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Mealy vs Moore 2 examples of problems where Moore FSM has more than 1 extra state versus Mealy FSM
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Problem Σ o = {t, f} Σ I ={0, 1} Outputs t at least 2 last input digits are same
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Solutions One can see that Mealy implementation needs only 3 states, while Moore implementation needs 2 more almost duplicated states just in order to the output value t there (filled in green).
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Mealy 0 1 S 0/f 0/t 0/f 1/f 1/t
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Moore 0/f 1/f S/f 0 0 0 1 1 00/t 1 11/t 1 0 1 0
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One More Problem Σ o = {t, f} Σ I ={a, b, c} Outputs t the last 3 input symbols were either ‘abc’ or ‘cba’
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Solutions One can see that Mealy implementation needs only 5 states, while Moore implementation needs 2 more almost duplicated states just in order to the output value t there (filled in green).
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Mealy O B’ C A B” b/f c/t b/f a/t a/f c/f a/f c/f b/f a/f c/f b/f
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Moore O /f B’ /f C /f A /f B” /f b c b a a a c c a c b a c b b C /t t A /t t c a a b b c
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