Download presentation
Presentation is loading. Please wait.
1
Chemical Reaction Engineering (CRE) is the field that studies the rates and mechanisms of chemical reactions and the design of the reactors in which they take place. Lecture 8
2
Lecture 8 – Tuesday 2/1/2011 Liquid Phase Reactions: Pressure Drop does not affect the concentrations in liquid phase rxn. Gas Phase Reactions: Epsilon not Equal to Zero d(P)/d(W)=. Polymath will combine with d(X)/f(W)=..for you Epsilon = 0 and Isothermal P=f(W) Combine then Separate Variables (X,W) and Integrate Engineering Analysis of Pressure Drop 2
3
Gas Phase Flow System: Concentration Flow System: 3
4
Note: Pressure drop does NOT affect liquid phase reactions Sample Question: Analyze the following second order gas phase reaction that occurs isothermally in a PBR: A B Must use the differential form of the mole balance to separate variables: Second order in A and irreversible: 4
5
Stoichiometry: Isothermal, T=T 0 Combine: Need to find (P/P 0 ) as a function of W (or V if you have a PFR) 5
6
Ergun Equation: 6 Constant mass flow:
7
Variable Density Let 7
8
Catalyst Weight Where Let 8
9
We will use this form for single reactions: Isothermal case 9
10
andor 10
11
11
12
W P 1 12
13
CACA W 13 2
14
-r A W 14 3
15
X W 15 4
16
W 1.0 16 5
17
17
18
Gas Phase Reaction in PBR with δ = 0 (Analytical Solution) A + B 2C Repeat the previous one with equimolar feed of A and B and k A = 1.5dm 6 /mol/kg/min α = 0.0099 kg -1 Find X at 100 kg 18
19
1) Mole Balance: 2) Rate Law: 3) Stoichiometry: 19
20
, 20, 4) Combine:
21
21
22
Polymath Solution A + 2B C is carried out in a packed bed reactor in which there is pressure drop.The fed is stoichiometric in A and B. Plot the conversion and pressure ratio y = P/P 0 as a function of catalyst weight upto 100 kg. Additional Information k A = 6dm 9 /mol 2 /kg/min α = 0.02 kg -1 22
23
A + 2B C 1) Mole Balance: 2) Rate Law: 3) Stoichiometry: Gas, Isothermal 23
24
4) 5) 6) 7) Initial values: W=0, X=0, y=1 W=100 Combine with Polymath. If δ ≠0, polymath must be used to solve. 24
25
25
26
26
27
27 T = T 0
29
29
30
30
31
31
32
Mole Balance Rate Laws Stoichiometry Isothermal Design Heat Effects 32
33
End of Lecture 8 33
34
Use for heat effects, multiple rxns Isothermal: T = T 0 34
35
A + B 2C Case 1: Case 2: 35
36
36
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.