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PH 201 Dr. Cecilia Vogel Lecture 3
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REVIEW Motion in 1-D instantaneous velocity and speed acceleration OUTLINE Graphs Constant acceleration x vs t, v vs t, v vs x Vectors notation magnitude and direction
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Sign of Acceleration Mathematically If (signed) velocity increases, a is + If (signed) velocity decreases, a is - Memorize If velocity and acceleration are in same direction, object will speed up If velocity and acceleration are in opposite directions, object will slow down Physical intuition positive acceleration produced by push or pull in + direction negative acceleration produced by push or pull in - direction
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Position, Velocity, Acceleration Velocity is slope of tangent line on an x vs t graph limit of x/ t as t goes to zero the derivative of x with respect to time dx/dt Similarly acceleration is slope of tangent line on a v vs t graph limit of v/ t as t goes to zero the derivative of v with respect to time dv/dt If you have position as a function of time, x(t) can take derivative to find v(t) take derivative again to find a(t)
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Derivatives of Polynomials The derivative with respect to time of a power of t, if C is a constant: Special case, if the power is zero: The derivative of a sum is sum of derivatives: ex
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Example ex The acceleration at t=0 is -6 m/s2, and at t=3 is 90 m/s2. The average acceleration between t=0 and t=3 is 39 m/s2
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Special Case: Constant Velocity Acceleration is zero Graph of x vs. t is linear slope is constant Average velocity is equal to the constant velocity value, v if initial time is zero, and we drop subscript on final variables. becomes
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Special Case: Constant Acceleration If object’s acceleration has a constant value, a, then its velocity changes at a constant rate: And its position changes quadratically with time:
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Position with Constant Acceleration Slope of the position graph (velocity) is constantly changing quadratic function of time.
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Example A little red wagon is rolling in the positive direction with an initial speed of 5.0 m/s. A child grabs the handle and pulls, giving it a constant acceleration of 1.1 m/s 2 opposite its initial motion. Let the time the child begins to pull be t=0, and take the position of the wagon at that time to be x=0. a)How fast will the wagon be going after 1.0 s of pulling? b)Where will the wagon be then? c)At what time will the wagon come to a stop (for an instant)?
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What if…? What if I asked “where will the wagon be when it is going -1.0 m/s?” You could: find the time that v= -1.0 m/s find the position at that time.
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What if…? Let’s find a generalization of that: Where will object be when it’s velocity is v, given a known initial position, velocity, and constant acceleration ? simplify:
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Derivatives and Constant Acceleration Yeah – consistency!
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