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ME221Lecture 281 ME 221 Statics Lecture #28 Sections 6.1 – 6.4.

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Presentation on theme: "ME221Lecture 281 ME 221 Statics Lecture #28 Sections 6.1 – 6.4."— Presentation transcript:

1 ME221Lecture 281 ME 221 Statics Lecture #28 Sections 6.1 – 6.4

2 ME221Lecture 282 Homework #10 Chapter 7 problems: –2, 5, 6, 8, 19, 21, 24, 26 & 35 Due Friday, November 7

3 ME221Lecture 283 Homework #11 Chapter 6 problems: –2, 3, 6 & 7 – Method of Joints –32, 36, 47 & 53 – Method of Sections –68 & 75 – See Angel for info Due Wednesday, November 19

4 ME221Lecture 284 Quiz #6 Today Exam #3 Wednesday, November 12

5 ME221Lecture 285 Chapter 6: Analysis of Structures The knowledge of internal forces is a fundamental requirement for true design The Structural elements are: Trusses Frames Machines

6 ME221Lecture 286 Trusses Composed of slender straight pieces connected together by frictionless pins where all the loads (no moments) are applied. Each member will act as a two-force member (either in tension or compression). All the forces acting on a truss member are axial.

7 ME221Lecture 287 Frames Are designed to support, prevent or transmit loads (forces, no moments). At least one member is not a two-force member. Machines Are designed to transmit force, motion or energy (forces and moments). Will always have at least one member with multiple forces.

8 ME221Lecture 288 Planar Trusses If the planar truss (2-D) is statically determinant, then the number of joints is related to the number of reactions and internal members by : 2j = m + r j = number of joints m = number of internal members r = number of reactions

9 ME221Lecture 289 Analysis of Trusses Using the Method of Joints AyAy AxAx P Ax P AY P By P Bx P Cy P Cx CyCy A B C  We need to solve for: (1) - Internal forces F AB, F AC, and F BC (2) - Reactions A x, A y and C y

10 ME221Lecture 2810 AyAy AxAx P Ax P AY A  F AC F AB F AB cos  + F AC + A x = -P ax ……………….(1) F AB sin  + A y = -P ay ……………………(2) Joint A:

11 ME221Lecture 2811 P Cy P Cx CyCy C  F CA F CB At Joint C:

12 ME221Lecture 2812 P By P Bx B  F BA F BC At Joint B:

13 ME221Lecture 2813 Using Matrix Notation = Using manual calculations Look for joints with 2 unknowns

14 ME221Lecture 2814 Example

15 ME221Lecture 2815 Example 1.2 m 1.2 m 6 kN 3 kN E B A CD 0.9 m

16 ME221Lecture 2816 6 kN 3 kN E B A C D 44 16 4 4 9 9 15 5 5


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