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Lecture 284/3/06 Seminar today
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Secondary Batteries (rechargeable) Lead Acid battery E° = 2.04 V Anode:Pb(s) + HSO 4 - (aq) PbSO 4 (s) + H + + 2e - Cathode:PbO 2 (s) + HSO 4 - (aq) + 3H + + 2e - PbSO 4 (s) + 2H 2 O Combine 6 cells to get 12 V
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Electrolysis Need to put in energy 2 kinds Molten Aqueous Overpotential (or overvoltage) Extra voltage need to overcome electron transfer limitations between electrode and solution
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Electrolysis of molten salts Cathode:2Na + (l) + 2e - 2Na(l)E° = -2.71 V Anode:2Cl - (l) Cl 2 (g) + 2e - E° = 1.36 V Net:2NaCl (l) Cl 2 (g) + 2Na(l)E° =
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Electrolysis of aqueous solutions What would happen if you put electricity into a solution of KI? Possible oxidation reactions? Possible reduction reactions? Actual Reaction?
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General rules in aqueous solutions Reduction 6H 2 O + 2e - H 2 (g) + 2OH - E° = -0.8277 V Oxidation 6H 2 O O 2 (g) + 4H 3 O + + 4e - E° = 1.229 V
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Counting electrons
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1.50 amps flow through a Ag + (aq) solution for 15.0 min. What mass of Ag metal is deposited?
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The anode reaction in a lead storage battery is: Pb(s) + HSO 4 - (aq) PbSO 4 (s) + H + (aq) + 2e - If a battery delivers 1.50 amp, and you have 454 g of Pb, how long will the battery last?
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