplemental Material
The relationship between the formula for a cylinder, cone and sphere: Given a cylinder and cone with the same radius and height, r and h respectively, such that r is equal to h, and a sphere of radius r = h, the volume of the cylinder minus the volume of the cone is equal to the volume of ½ of the sphere (i.e. the hemisphere).

53 Questions?


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