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PH 401 Dr. Cecilia Vogel
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Atoms in a Crystal On Monday, we modeled electrons in a crystal as experiencing an array of wells, one for each atom in the crystal. What do the atoms themselves experience? Each atom is pretty much bound to one well – no such thing as “conduction atoms” generally! Is it a square well? No, square well energy levels get further and further apart, Crystal atom levels are nearly evenly spaced
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SHO Any well that is not flat at the bottom has some curvature Thus can be approximated by a quadratic A quadratic potential energy function is called a simple harmonic oscillator If we place x=0 at the center of the well, V(x) = ½ m 2 x 2. where = the classical oscillation frequency (if it were classical rather than quantum)
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SHO Tricks Let’s find the stationary states of SHO by solving TISE Solutions are not obvious. 1 st trick: Let’s consider regions where |x| is very large, then and solution is
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SHO Tricks Plugging into Yields a value for B Unlike the square well, this decay constant is the same value (same B) for all energy levels, for all n. Why then does the wavefunction for higher energy levels extend further, wider?
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SHO Qualitative We can divide space into CA and CF regions, just like we have done before the center of the well, where E>V is classically allowed for large x, where E<V it is classically forbidden The point where it changes from CA to CF are the classical turning points the larger E is, the farther out the classical turning points E=V= ½ m 2 x 2 occurs for larger if E is larger
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SHO Tricks Trick #2: We know is true for large x For all x, we must have where f(x) is dominated by the exponential at large x f(x) is thus a polynomial of degree n
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SHO Qualitative We know qualitatively that the nth excited state crosses the axis n times as does a symmetric polynomial We also know that (since our PE is symmetric) our wavefunctions will be even or odd So our polynomials contain only even powers (even n) or only odd powers (odd n)
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Ground State Energy n=0, polynomial of degree zero = constant, call it Ao Plug into TISE plug in B Eo=(1/2) .
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2 nd Excited State Energy n=2, Plug into TISE quadratic term plug in B E2=(5/2) .
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PAL Friday week 6 1.Without doing any integrals, find the uncertainty in x and p for the ground state of a simple harmonic oscillator in terms of parameters and m. (HW) 2.a) What is the form of the wavefunction for the first excited state of a simple harmonic oscillator (n=1)? b) Plug this wavefunction into the TISE to determine the 1 st excited state energy in terms of parameters and m.
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Patterns for SHO 1.E n =(n + ½) 2. Energy levels are equally spaced, E= 3.
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