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The Standard Normal Distribution Area =.05 Area =.5 Area =.45 1.645 z P(Z≤ 1.645)=0.95 (Area Under Curve) Shaded area =0.95.

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Presentation on theme: "The Standard Normal Distribution Area =.05 Area =.5 Area =.45 1.645 z P(Z≤ 1.645)=0.95 (Area Under Curve) Shaded area =0.95."— Presentation transcript:

1 The Standard Normal Distribution Area =.05 Area =.5 Area =.45 1.645 z P(Z≤ 1.645)=0.95 (Area Under Curve) Shaded area =0.95

2 The Standard Normal Distribution Area =.07 Area =.5 Area =.43 1.5 z P(Z≤ 1.5)= = NORMSDIST(1.5) = 0.93 Shaded area =0.93

3 The Standard Normal Distribution Area =.07 Area =.43 Area =.5 -1.5 z P(Z ≥- 1.5)= 1- P(Z≤-1.5) = 1-NORMSDIST(-1.5) = 0.93 Shaded area =0.93

4 The Standard Normal Distribution Area =.16 Area =.34 z Shaded area =0.68 1.0 P(-1.0≤Z≤1.0) = P(Z≤1.0) - P(Z≤-1.0) = NORMSDIST(1)-NORMSDIST(-1) = 0.68 Area =.16

5 The Standard Normal Distribution Area =.5 Area =.35 z Shaded area =0.85 1.04 P(Z ≤ x) = 0.85 x = ?? x = NORMSINV(0.85) = 1.04 Area =.15

6 Example: Find: Mean = 0 Standard deviation = 1 P(Z≤1.5) = NORMSDIST(1.5) = 0.93 P(Z≥-1.5) = 1- P(Z≤-1.5) = 1-NORMSDIST(-1.5) = 0.93 P(-1.0≤Z≤1.0) = P(Z≤1.0) - P(Z≤-1.0) = NORMSDIST(1)-NORMSDIST(-1) = 0.68 P(Z ≤ x) = 0.85 x = ?? x = NORMSINV(0.85) = 1.04

7 Example: Find: If Mean = 100 Standard deviation = 10 P(Z≤125) = NORMDIST(125,100,10,TRUE) = 0.994 P(Z ≤ z) = 0.3 z = NORMINV(0.3,100,10) z = 94.8


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