1. ANSWERS set 7 WAIT LINE

3. L=24 30-24 (1)(a)L=4 people in drug store

4. (1)(b)Lq Lq = 24*24 30(30-24) Lq= 3.2 people waiting for service

5. (1)(c) W= 1 30-24 W=.167 hr Interpret: W = 10 minutes from time you enter drug store until time you leave

6. (1)(d) Wq Wq = 24 30(30-24) Wq=.13 hour Interpret: 8 minutes before service

7. (1)(e) U=24/30=.80 80% efficiency P(server busy)

8. (1)(f) Po=1-.8=.2 P(no waiting)

9. (2) Cost of Waiting Av 3 customers arrive per hour(given) 10 hours per day(given) You compute: 30 customers/day Cost of waiting $5 per hour(given)

10. WAIT COST (A)(B) #SERVED/HR60/5=1260/10=6 WAIT TIME 3 =.028 12(12-3) 3 =.167 6(6-3) DAILY WAIT TIME 30(.028)=.8330(.167)=5 WAIT COST.83(5)=$4.175(5)=$25

11. Labor Cost (a)(b) Hourly wage$16$8 Labor Cost10(16)=$16010(8)=$ 80

12. Total Cost (a)(b) Wait4.1725 Labor16080 Total$164.17$105=MIN

13. (3) SIMULATION ARRIVALPROBCUMULARR RN 0.13 01 to 13 1.17.3014 to 30 2.15.4531 to 45 3.25.7046 to 70 4.20.9071 to 90 5.10191 to 00

14. (3) MAXIMUM UNLOADED MAX UNLPROBCUMULRN UNL 1.03 01 TO 03 2.12.1504 TO 15 3.40.5516 TO 55 4.28.8356 TO 83 5.12.9584 TO 95 6.05196 TO 00

15. FIRST 5 DAYS: RN ARR RNSIM ARRUNL RNSIM UNL 372694 774845 130122 100945 020513

16. delay Case 1: Demand > Supply Delay = Demand – Supply Case 2: Demand < Supply Delay =0 Next slide: Demand = 2B UNL Supply = UNL

17. FIRST 5 DAYS DELAYARRIV2B UNLMAX UUNL 02242 04454 00020 00050 00030

18. DAYS 6-10 DELAYARRIV2B UNLMAX UUNL 01131 02232 01111 02222 04433

19. DAYS 11-15 DELAYARRIV2B UNLMAX UUNL 4-3=12333 3-3=05533 5-3=24644 6-4=22433 4-3=12333

20. Av number delayed per day Total delayed= 1+2+2+1= 6 Number of days = 15 Av = 6/15= 0.4