Download presentation
Presentation is loading. Please wait.
1
Engines Physics 202 Professor Lee Carkner Lecture 18
2
Notes We should have class Friday, Jan 27 But check web page first Exam #2 has been moved from next Monday to next Wednesday (Feb 1) The discussion questions that were emailed out Monday are due Friday in class
3
PAL #16 Internal Energy 3 moles of gas, temperature raised from 300 to 400 K He gas, isochorically Q = nC V T, C V = Q = (3)(3/2)R(100) = # 4 for heat, all in translational motion He gas, isobarically Q = nC P T, C P = Q = (3)(5/2)R(100) = # 2 for heat, energy in translational and work H 2 gas, isochorically Q = nC V T, CV = Q = (3)(5/2)R(100) = # 2 for heat, energy into translational and rotational motion H 2 gas, isobarically Q = nC P T, CP = Q = (3)(7/2)R(100) = # 1 for heat, energy, into translation, rotation and work
4
Engines General engine properties: A working substance (usually a gas) An output of work
5
The Stirling Engine The Stirling engine is useful for illustrating the engine properties: The input of heat is from the flame The output of heat makes the fins hot
6
Parts of the Cycle Cycle can be broken down into specific parts In general: One involves compression One involves the output of heat Q L Change in internal energy is zero
7
Heat and Work Over the course of one cycle positive work is done and heat is transferred Since the engine is a cycle, the change in internal energy is zero E int =(Q H -Q L )-W =0 W = Q H - Q L
8
Engine Elements
9
Efficiency We get work out of an engine, what do we put into it? Q H is what you put in, W is what you get out so the efficiency is: = W/Q H The rest is output as Q L
10
Efficiency and Heat = 1 - (Q L /Q H ) The efficiency depends on how much of Q H is transformed into W and how much is lost in Q L : Reducing the output heat means improving the efficiency
11
The Second Law of Thermodynamics (Engines) This is one way of stating the second law: It is impossible to build an engine that converts heat completely into work Engines get hot, they produce waste heat (Q L ) You cannot completely eliminate friction, turbulence etc.
12
Carnot Engine C = 1 - (T C / T H ) This is the Carnot efficiency Any engine operating between two temperatures is less efficient than the Carnot efficiency < C There is a limit as to how efficient you can make your engine
13
The First and Second Laws The first law of thermodynamics says: The second law of thermodynamics says: The two laws imply: W < Q H W Q H
14
Dealing With Engines Most engine problems can be solved by knowing how to express the efficiency and relate the work and heats: W = Q H - Q L = Efficiency must be less than or equal to the Carnot Efficiency: If you know T L and T H you can find an upper limit for (=W/Q H ) For individual parts of the cycle you can often use the ideal gas law:
15
Entropy How can we quantify these limits and define a second law? In any thermodynamic process that proceeds from an initial to a final point, the change in entropy depends on the heat and temperature, specifically: S = S f –S i = ∫ (dQ/T)
16
Isothermal Entropy In practice, the integral may be hard to compute Let us consider the simplest case where the process is isothermal (T is constant): This is also approximately true for situations where temperature changes are very small
17
Entropy Change Imagine now a simple idealized system consisting of a box of gas in contact with a heat reservoir If the system loses heat –Q to the reservoir and the reservoir gains heat +Q from the system isothermally: The total change in entropy is zero
18
Second Law of Thermodynamics (Entropy) This situation is actually an upper limit S>0 This is also the second law of thermodynamics
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.