Download presentation
Presentation is loading. Please wait.
1
Second Law of Thermodynamics Physics 202 Professor Lee Carkner Lecture 18
2
PAL #17 Entropy Temperature of Titan P in = (F)( )(r 2 ) = (15.18)( )(2.58X10 6 ) 2 = 3.17X10 14 W T = [(P in )/( A)] 1/4 = [(P in )/( 4 r 2 )] 1/4 T = [(3.17X10 14 )/((5.6703X10 -8 )(4)( )(2.58X10 6 ) 2 )] 1/4
3
PAL #17 Entropy (con’t) Minimum mass molecule that will stay in atmosphere (( m = (300kTR)/(2GM) m = [(300)(1.38X10 -23 )(90)(2.58X10 6 )]/ [(2)(6.67X10 -11 )(1.35X10 23 )] m = 5.33X10 -26 kg What gasses would not be found on Titan? H 2, mass = 2, no CH 4, mass = 16, no CO 2, mass = 44, yes
4
Hero’s Door Opener (1 AD)
5
Steam Engines (18th century)
6
Internal Combustion Engine (late 19th century)
7
Engines These processes can be adiabatic, isothermal etc. Engines have a working substance that transfers heat and does work (usually a gas) The four processes will bring the working substance back to its initial condition
8
p-V and T-S Engine Diagrams
9
Engine Elements
10
The Stirling Engine The engine consists of two pistons one of which is maintained at a high temperature T H, the other at a low temperature T C The pistons are connected to linkages to transfer out the work
11
Stirling Engine Diagram QHQH QCQC THTH TCTC Hot Piston Cold Piston
12
The First 2 Strokes 1) The hot piston moves up adding heat Q H to the gas 2) Hot piston moves down and cold piston moves up, pushing hot gas into the central chamber
13
The Last 2 Strokes 3) The cold piston moves down transferring heat Q C to the cold reservoir 4) The cold piston moves down and the hot piston moves up, drawing the cold gas back into the hot piston
14
Stirling Engine Diagram
15
Cycle Computations Example: What is the net work of the Stirling Engine? For the first isothermal expansion: For the isothermal compression: Net work equals W out –W in
16
Heat and Work Over the course of one cycle positive work is done and heat is transferred Since the engine is a cycle the change in internal energy is zero Let us now use a Carnot engine (sometimes called an ideal engine), which has the maximum efficiency Since the total heat is Q H -Q L from the first law of thermodynamics W = Q H -Q L
17
Efficiency In order for the engine to work we need a source of heat for Q H = W/Q H An efficient engine produces a high ratio of output work to input heat
18
Efficiency and Heat = 1 - (Q L /Q H ) Q H = W + Q L
19
Efficiency and Entropy If all the processes are reversible, the change in entropy between the two reservoirs must be zero so: Q H /T H = Q L /T L C = 1 - (T L /T H ) Called ideal or Carnot engines
20
Ideal and Perfect Engines The above equations hold only for ideal engines Since no real processes are truly ideal < C It is also impossible to produce an engine where Q H is completely converted into work Why? Called a perfect engine (no energy lost to heat) Perfect engines violate the 2nd law of thermodynamics but not the first
21
Perfect Engine
22
Entropy and Real Engines Engines get hot, they produce waste heat (Q L ) The first law can be written: The second law of thermodynamics can be stated: You can not get out of an process as much as you put in
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.