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ME 482: Mechanical Vibrations (062) Dr. M. Sunar.

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Presentation on theme: "ME 482: Mechanical Vibrations (062) Dr. M. Sunar."— Presentation transcript:

1 ME 482: Mechanical Vibrations (062) Dr. M. Sunar

2 Vibrations FreeForced UndampedDampedUndampedDamped

3 Undamped Free Vibrations of Single Degree of Freedom Systems Single Degree of Freedom System: System with one mass or inertia

4 The system is said to have a single degree-of-freedom, because it has only one mass and the variable x(t) is enough to describe the motion. Equation of Motion: Or, in another form: Example 1: Spring-Mass System

5 The system is again said to have a single degree-of-freedom, because it has only one inertia (and mass) and the variable  (t) is enough to describe the motion. Equation of Motion: Or, in another form: Example 2: Compound Pendulum  L = Length, m = mass

6 The system is said to have a single degree-of-freedom, because it has only one moment of inertia and the variable  (t) is enough to describe the motion. Equation of Motion: Or, in another form: Example 3: Shaft and Disk

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9 Equation of Motion: Or, in another form: Damped Free Vibrations of Single Degree of Freedom Systems A Single Degree of Freedom System with Viscous Damping:

10 We define the following: Natural Frequency = Damping Ratio = Damped Natural Frequency = Damped Period = Solution: Depends on the values of  0<  < 1 : Underdamped  = 1 : Critically Damped  > 1 : Overdamped

11 We get: Assume the solution as: IC are: 0<  < 1 : Underdamped

12 We also define, Logarithmic Decrement =  = Natural Log of Ratio of Amplitudes of Successive Cycles

13  = For small values of ,  = 2  In general, we have  = Furthermore,  = Or,  =

14 We get: Assume the solution as: IC are:  = 1 : Critically Damped

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16 We get: Assume the solution as: IC are:  > 1 : Overdamped

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