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Cell Adhesion Matt Tanke Will Howerton Stewart Bewley Jeff Mills
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Cell Adhesion Measurement Device Cell sits between two plates One plate fixed, one plate attached to linear spring Actuator pulls spring into tension
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Adhesion of Cell Cell will have a smooth outer membrane or flagellum Both exhibit non-linear cell/plate separation Flagellum Smooth Membrane http://library.thinkquest.org/16985/cellmain.htm http://fig.cox.miami.edu/Faculty/Dana/105F00_4.html
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Adhesion of Cell
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Current Design: Optical Tweezers Nm displacement pN force Glass bead dependent
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Scratch Drive μN forces 500 μm displacement Difficult to model
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Nano-tractor 40 nm step size Moves at 3 mm/s Stalls when 2.5 mN max tangential force is reached
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How it works
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Accuracy
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SUMMiT V Process Flow Conformal Deposition Planar Depostion Dry Etch Wet Etch Release Etch
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Diagram and Variables 6 variables: D 2, P 2, k s, D 1, P 1, k c 2 equations can be derived: P 1 = D 1 *(k c + k s ) – D 2 *k s P 2 = k s *(D 2 – D 1 ) D2D2 P2P2 ksks kckc D1D1 P1P1 D 2 is controlled by nano-tractor P 2 is the force needed for nano-tractor P 1 is the force needed to pull the cell D 1 is the displacement of the cell k c is the spring constant of the cell k s is the spring constant of the spring
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Assumptions P2 is not needed Assumptions need to be made for other variables in order to find values for k’s D2D2 P2P2 ksks kckc D1D1 P1P1 Finding k c Assumptions Cell is a cylinder Diameter equals length Diameter roughly 10-50 um Calculation kc = E*pi*d/4 kc =.0076-.0393 N/m
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Finding ks D2D2 P2P2 ksks kckc D1D1 P1P1 Assumptions P1 = 1-100 nN D2 = 11 um – ls + D1 Due to limit of optical measuring tool Assume ls = 8 um Made spreadsheet ks = 0.0246 N/m Verification Find increment for D2 that works for range Must be greater than 40 nm Selected 250 nm Check if increment will be detectable
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Overview of Range Case K s (N/m) K c (N/m) P 1 (nN) D 1 (um) D 2 (um) # of Increments Most Elastic Cell.0246.007610022.025.0100 Least Elastic Cell.0246.039311.744.7420
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Spring Dimensions 2 double cantilever beams ks = E*t*(w/l) 3 w = 2.25 um l = 785 um T = 7 um
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Results
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Thank You Questions?
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