1. ENGR 150 Engineering Graphics REVIEW

2. Station Point Vanishing Point Picture Plane Horizon Line Ground Line abc a’b’ c’ 1-Point Perspective

3. Picture Plane Ground Line 2-Point Perspective SP Horizon LineVanishing Point Parallel

4. Station Point Picture Plane Horizon Line Ground Line 1-Point Perspective vp

5. Station Point Picture Plane Horizon Line Ground Line 1-Point Perspective vp

6. Isometric

7. Isometric Ellipse

8. Isometric Ellipse (4-center method) 1.Draw an isometric equilateral parallelogram with sides equal to diameter of circle. 2.Join the mid-point of each side to the nearer end-point of the opposite side. 3.Draw arcs of radius r and radius R. r R

9. True length line H 1 H F AFAF BHBH AHAH BFBF 12

10. True Length line and Point View True Length: – Place an auxiliary view parallel to the line – Project line on to the auxiliary view. Point View: – Find true length first – Place auxiliary view perpendicular to true length line – Project line on to 2 nd auxiliary view. H 1 H F AFAF BHBH AHAH BFBF 12

11. Edge View and True Shape Plane Edge View – Draw a line in the plane parallel to a “folding line” – Project this line into the adjacent view. – Find a point view of the this line and project the other points of the plane. True Shape – Place an auxiliary view parallel to the edge view – Project the plane into auxiliary view AFAF F H BFBF CHCH CFCF AHAH BHBH C1C1 A1A1 B1B1 1H T.L. 1 2 C2C2 B2B2 A2A2

12. Angle Between Planes C A D A F H B B D C T.L. E.V.

13. Exercise 1 F F H 2 1 2 3 TS θ C B,D A,E B,F B A F E C D F E C D A,C A,B E F D C D B A

14. Intersection and Visibility AFAF CFCF BFBF DFDF CHCH BHBH AHAH DHDH F H EFEF GFGF F HFHF GHGH FHFH EHEH H F H GH lies in front of EF GH lies on top of EF

15. Intersection of Line and Plane Cutting Plane Method AFAF F H BFBF CFCF GFGF LFLF AHAH BHBH CHCH GHGH LHLH Step 1 Step 2 Step 3

16. Intersection of Two Planes Cutting Plane Method BFBF F H AFAF CFCF XFXF YFYF BHBH CHCH AHAH YHYH ZHZH ZFZF XHXH BFBF F H AFAF CFCF XFXF YFYF BHBH CHCH AHAH YHYH ZHZH ZFZF XHXH

17. a2a2 c2c2 b2b2 d2d2 500 m a3a3 c3c3 c5c5 b5b5 Solution to 6-19 e,f 2 500 m 250 m d4d4 e4e4 b,f 4

18. Gradient Problem: solution