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Putting a Junta to the Test Joint work with Eldar Fischer & Guy Kindler
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© S.Safra Boolean Functions and Juntas A boolean function Def: f is a j-Junta if there exists J [n] where |J|≤ j, and s.t. for every x f(x) = f(x J) f is ( , j)-Junta if j-Junta f’ s.t. f is ( , j)-Junta if j-Junta f’ s.t.
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© S.Safra Junta Test Def: A Junta test is as follows: A distribution over l queries For each l-tuple, a local-test that either accepts or rejects:T[x 1, …, x l ]: {1, -1} l {T,F} s.t. for a j-junta f whereas for any f which is not ( , j)-Junta
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© S.Safra Functions as Inner-Product Space {-1,1} n f f n n 2n2n 2n2n f f n n 2n2n 2n2n
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© S.Safra Fourier-Walsh Transform Consider all multiplicative functions, one for each character S [n] Consider all multiplicative functions, one for each character S [n] Given any function let the Fourier-Walsh coefficients of f be Given any function let the Fourier-Walsh coefficients of f be thus f can described as thus f can described as 2n2n 2n2n
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© S.Safra Simple Observations Claim: Claim: Thm [Parseval]: Thm [Parseval]: Hence, for a boolean f Hence, for a boolean f 2n2n 2n2n
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© S.Safra Variables` Influence The influence of an index i [n] on a boolean function f:{1,-1} n {1,-1} is The influence of an index i [n] on a boolean function f:{1,-1} n {1,-1} is Which can be expressed in terms of the Fourier coefficients of f Claim: Which can be expressed in terms of the Fourier coefficients of f Claim: 2n2n 2n2n
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© S.Safra Fourier Representation of influence Proof: consider the I-average function which in Fourier representation is and
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© S.Safra Fourier Representation of influence Proof: consider the influence function which in Fourier representation is and
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© S.Safra High vs Low Frequencies Def: The section of a function f above k is and the low-frequency portion is
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© S.Safra Subsets` Influence Def: The influence of a subset I [n] on a boolean function f is and the low-frequency influence 2n2n 2n2n
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© S.Safra Independence-Test The I-independence-test on a boolean function f is, for Lemma:
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© S.Safra
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Junta Test The junta-size test on a boolean function f is The junta-size test on a boolean function f is Randomly partition [n] to I 1,.., I r Randomly partition [n] to I 1,.., I r Run the independence-test t times on each I h Run the independence-test t times on each I h Accept if all but ≤j of the I h fail their independence-tests Accept if all but ≤j of the I h fail their independence-tests For r>>j 2 and t>>j 2 /
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© S.Safra Completeness Lemma: for a j-junta f Proof: only those sets which contain an index of the Junta would fail the independence-test
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© S.Safra Soundness Lemma: Proof: Assume the premise. Fix <<1/t and let
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© S.Safra |J| ≤ j Prop: r >> j implies |J| ≤ j Proof: otherwise, J spreads among I h w.h.p. J spreads among I h w.h.p. and for any I h s.t. I h J ≠ it must be that influence I (f) > and for any I h s.t. I h J ≠ it must be that influence I (f) >
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© S.Safra High Frequencies Contribute Little Prop: k >> r log r implies Proof: a character S of size larger than k spreads w.h.p. over all parts I h, hence contributes to the influence of all parts. If such characters were heavy (> /4), then surely there would be more than j parts I h that fail the t independence-tests
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© S.Safra Almost all Weight is on J Lemma: Proof: otherwise, since for a random partition w.h.p. (Chernoff bound) for every h however, since for any I the influence of every I h would be ≥ /100rk
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© S.Safra Find the Close Junta Now, since consider the (non boolean) which, if rounded outside J is boolean and not more than far from f
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© S.Safra Open Problems Is there a characterization, via Fourier transform, of all efficiently testable properties? Is there a characterization, via Fourier transform, of all efficiently testable properties? What about tests that probe f only at two or three points? With applications to hardness of approximation. What about tests that probe f only at two or three points? With applications to hardness of approximation.
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