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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 1 Active Filters *Based on use of amplifiers to achieve filter function *Frequently use op amps so filter may have some gain as well. *Alternative to LRC-based filters *Benefits lProvide improved characteristics lSmaller size and weight lMonolithic integration in IC lImplement without inductors lLower cost lMore reliable lLess power dissipation *Price lAdded complexity lMore design effort Transfer Function V o (s) V i (s)
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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 2 Filter Types *Four major filter types : lLow pass (blocks high frequencies) lHigh pass (blocks low frequencies) lBandpass (blocks high and low frequencies except in narrow band) lBandstop (blocks frequencies in a narrow band) Low PassHigh Pass BandpassBandstop
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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 3 Filter Specifications *Specifications - four parameters needed lExample – low pass filter: A min, A max, Passband, Stopband lParameters specify the basic characteristics of filter, e.g. low pass filtering lSpecify limitations to its ability to filter, e.g. nonuniform transmission in passband, incomplete blocking of frequencies in stopband
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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 4 Filter Transfer Function *Any filter transfer function T(s) can be written as a ratio of two polynomials in “s” *Where M < N and N is called the “order” of the filter function lHigher N means better filter performance lHigher N also means more complex circuit implementation *Filter transfer function T(s) can be rewritten as lwhere z’s are “zeros” and p’s are “poles” of T(s) lwhere poles and zeroes can be real or complex *Form of transfer function is similar to low frequency function F L (s) seen previously for amplifiers where A(s) = A M F L (s)F H (s)
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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 5 First Order Filter Functions * First order filter functions are of the general form Low Pass High Pass a 1 = 0 a 0 = 0
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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 6 First Order Filter Functions * First order filter functions are of the form General All Pass a 1 0, a 2 0
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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 7 Example of First Order Filter - Passive *Low Pass Filter 0 dB
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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 8 20 log (R 2 /R 1 ) Example of First Order Filter - Active *Low Pass Filter V_= 0 IoIo I 1 = I o GainFilter function
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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 9 Second-Order Filter Functions * Second order filter functions are of the form which we can rewrite as where o and Q determine the poles * There are seven second order filter types: Low pass, high pass, bandpass, notch, Low-pass notch, High-pass notch and All-pass jj s-plane oo x x This looks like the expression for the new poles that we had for a feedback amplifier with two poles.
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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 10 Second-Order Filter Functions Low Pass High Pass Bandpass a 1 = 0, a 2 = 0 a 0 = 0, a 1 = 0 a 0 = 0, a 2 = 0
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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 11 Second-Order Filter Functions Notch Low Pass Notch High Pass Notch a 1 = 0, a o = ω o 2 a 1 = 0, a o > ω o 2 a 1 = 0, a o < ω o 2 All-Pass
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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 12 Passive Second Order Filter Functions *Second order filter functions can be implemented with simple RLC circuits *General form is that of a voltage divider with a transfer function given by *Seven types of second order filters lHigh pass lLow pass lBandpass lNotch at ω o lGeneral notch lLow pass notch lHigh pass notch
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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 13 *Low pass filter Example - Passive Second Order Filter Function General form of transfer function T(dB) 00 0 dB Q
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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 14 Example - Passive Second Order Filter Function *Bandpass filter General form of transfer function T(dB) 00 0 dB -3 dB
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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 15 Single-Amplifier Biquadratic Active Filters *Generate a filter with second order characteristics using amplifiers, R’s and C’s, but no inductors. *Use op amps since readily available and inexpensive *Use feedback amplifier configuration lWill allow us to achieve filter-like characteristics *Design feedback network of resistors and capacitors to get the desired frequency form for the filter, i.e. type of filter, e.g bandpass. *Determine sizes of R’s and C’s to get desired frequency characteristics ( 0 and Q), e.g. center frequency and bandwidth. *Note: The frequency characteristics for the active filter will be independent of the op amp’s frequency characteristics. Example - Bandpass Filter General form of transfer function
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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 16 Design of the Feedback Network *General form of the transfer function for feedback network is *Loop gain for feedback amplifier is *Gain with feedback for feedback amplifier is *Poles of feedback amplifier (filter) are found from setting Conclusion: Poles of the filter are the same as the zeros of the RC feedback network ! Design Approach: 1. Analyze RC feedback network to find expressions for zeros in terms R’s and C’s. 2. From desired 0 and Q for the filter, calculate R’s and C’s. 3. Determine where to inject input signal to get desired form of filter, e.g. bandpass.
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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 17 Design of the Feedback Network *Bridged-T networks (2 R’s and 2C’s) can be used as feedback networks to implement several of the second order filter functions. *Need to analyze bridged-T network to get transfer function t(s) of the feedback network. We will show that *Zeros of this t(s) will give the pole frequencies for the active filter.. Bridged – T network General form of filter’s transfer function
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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 18 Analysis of t(s) for Bridged-T Network VbVb VaVa I 3 = (V b -V a )/R 3 I 2 = I 3 I a = 0 I1I1 V 12 I4I4 Analysis for t(s) = V a / V b
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ECES 352 Winter 2007 Ch. 12 Active Filters Part 1 19 Analysis of Bridged-T Network *Setting numerator of t(s) = 0 gives zeroes of t(s), which are also the poles of filter’s transfer function T(s) since *Where the general form of filter’s T(s) is *Then comparing the numerator of t(s) and the denominator of T(s), o and Q are related to the R’s and C’s by *so *Given the desired filter characteristics specified by o and Q, the R’s and C’s can now be calculated to build the filter. These have the same form – a quadratic !
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