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An Analysis of Convex Relaxations M. Pawan Kumar Vladimir Kolmogorov Philip Torr for MAP Estimation
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Aim 2 5 4 2 6 3 3 7 0 1 1 0 0 2 3 1 1 41 0 V1V1 V2V2 V3V3 V4V4 Label ‘0’ Label ‘1’ Labelling m = {1, 0, 0, 1} Random Variables V = {V 1,...,V 4 } Label Set L = {0, 1} To analyze convex relaxations for MAP estimation
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Aim 2 5 4 2 6 3 3 7 0 1 1 0 0 2 3 1 1 41 0 V1V1 V2V2 V3V3 V4V4 Label ‘0’ Label ‘1’ Cost(m) = 2 To analyze convex relaxations for MAP estimation
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Aim 2 5 4 2 6 3 3 7 0 1 1 0 0 2 3 1 1 41 0 V1V1 V2V2 V3V3 V4V4 Label ‘0’ Label ‘1’ Cost(m) = 2 + 1 To analyze convex relaxations for MAP estimation
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Aim 2 5 4 2 6 3 3 7 0 1 1 0 0 2 3 1 1 41 0 V1V1 V2V2 V3V3 V4V4 Label ‘0’ Label ‘1’ Cost(m) = 2 + 1 + 2 To analyze convex relaxations for MAP estimation
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Aim 2 5 4 2 6 3 3 7 0 1 1 0 0 2 3 1 1 41 0 V1V1 V2V2 V3V3 V4V4 Label ‘0’ Label ‘1’ Cost(m) = 2 + 1 + 2 + 1 To analyze convex relaxations for MAP estimation
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Aim 2 5 4 2 6 3 3 7 0 1 1 0 0 2 3 1 1 41 0 V1V1 V2V2 V3V3 V4V4 Label ‘0’ Label ‘1’ Cost(m) = 2 + 1 + 2 + 1 + 3 To analyze convex relaxations for MAP estimation
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Aim 2 5 4 2 6 3 3 7 0 1 1 0 0 2 3 1 1 41 0 V1V1 V2V2 V3V3 V4V4 Label ‘0’ Label ‘1’ Cost(m) = 2 + 1 + 2 + 1 + 3 + 1 To analyze convex relaxations for MAP estimation
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Aim 2 5 4 2 6 3 3 7 0 1 1 0 0 2 3 1 1 41 0 V1V1 V2V2 V3V3 V4V4 Label ‘0’ Label ‘1’ Cost(m) = 2 + 1 + 2 + 1 + 3 + 1 + 3 To analyze convex relaxations for MAP estimation
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Aim 2 5 4 2 6 3 3 7 0 1 1 0 0 2 3 1 1 41 0 V1V1 V2V2 V3V3 V4V4 Label ‘0’ Label ‘1’ Cost(m) = 2 + 1 + 2 + 1 + 3 + 1 + 3 = 13 Minimum Cost Labelling = MAP estimate Pr(m) exp(-Cost(m)) To analyze convex relaxations for MAP estimation
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Aim 2 5 4 2 6 3 3 7 0 1 1 0 0 2 3 1 1 41 0 V1V1 V2V2 V3V3 V4V4 Label ‘0’ Label ‘1’ Cost(m) = 2 + 1 + 2 + 1 + 3 + 1 + 3 = 13 Which approximate algorithm is the best? NP-hard problem To analyze convex relaxations for MAP estimation
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Aim 2 5 4 2 6 3 3 7 0 1 1 0 0 2 3 1 1 41 0 V1V1 V2V2 V3V3 V4V4 Label ‘0’ Label ‘1’ Objectives Compare existing convex relaxations – LP, QP and SOCP Develop new relaxations based on the comparison To analyze convex relaxations for MAP estimation
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Outline Integer Programming Formulation Existing Relaxations Comparison Generalization of Results Two New SOCP Relaxations
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Integer Programming Formulation 2 5 4 2 0 1 3 0 V1V1 V2V2 Label ‘0’ Label ‘1’ Unary Cost Unary Cost Vector u = [ 5 Cost of V 1 = 0 2 Cost of V 1 = 1 ; 2 4 ] Labelling m = {1, 0}
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2 5 4 2 0 1 3 0 V1V1 V2V2 Label ‘0’ Label ‘1’ Unary Cost Unary Cost Vector u = [ 5 2 ; 2 4 ] T Labelling m = {1, 0} Label vector x = [ -1 V 1 0 1 V 1 = 1 ; 1 -1 ] T Recall that the aim is to find the optimal x Integer Programming Formulation
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2 5 4 2 0 1 3 0 V1V1 V2V2 Label ‘0’ Label ‘1’ Unary Cost Unary Cost Vector u = [ 5 2 ; 2 4 ] T Labelling m = {1, 0} Label vector x = [ -11; 1 -1 ] T Sum of Unary Costs = 1 2 ∑ i u i (1 + x i ) Integer Programming Formulation
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2 5 4 2 0 1 3 0 V1V1 V2V2 Label ‘0’ Label ‘1’ Pairwise Cost Labelling m = {1, 0} 0 Cost of V 1 = 0 and V 1 = 0 0 00 0 Cost of V 1 = 0 and V 2 = 0 3 Cost of V 1 = 0 and V 2 = 1 10 00 00 10 30 Pairwise Cost Matrix P Integer Programming Formulation
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2 5 4 2 0 1 3 0 V1V1 V2V2 Label ‘0’ Label ‘1’ Pairwise Cost Labelling m = {1, 0} Pairwise Cost Matrix P 00 00 0 3 10 00 00 10 30 Sum of Pairwise Costs 1 4 ∑ ij P ij (1 + x i )(1+x j ) Integer Programming Formulation
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2 5 4 2 0 1 3 0 V1V1 V2V2 Label ‘0’ Label ‘1’ Pairwise Cost Labelling m = {1, 0} Pairwise Cost Matrix P 00 00 0 3 10 00 00 10 30 Sum of Pairwise Costs 1 4 ∑ ij P ij (1 + x i +x j + x i x j ) 1 4 ∑ ij P ij (1 + x i + x j + X ij )= X = x x T X ij = x i x j Integer Programming Formulation
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Constraints Uniqueness Constraint ∑ x i = 2 - |L| i V a Integer Constraints x i {-1,1} X = x x T Integer Programming Formulation
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x* = argmin 1 2 ∑ u i (1 + x i ) + 1 4 ∑ P ij (1 + x i + x j + X ij ) ∑ x i = 2 - |L| i V a x i {-1,1} X = x x T Convex Non-Convex Integer Programming Formulation
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Outline Integer Programming Formulation Existing Relaxations –Linear Programming (LP-S) –Semidefinite Programming (SDP-L) –Second Order Cone Programming (SOCP-MS) Comparison Generalization of Results Two New SOCP Relaxations
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LP-S x* = argmin 1 2 ∑ u i (1 + x i ) + 1 4 ∑ P ij (1 + x i + x j + X ij ) ∑ x i = 2 - |L| i V a x i {-1,1} X = x x T Retain Convex Part Schlesinger, 1976 Relax Non-Convex Constraint
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LP-S x* = argmin 1 2 ∑ u i (1 + x i ) + 1 4 ∑ P ij (1 + x i + x j + X ij ) ∑ x i = 2 - |L| i V a x i [-1,1] X = x x T Retain Convex Part Schlesinger, 1976 Relax Non-Convex Constraint
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LP-S X = x x T Schlesinger, 1976 X ij [-1,1] 1 + x i + x j + X ij ≥ 0 ∑ X ij = (2 - |L|) x i j V b
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LP-S x* = argmin 1 2 ∑ u i (1 + x i ) + 1 4 ∑ P ij (1 + x i + x j + X ij ) ∑ x i = 2 - |L| i V a x i [-1,1] X = x x T Retain Convex Part Schlesinger, 1976 Relax Non-Convex Constraint
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LP-S x* = argmin 1 2 ∑ u i (1 + x i ) + 1 4 ∑ P ij (1 + x i + x j + X ij ) ∑ x i = 2 - |L| i V a x i [-1,1], Retain Convex Part Schlesinger, 1976 X ij [-1,1] 1 + x i + x j + X ij ≥ 0 ∑ X ij = (2 - |L|) x i j V b LP-S
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Outline Integer Programming Formulation Existing Relaxations –Linear Programming (LP-S) –Semidefinite Programming (SDP-L) –Second Order Cone Programming (SOCP-MS) Comparison Generalization of Results Two New SOCP Relaxations Experiments
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SDP-L x* = argmin 1 2 ∑ u i (1 + x i ) + 1 4 ∑ P ij (1 + x i + x j + X ij ) ∑ x i = 2 - |L| i V a x i {-1,1} X = x x T Retain Convex Part Lasserre, 2000 Relax Non-Convex Constraint
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SDP-L x* = argmin 1 2 ∑ u i (1 + x i ) + 1 4 ∑ P ij (1 + x i + x j + X ij ) ∑ x i = 2 - |L| i V a x i [-1,1] X = x x T Retain Convex Part Relax Non-Convex Constraint Lasserre, 2000
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x1x1 x2x2 xnxn 1... 1x1x1 x2x2... xnxn 1xTxT x X = Rank = 1 X ii = 1 Positive Semidefinite Convex Non-Convex SDP-L
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x1x1 x2x2 xnxn 1... 1x1x1 x2x2... xnxn 1xTxT x X = X ii = 1 Positive Semidefinite Convex SDP-L
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Schur’s Complement AB BTBT C = I0 B T A -1 I A0 0 C - B T A -1 B IA -1 B 0 I 0 A 0 C -B T A -1 B 0
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X - xx T 0 1xTxT x X = 10 x I 10 0 X - xx T IxTxT 0 1 Schur’s Complement SDP-L
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x* = argmin 1 2 ∑ u i (1 + x i ) + 1 4 ∑ P ij (1 + x i + x j + X ij ) ∑ x i = 2 - |L| i V a x i [-1,1] X = x x T Retain Convex Part Relax Non-Convex Constraint Lasserre, 2000
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SDP-L x* = argmin 1 2 ∑ u i (1 + x i ) + 1 4 ∑ P ij (1 + x i + x j + X ij ) ∑ x i = 2 - |L| i V a x i [-1,1] Retain Convex Part X ii = 1 X - xx T 0 Accurate SDP-L Inefficient Lasserre, 2000
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Outline Integer Programming Formulation Existing Relaxations –Linear Programming (LP-S) –Semidefinite Programming (SDP-L) –Second Order Cone Programming (SOCP-MS) Comparison Generalization of Results Two New SOCP Relaxations
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SOCP Relaxation x* = argmin 1 2 ∑ u i (1 + x i ) + 1 4 ∑ P ij (1 + x i + x j + X ij ) ∑ x i = 2 - |L| i V a x i [-1,1] X ii = 1 X - xx T 0 Derive SOCP relaxation from the SDP relaxation Further Relaxation
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1-D Example X - xx T 0 X - x 2 ≥ 0 For two semidefinite matrices, Frobenius inner product is non-negative A A 0 x 2 X SOC of the form || v || 2 st = 1
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2-D Example X 11 X 12 X 21 X 22 1X 12 1 = X = x1x1x1x1 x1x2x1x2 x2x1x2x1 x2x2x2x2 xx T = x12x12 x1x2x1x2 x1x2x1x2 = x22x22
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2-D Example (X - xx T ) 1 - x 1 2 X 12 -x 1 x 2. 0 10 00 X 12 -x 1 x 2 1 - x 2 2 x 1 2 1 -1 x 1 1 C 1. 0 C 1 0
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2-D Example (X - xx T ) 1 - x 1 2 X 12 -x 1 x 2 C 2. 0. 0 00 01 X 12 -x 1 x 2 1 - x 2 2 x 2 2 1 -1 x 2 1 C 2 0
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2-D Example (X - xx T ) 1 - x 1 2 X 12 -x 1 x 2 C 3. 0. 0 11 11 X 12 -x 1 x 2 1 - x 2 2 (x 1 + x 2 ) 2 2 + 2X 12 SOC of the form || v || 2 st C 3 0
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2-D Example (X - xx T ) 1 - x 1 2 X 12 -x 1 x 2 C 4. 0. 0 1 1 X 12 -x 1 x 2 1 - x 2 2 (x 1 - x 2 ) 2 2 - 2X 12 SOC of the form || v || 2 st C 4 0
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SOCP Relaxation Consider a matrix C 1 = UU T 0 (X - xx T ) ||U T x || 2 X. C 1 C 1. 0 Continue for C 2, C 3, …, C n SOC of the form || v || 2 st Kim and Kojima, 2000
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SOCP Relaxation How many constraints for SOCP = SDP ? Infinite. For all C 0 Specify constraints similar to the 2-D example xixi xjxj X ij (x i + x j ) 2 2 + 2X ij (x i + x j ) 2 2 - 2X ij
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SOCP-MS x* = argmin 1 2 ∑ u i (1 + x i ) + 1 4 ∑ P ij (1 + x i + x j + X ij ) ∑ x i = 2 - |L| i V a x i [-1,1] X ii = 1 X - xx T 0 Muramatsu and Suzuki, 2003
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SOCP-MS x* = argmin 1 2 ∑ u i (1 + x i ) + 1 4 ∑ P ij (1 + x i + x j + X ij ) ∑ x i = 2 - |L| i V a x i [-1,1] (x i + x j ) 2 2 + 2X ij (x i - x j ) 2 2 - 2X ij Specified only when P ij 0 Muramatsu and Suzuki, 2003
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Outline Integer Programming Formulation Existing Relaxations Comparison Generalization of Results Two New SOCP Relaxations
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Dominating Relaxation For all MAP Estimation problem (u, P) A dominates B A B ≥ Dominating relaxations are better
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Equivalent Relaxations A dominates B A B = B dominates A For all MAP Estimation problem (u, P)
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Strictly Dominating Relaxation A dominates B A B > B does not dominate A For at least one MAP Estimation problem (u, P)
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SOCP-MS (x i + x j ) 2 2 + 2X ij (x i - x j ) 2 2 - 2X ij Muramatsu and Suzuki, 2003 P ij ≥ 0 (x i + x j ) 2 2 - 1 X ij = P ij < 0 (x i - x j ) 2 2 1 - X ij = SOCP-MS is a QP Same as QP by Ravikumar and Lafferty, 2005 SOCP-MS ≡ QP-RL
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LP-S vs. SOCP-MS Differ in the way they relax X = xx T X ij [-1,1] 1 + x i + x j + X ij ≥ 0 ∑ X ij = (2 - |L|) x i j V b LP-S (x i + x j ) 2 2 + 2X ij (x i - x j ) 2 2 - 2X ij SOCP-MS F(LP-S) F(SOCP-MS)
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LP-S vs. SOCP-MS LP-S strictly dominates SOCP-MS LP-S strictly dominates QP-RL Where have we gone wrong? A Quick Recap !
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Recap of SOCP-MS xixi xjxj X ij 11 11 C = (x i + x j ) 2 2 + 2X ij
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Recap of SOCP-MS xixi xjxj X ij 1 1 C = (x i - x j ) 2 2 - 2X ij Can we use different C matrices ?? Can we use a different subgraph ??
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Outline Integer Programming Formulation Existing Relaxations Comparison Generalization of Results –SOCP Relaxations on Trees –SOCP Relaxations on Cycles Two New SOCP Relaxations
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SOCP Relaxations on Trees Choose any arbitrary tree
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SOCP Relaxations on Trees Choose any arbitrary C 0 Repeat over trees to get relaxation SOCP-T LP-S strictly dominates SOCP-T LP-S strictly dominates QP-T
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Outline Integer Programming Formulation Existing Relaxations Comparison Generalization of Results –SOCP Relaxations on Trees –SOCP Relaxations on Cycles Two New SOCP Relaxations
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SOCP Relaxations on Cycles Choose an arbitrary even cycle P ij ≥ 0 P ij ≤ 0OR
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SOCP Relaxations on Cycles Choose any arbitrary C 0 Repeat over even cycles to get relaxation SOCP-E LP-S strictly dominates SOCP-E LP-S strictly dominates QP-E
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SOCP Relaxations on Cycles True for odd cycles with P ij ≤ 0 True for odd cycles with P ij ≤ 0 for only one edge True for odd cycles with P ij ≥ 0 for only one edge True for all combinations of above cases
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Outline Integer Programming Formulation Existing Relaxations Comparison Generalization of Results Two New SOCP Relaxations –The SOCP-C Relaxation –The SOCP-Q Relaxation
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The SOCP-C Relaxation Include all LP-S constraintsTrue SOCP ab 0 0 11 0 0 0 bc 1 0 00 0 0 0 ca 0 0 11 0 0 0 010 Submodular Non-submodularSubmodular
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The SOCP-C Relaxation ab Include all LP-S constraintsTrue SOCP 0 0 11 0 0 0 bc 1 0 00 0 0 0 ca 0 0 11 0 0 0 010 Frustrated Cycle
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The SOCP-C Relaxation ab Include all LP-S constraintsTrue SOCP 0 0 11 0 0 0 bc 1 0 00 0 0 0 ca 0 0 11 0 0 0 010 LP-S Solution ab 1 0 0 0 0 bc 0 11 0 0 0 ca 0 0 0 0 1 1 1 Objective Function = 0
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The SOCP-C Relaxation ab Include all LP-S constraintsTrue SOCP 0 0 11 0 0 0 bc 1 0 00 0 0 0 ca 0 0 11 0 0 0 010 LP-S Solution ab 1 0 0 0 0 bc 0 11 0 0 0 ca 0 0 0 0 1 1 1 Define an SOC Constraint using C = 1
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The SOCP-C Relaxation ab Include all LP-S constraintsTrue SOCP 0 0 11 0 0 0 bc 1 0 00 0 0 0 ca 0 0 11 0 0 0 010 LP-S Solution ab 1 0 0 0 0 bc 0 11 0 0 0 ca 0 0 0 0 1 1 1 (x i + x j + x k ) 2 3 + 2 (X ij + X jk + X ki )
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The SOCP-C Relaxation ab Include all LP-S constraintsTrue SOCP 0 0 11 0 0 0 bc 1 0 00 0 0 0 ca 0 0 11 0 0 0 010 SOCP-C Solution Objective Function = 0.75 SOCP-C strictly dominates LP-S ab 0.8 0.6 -0.8 -0.6 0.6 -0.6 bc 0.6 -0.6 0 0 ca 0 0 0.8 0.6 -0.6 0.4 -0.4 0.4 -0.3 0.3 -0.3
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Outline Integer Programming Formulation Existing Relaxations Comparison Generalization of Results Two New SOCP Relaxations –The SOCP-C Relaxation –The SOCP-Q Relaxation
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The SOCP-Q Relaxation Include all cycle inequalitiesTrue SOCP ab cd Clique of size n Define an SOCP Constraint using C = 1 (Σ x i ) 2 ≤ n + (Σ X ij ) SOCP-Q strictly dominates LP-S SOCP-Q strictly dominates SOCP-C
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4-Neighbourhood MRF Test SOCP-C 50 binary MRFs of size 30x30 u ≈ N (0,1) P ≈ N (0,σ 2 )
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4-Neighbourhood MRF σ = 2.5
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8-Neighbourhood MRF Test SOCP-Q 50 binary MRFs of size 30x30 u ≈ N (0,1) P ≈ N (0,σ 2 )
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8-Neighbourhood MRF σ = 1.125
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Conclusions Large class of SOCP/QP dominated by LP-S New SOCP relaxations dominate LP-S More experimental results in poster
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Future Work Comparison with cycle inequalities Determine best SOC constraints Develop efficient algorithms for new relaxations
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Questions ??
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