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Lecture 4 Chemical Reaction Engineering (CRE) is the field that studies the rates and mechanisms of chemical reactions and the design of the reactors in which they take place.
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Today’s lecture Block 1 Block 2 Block 3 Mole Balances
Size CSTRs and PFRs given –rA=f(X) Block 2 Rate Laws Reaction Orders Arrhenius Equation Block 3 Stoichiometry Stoichiometric Table Definitions of Concentration Calculate the Equilibrium Conversion, Xe
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Reactor Mole Balances in terms of conversion
Differential Algebraic Integral Batch X t CSTR PFR PBR X W
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Last Lecture Relative Rates of Reaction
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Last Lecture Rate Laws - Power Law Model
A reactor follows an elementary rate law if the reaction orders just happens to agree with the stoichiometric coefficients for the reaction as written. e.g. If the above reaction follows an elementary rate law 2nd order in A, 1st order in B, overall third order
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Last Lecture Arrhenius Equation
k is the specific reaction rate (constant) and is given by the Arrhenius Equation. Where: k T
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Reaction Engineering Mole Balance Rate Laws Stoichiometry
These topics build upon one another
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How to find Step 1: Rate Law Step 2: Stoichiometry
Step 3: Combine to get
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We shall set up Stoichiometry Tables using species A as our basis of calculation in the following reaction. We will use the stochiometric tables to express the concentration as a function of conversion. We will combine Ci = f(X) with the appropriate rate law to obtain -rA = f(X). A is the limiting Reactant.
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For every mole of A that react, b/a moles of B react
For every mole of A that react, b/a moles of B react. Therefore moles of B remaining: Let ΘB = NB0/NA0 Then:
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Batch System Stoichiometry Table
Species Symbol Initial Change Remaining A NA0 -NA0X NA=NA0(1-X) B NB0=NA0ΘB -b/aNA0X NB=NA0(ΘB-b/aX) C NC0=NA0ΘC +c/aNA0X NC=NA0(ΘC+c/aX) D ND0=NA0ΘD +d/aNA0X ND=NA0(ΘD+d/aX) Inert I NI0=NA0ΘI NI=NA0ΘI FT0 NT=NT0+δNA0X and Where: δ = change in total number of mol per mol A reacted
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if a gas phase reaction occurs in a rigid (e.g. steel) batch reactor
Constant Volume Batch Note: If the reaction occurs in the liquid phase or if a gas phase reaction occurs in a rigid (e.g. steel) batch reactor Then etc.
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Stoichiometry Suppose Batch: Equimolar feed: Stoichiometric feed:
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Constant Volume Batch Reactor (BR)
if then Constant Volume Batch and we have
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Calculating the equilibrium conversion for gas phase reaction,Xe
BR Example Calculating the equilibrium conversion for gas phase reaction,Xe Consider the following elementary reaction with KC=20 dm3/mol and CA0=0.2 mol/dm3. Xe’ for both a batch reactor and a flow reactor.
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BR Example Calculate Xe Step 1: Step 2: rate law,
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BR Example Calculate Xe Totals: NT0=NA0 NT=NA0 -NA0 X/2
Symbol Initial Change Remaining A NA0 -NA0X NA0(1-X) B ½ NA0X NA0 X/2 Totals: NT0=NA0 NT=NA0 -NA0 X/2 @ equilibrium: -rA=0
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Calculating the equilibrium conversion for gas phase reaction
BR Example Calculating the equilibrium conversion for gas phase reaction Solution: At equilibrium Stoichiometry Constant volume Batch Species Initial Change Remaining A NA0 -NA0X NA=NA0(1-X) B +NA0X/2 NB=NA0X/2 NT0=NA0 NT=NA0-NA0X/2
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BR Example Xeb
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Flow System Stochiometric Table
Species Symbol Reactor Feed Change Reactor Effluent A FA0 -FA0X FA=FA0(1-X) B FB0=FA0ΘB -b/aFA0X FB=FA0(ΘB-b/aX) Where:
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Flow System Stochiometric Table
Species Symbol Reactor Feed Change Reactor Effluent C FC0=FA0ΘC +c/aFA0X FC=FA0(ΘC+c/aX) D FD0=FA0ΘD +d/aFA0X FD=FA0(ΘD+d/aX) Inert I FI0=A0ΘI FI=FA0ΘI FT0 FT=FT0+δFA0X Where: and Concentration – Flow System
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Flow System Stochiometric Table
Species Symbol Reactor Feed Change Reactor Effluent A FA0 -FA0X FA=FA0(1-X) B FB0=FA0ΘB -b/aFA0X FB=FA0(ΘB-b/aX) C FC0=FA0ΘC +c/aFA0X FC=FA0(ΘC+c/aX) D FD0=FA0ΘD +d/aFA0X FD=FA0(ΘD+d/aX) Inert I FI0=FA0ΘI FI=FA0ΘI FT0 FT=FT0+δFA0X Where: and Concentration – Flow System
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We will consider CA and CB for gas phase reactions in the next lecture
Concentration Flow System: Liquid Phase Flow System: Flow Liquid Phase etc. We will consider CA and CB for gas phase reactions in the next lecture
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Heat Effects Isothermal Design Stoichiometry Rate Laws Mole Balance
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End of Lecture 4
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