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Weak acids and Bases in water دکتر امید رجبی دانشیار گروه شیمی دارویی دانشکده داروسازی مشهد دکتر امید رجبی دانشیار گروه شیمی دارویی دانشکده داروسازی مشهد شیمی عمومی
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Weak acids in water Arrhenius: An acid furnishes a hydronium ion (H + or H 3 O + ) in solution. Bronsted-Lowry: An acid is a proton donor HC 2 H 3 O 2 + H 2 O C 2 H 3 O 2 - + H 3 O + acid base conj base conj. acid H 4 P 2 O 7 + H 2 O H 3 P 2 O 7 - + H 3 O + The H + (H 3 O + ) tells us this a K a Problem or: HA H + + A -
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Problem: Butanoic acid, HC 4 H 7 O 2 has a K a = 1.5 x 10 - 5. Calculate the [H + ] and pH of a 0.09 M butanoic acid solution. 1st write equilibrium: HC 4 H 7 O 2 H + + C 4 H 7 O 2 - I. C. E. 0.09 0 0 -x +x +x 0.09 - x x x try dropping x = 0.00116 = [H + ] pH = -log 0.00116 = 2.93 pOH = 11.065 and the [OH - ] = 8.61 x 10 - 12
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Weak Bases in Water: Arrhenius: A base furnishes a hydroxide ion (OH - ) in solution. NH 3 C 6 H 5 NH 2 (CH 3 ) 2 NH + H 2 O NH 4 + + OH - + H 2 O C 6 H 5 NH 3 + + OH - + H 2 O (CH 3 ) 2 NH 2 + + OH - The OH - ion tells us that these are K b problems. Also: K a K b =K w and K w @ 25 o C = 1 x10 -14 Bronsted-Lowry: A base is a proton acceptor base acid conj acid conj. base
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Given: K b for trimethylamine (CH 3 ) 3 N is 6.4 x 10 -5 Problem: Calculate the pH of a 0.05 M (CH 3 ) 3 N solution. Hydrolysis Eq. Expression: (CH 3 ) 3 N + H 2 O (CH 3 ) 3 NH + + OH - I. C. E. 0.05 0 0 -x +x +x 0.05 - x x x try dropping to simplify the math x = 1.79 x 10 -3 What does x represent? [OH - ] pOH = -log[1.79 x 10 -3 ] = 2.75pH = 14 -2.75 = 11.25
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Given: K b for trimethylamine (CH 3 ) 3 N is 6.4 x 10 -5 Problem: Calculate the pH of a 0.05 M (CH 3 ) 3 N solution. Hydrolysis Eq. Expression: (CH 3 ) 3 N + H 2 O (CH 3 ) 3 NH + + OH - I. C. E. 0.05 0 0 -x +x +x 0.05 - x x x try dropping to simplify the math x = 1.79 x 10 -3 What does x represent? [OH - ]
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