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Math 025 Section 7.1 Coordinate Systems
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y-axis Quadrant II Quadrant I x-axis Origin Quadrant III Quadrant IV
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Each point in the plane can be identified by an ordered pair
(5, 7) The ordered pair tells the location of the point with reference to the origin Example: (5, 7) The numbers in the ordered pair are called the coordinates of the point 5 is the x-coordinate or abscissa 7 is the y-coordinate or ordinate The graph of a point is a dot placed at the location of the point
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Graph the following ordered pairs: A(-2, -3) B(3, -2) C(0,2) D(-3,0)
y C D x B A
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Give the coordinates of A and B Give the abscissa of C
y Give the abscissa of C B Give the ordinate of D C A D x Answers: Coordinates of A are (-4,2) Coordinates of B are (4, 4) Abscissa of C is -1 Ordinate of D is 1
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Objective: To check solutions of an equation in two variables.
Question: Is (-3, 7) a solution of y = -2x + 1 ? y = -2x + 1 Replace x with -3 7 = -2(-3) + 1 Replace y with 7 7 = 7 = 7 Both sides of the equation simplify to the same thing. Yes, (-3, 7) is a solution
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Objective: To check solutions of an equation in two variables.
Question: Is (3, -2) a solution of 3x – 4y = 15 ? 3x – 4y = 15 3(3) – 4(-2) = 15 Replace x with 3 Replace y with -2 9 + 8 = 15 17 = 15 Both sides of the equation are not the same. No, (3, -2) is not a solution
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Problem: Graph the ordered-pair solutions of 2x – 3y = 6
Problem: Graph the ordered-pair solutions of 2x – 3y = when x = -3, 0, 3 and 6 Solve 2x – 3y = 6 for y - 3y = -2x + 6 y = 2x – 2 3 x y 5 -3 2(-3) – 2 -4 3 2(0) – 2 -2 3 -5 3 2(3) – 2 3 6 2(6) – 2 2 3
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Problem: Graph the ordered-pair solutions of y = 2x – 1
Problem: Graph the ordered-pair solutions of y = 2x – when x = -2, 0, 1 and 3 y = 2x - 1 x y 3 -2 -5 -1 1 1 3 3 5
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Objective: To determine if a set of ordered pairs is a function
Definition of a relation A relation is any set of ordered pairs. Example: {(2, 3), (5, -4), (-7, 8), (-12, 8)} Definition of a function A function is a relation in which no two ordered pairs have the same first coordinate. Example: {(2, 3), (5, -4), (-7, 8), (-12, 8)} is a function
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Objective: To determine if a set of ordered pairs is a function
State whether each of the following relations is a function No {(5, 3), (5, -4), (-7, 12), (-5, 12)} Yes {(3, 3), (6, -5), (-7, 12), (-5, 12), (8, 3)} {(3, 3), (6, 3), (-7, 3), (-5, 3), (8, 3)} Yes {(2, 3), (2, -5), (2, 12), (2, 15), (2, 9)} No
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Does the equation express y as a function of x ?
y = 0.5x where x Î {-4, 0, 2} x y The relation for this domain is -1 {(-4,-1), (0, 1), (2, 2)} 1 2 Yes, the equation is a function
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Does the equation express y as a function of x ?
|y| = x where x Î {-2, 0, 2} x y When x = 2, |y| = 0 so y = 0 -2 When x = 0, |y| = 2 so y = 2 or y = -2 2 When x = 2, |y| = 4 so y = 4 or y = - 4 -2 2 4 The relation for this domain is 2 -4 {(-2, 0), (0, 2), (0, -2), (2, 4), (2, -4)} No, the equation is not a function
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Objective: To evaluate a function that is written in function notation.
When an equation such as y = x defines y as a function of x, the following function notation is often used to emphasize that the relation is a function f(x) = x2 + 3 f(x) is read “the value of the function f at x” or “f of x” The expression f(4) means “the value of the function when x = 4” so f(4) = (4)2 + 3 = = 19 This process is called evaluating the function
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Objective: To evaluate a function that is written in function notation.
Problem: Given f(x) = 5x find f(2) Solution: f(x) = 5x + 1 f(2) = 5(2) + 1 = 11 Problem: Given Q(r) = 4r2 – r – find Q(3) Solution: Q(r) = 4r2 – r – 3 Q(3) = 4(3)2 – (3) – 3 = 36 – 3 – 3 = 30
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