1. Residence time: T ave = C/R

6. 1 resident of the United States. 2.3 residents of Europe. 7.6 residents of Mexico. 7.4 residents of South America. 26.3 residents of Africa. 12.35 residents of the Far East. 1000 kilowatt-hours of electricity is equivalent to the average amount of electricity consumed per month by:

7. 574 fast-food meals. 34 pieces of firewood. 28.5 gallons of gasoline. 274 pounds of coal. 34 therms of natural gas. lead-acid battery weighing 61,110 pounds. 1000 kilowatt-hours of electricity is equivalent to the energy stored in each of the following:

8. 1000 kilowatt-hours of electricity production emits the following pollutants: PoundsPing pong balls (eq. vol. @STP) CO 2 1,72514,960,000 SO 2 4.1235,900 NO X 3.4830,530 And require 422 gallons of cooling water

10. Oil consumption per capita

11. Major oil trade movements

12. Coal production - Coal consumption

14. Natural gas consumption per capita

15. Major natural gas trade movements

23. * * C 3 refers to 3-phosphoglycerate, C 4 to a 4-carbon analogue (3.2 x 10 10 GJ/year)

24. Note: Approximate surface area of the earth is 4πr 2, or 4π(6.378  10 6 m) 2. This comes to ~5.112  10 14 m 2, and a hemisphere is ~2.556  10 14 m 2. Approximate average insolation is 343 W/m 2. So the total power falling on one hemisphere is: 343 W/m 2  2.556  10 14 m 2 = 8.78  10 16 W U.S. energy consumption is ~100 quad/yr, or 1.05  10 20 J/yr. World energy consumption is ~4.71  10 20 J/yr. SO: and

25. In other words, the average insolation in: is enough to satisfy the energy needs of: For: 20 minThe United States1 year 1 hourThe United States3 years 1.5 hoursThe world1 year 3 hoursThe world2 years