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1) HBr 1D (2+n)REMPI spectra simulations 2) Energy level shifts and intensity ratios for the F(v´=1) state agust,www,....Jan11/PPT-080211ak.ppt agust,heima,....Jan11/XLS-080211ak.xls agust,heima,....Jan11/PXP-080211ak.pxp agust,heima,...Jan11/XLS-080211hrhak.xls
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H81Br H79Br Estimated values: see agust,heima,....Jan11/XLS-080211ak.xls
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Calc. B´= 7.2379, D´=0.0006 T=70K Exp. H79Br agust,heima,....Jan11/PXP-080211ak.pxp; Lay:0, Gr:1 Peakspectra("AB_Standard",70.15,0,0,0,0,2456.527,41.93246,7.2379,0.0006) Absorptionspectra("w_stx","w_sty","w_glx","w_gly",0.5,"Gauss",0.1,21) Unknown system h
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H79Br H81Br agust,heima,....Jan11/PXP-080211ak.pxp; Lay:0, Gr:1 h
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Not easy to obtain good fit Possible explanation: The “unknown state”, being very close to the V(v´=m+8) system, is heavily perturbed due to “unknown state” V(v´=m+8) level to level near resonance interaction.
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Peakspectra("AB_Standard",70.15,0,0,0,0,2456.527,41.93246, 7.2379,-0.016) Absorptionspectra("w_stx","w_sty","w_glx","w_gly",0.5,"Gauss",0.1,21) agust,heima,....Jan11/PXP-090211ak.pxp; Lay:0, Gr:1 Calc. B´= 7.2379, D´=-0.016 T=70K Unknown system h Exp. H79Br
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Fit can be obtaiend by using relatively high negative value for D´(= - 0.016 cm-1) which definitly suggests that there is a perturbation effect
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Peakspectra("AB_Standard",150.15,0,0,0,0,2456.527,41.93246,4.40,0.0017) Absorptionspectra("w_stx","w_sty","w_glx","w_gly",0.5,"Gauss",0.1,21) Calc. B´= 4.40 D´=0.0017 T=150K Exp. H79Br agust,heima,....Jan11/PXP-080211ak.pxp; Lay:0, Gr:1 V(v´=m+8) <-<-X h
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2) Energy level shifts and intensity ratios for the F(v´=1) state
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From Q lines (C&G): E J´,J´-1 J´ Increase agust,heima,....Jan11/PXP-080211ak.pxp; Lay:1, Gr:4 Coefficient values ± one standard deviation a = 1.2667 ± 0.269 b = 15.597 ± 0.0375
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Closer look / From Q lines (C&G): E J´,J´-1 J´ Increase Decrease agust,heima,....Jan11/PXP-080211ak.pxp; Lay:1, Gr:4 Coefficient values ± one standard deviation a = 1.2667 ± 0.269 b = 15.597 ± 0.0375
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It ought to be possible to derive W 12 (and W 12 ´) and the mixing fractions ( and ) from the data above: i.e. W 12 from the procedure described in http://www3.hi.is/~agust/rannsoknir/rempi/hcl/Jan11/PDF-020111ak.pdf And and from In order to do this more rotational lines / energy levels are needed for V, v´=m+7 than those given by Callaghan and Gordon (C & G)
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F(v´=1) <-<-X; Q: agust,heima,...Jan11/XLS-080211hrhak.xls
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The intensity ratio looks convincing for J´= 2-7 The intensity ratio is surprisingly high for J´=8 It is important to evaluate the uncertainties for the intensity ratios We should try to fit the Intensity ratios vs J´by the expression -which should be possible as long as more energy levels can be evaluated For the V(v´=m+7) state All in all we should emphasise to evaluate more energy levels from rotational lines for V(v´=m+7)
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81Br+ H81Br+ H+ J´=5 J´=6 J´=7 J´=4 3 2 1 0 J´=6,5 F(v´=1)Q V,v´=m+7 Br+ 2 P 3/2 ->-> 4 S 3/2 should be at 79178.33 cm-1 J´=8
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We need to repeat a scan over the region close to J´=5 peak for The V(v´=m+7) system to find the position of that peak.
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