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Robust Estimator 學生 : 范育瑋 老師 : 王聖智
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Outline Introduction LS-Least Squares LMS-Least Median Squares RANSAC- Random Sample Consequence MLESAC-Maximum likelihood Sample consensus MINPRAN-Minimize the Probability of Randomness
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Outline Introduction LS-Least Squares LMS-Least Median Squares RANSAC- Random Sample Consequence MLESAC-Maximum likelihood Sample consensus MINPRAN-Minimize the Probability of Randomness
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Introduction Objective: Robust fit of a model to a data set S which contains outliers.
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Outline Introduction LS-Least Squares LMS-Least Median Squares RANSAC- Random Sample Consequence MLESAC-Maximum likelihood Sample consensus MINPRAN-Minimize the Probability of Randomness
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LS Consider the data generating process Yi = b0 + b1Xi + ei, where ei is independently and identically distributed N(0, σ). If any outlier exists in the data. Least squares performs poorly.
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Outline Introduction LS-Least Squares LMS-Least Median Squares RANSAC- Random Sample Consequence MLESAC-Maximum likelihood Sample consensus MINPRAN-Minimize the Probability of Randomness
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LMS The method can tolerates the highest possible breakdown point of 50%.
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Outline Introduction LS-Least Squares LMS-Least Median Squares RANSAC- Random Sample Consequence MLESAC-Maximum likelihood Sample consensus MINPRAN-Minimize the Probability of Randomness
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Main idea
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Algorithm a. Randomly select a sample of s data points from S and instantiate the model from this subset. b. Determine the set of data points Si which are within a distance threshold t of the model. c. If the size of Si (number of inliers) is greater than threshold T, re-estimate the model using all points in Si and terminate. d. If the size of Si is less than T, select a new subset and repeat above. e. After N trials the largest consequence ser Si is selected, and the model is re-estimate the model using all points in the subset Si.
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Algorithm 1. What is the distance threshold? 2. How many sample? 3. How large is an acceptable consensus set?
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What is the distance threshold? We would like to choose the distance threshold, t, such that with a probability α the point is an inlier. Assume the measurement error is Gaussian with zero mean and standard deviation σ. In this case the square of point distance, d 2 ⊥, is sum of squared Gaussian variables and follows a χ 2 m distribution with m degrees of freedom.
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What is the distance threshold? Note: The probability that the value of a random variable is less than k 2 is given by the cumulative chi-squared distribution. Choose α as 0.95
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How many sample? If w = proportion of inliers = 1-ε Prob(sample with all inliers)=w s Prob(sample with an outlier)=1-w s Prob(N samples an outlier)=(1-w s ) N We want Prob (N samples an outlier)<1-p Usually p is chosen at 0.99. (1-w s ) N <1-p N>log(1-p)/log(1-w s )
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How large is an acceptable consensus set? If we know the fraction of data consisting of outliers. Use a rule of thumb : T=(1- ε )n For example: Data points : n=12 The probability of outlier ε =0.2 T=(1-0.2)12=10
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Outline Introduction LS-Least Squares LMS-Least Median Squares RANSAC- Random Sample Consequence MLESAC-Maximum likelihood Sample consensus MINPRAN-Minimize the Probability of Randomness
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THE TWO-VIEW RELATIONS
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Maximum Likelihood Estimation Assume the measurement error is Gaussian with zero mean and standard deviation σ n: The number of correspondences M : The appropriate two-view relation, D : The set of matches.
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Maximum Likelihood Estimation
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Modify the mode: Where γ is the mixing parameter, v is just a constant. Here it is assumed that the outlier distribution is uniform, with - v/2,…,v/2 being the pixel range within which outliers are expected to fall.
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How to estimate γ 1. The initial estimate of γ is ½ 2. Estimate the expectation of the η i from the current estimate of γ Where ηi =1 if the ith correspondence is an inlier, and ηi =0 if the ith correspondence is an outlier.
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How to estimate γ p i is the likelihood of a datum given that it is an inlier and p o is the likelihood of a datum given that it is an outlier: 3.Make a new estimate of γ 4.Repeat step2 and step3 until convergence.
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Outline Introduction LS-Least Squared LMS-Least Median Squared RANSAC- Random Sample Consequence MLESAC-Maximum likelihood Sample consensus MINPRAN-Minimize the Probability of Randomness
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MINPRAN The first technique that reliably tolerates more than 50% outliers without assuming a know inlier bound. It only assumes the outliers are uniformly distributed within the dynamic range of the sensor.
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MINPRAN
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N: The points are drawn from a uniform distribution of z value in range Zmin to Zmax. r: A distance between a curve φ k: Least points randomly full with in the range φ± r Z 0 :(Zmax-Zmin)/2
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MINPRAN
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Algorithm 1. Assuming p points are required to completely instantiate a fit. 2. Chooses S distinct, but not necessarily disjoint subsets of p points from data, and finds the fit to each random subsets to form the data, and finds the fit to each random subset to form S hypothesized fits φ 1,…., φ S 3. Select the minimizing as the “best fit”. 4. If, then φ * is accepted as a correct fit. 5. A final least-squares fit involving the p + i* inliers to φ * produces a accurate estimate of the model parameters.
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How many sample? If w = proportion of inliers = 1-ε Prob(sample with all inliers)=w p Prob(sample with an outlier)=1-w p Prob(S samples an outlier)=(1-w p ) S We want Prob (S samples an outlier)<1-p Usually p is chosen at 0.99. (1-w p ) S <1-p S>log(1-p)/log(1-w p )
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Randomness Threshold F 0 Choose probability P 0, and solve the equation. We can get Randomness Threshold F 0.
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Randomness Threshold F 0 Define the equation There is a unique value,,which can found by bisection search, such that By Lemma 2, if and only if In order to for all i, we get the constraints c i, 0 ≦ i < N, denote the number of the residuals in the range (f i …f i+1 ]
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Randomness Threshold F 0 Because the residuals are uniformly distributed, the probability any particular residuals are in the range f i to f i+1 is, where The probability c i particular residuals are in the range f i to f i+1 is Based on this, we can calculate the probability
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Randomness Threshold F 0 To make the analysis feasible, we assume the S fits and their residuals are independent. So the probability each of the S samples has is just The probability at least one sample has a minimum less than is We can get F 0, since we know N, S, P 0.
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