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EART160 Planetary Sciences Francis Nimmo
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Last week Surface temperature depends on solar distance, albedo, atmosphere (greenhouse effect) Scale height and lapse rate are controlled by bulk properties of atmosphere (and gravity) Terrestrial planetary atmospheres are not primordial – affected by loss and outgassing Coriolis effect organizes circulation into “cells” and is responsible for bands seen on giant planets [Isotopic fractionation is a good signal of atmospheric loss due to Jeans escape Significant volatile quantities may be present in the interiors of terrestrial planets]
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Giant Planets What determines their internal structure? How did they form and evolve? What controls their atmospheric dynamics? (Week 5) What about extra-solar planets? Rings not discussed
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Image not to scale! Giant Planets
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Basic Parameters Data from Lodders and Fegley 1998. Surface temperature T s and radius R are measured at 1 bar level. a (AU) P orb (yrs) P rot (hrs) R (km) M (10 26 kg) Obli- quity Density g/cc TsKTsK Jupiter5.211.89.97149219.03.1 o 1.33165 Saturn9.629.410.6602685.726.7 o 0.69134 Uranus19.284.117.2R249730.8697.9 o 1.3276 Neptune30.116516.1247641.0229.6 o 1.6472
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Compositions (1) We’ll discuss in more detail later, but briefly: –(Surface) compositions based mainly on spectroscopy –Interior composition relies on a combination of models and inferences of density structure from observations –We expect the basic starting materials to be similar to the composition of the original solar nebula Surface atmospheres dominated by H 2 or He: (Lodders and Fegley 1998) SolarJupiterSaturnUranusNeptune H2H2 83.3%86.2%96.3%82.5%80% He 16.7%13.6%3.3%15.2% (2.3% CH 4 ) 19% (1% CH 4 )
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Pressure Hydrostatic approximation Mass-density relation These two can be combined (how?) to get the pressure at the centre of a uniform body P c : Jupiter P c =7 Mbar, Saturn P c =1.3 Mbar, U/N P c =0.9 Mbar This expression is only approximate (why?) (estimated true central pressures are 70 Mbar, 42 Mbar, 7 Mbar) But it gives us a good idea of the orders of magnitude involved
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Temperature We discussed this issue last week If a packet of gas rises rapidly (adiabatic), then it will expand and, as a result, cool Work done in expanding = work done in cooling Combining these two equations with hydrostatic equilibrium, we get the dry adiabatic lapse rate: C p is the specific heat capacity of the gas at constant pressure is the mass of one mole, is the density of the gas At 1 bar level on Jupiter, T=165 K, g=23 ms -2, C p ~3R/ , =0.002kg (H 2 ), so dT/dz = 1.8 K/km (adiabatic)
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Hydrogen phase diagram Jupiter – interior mostly metallic hydrogen Hydrogen undergoes a phase change at ~100 GPa to metallic hydrogen (conductive) It is also theorized that He may be insoluble in metallic H. This has implications for Saturn. Interior temperatures are adiabats Saturn – some metallic hydrogen Uranus/Neptune – molecular hydrogen only
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Compressibility & Density As mass increases, radius also increases But beyond a certain mass, radius decreases as mass increases. This is because the increasing pressure compresses the deeper material enough that the overall density increases faster than the mass The observed masses and radii are consistent with a mixture of mainly H+He (J,S) or H/He+ice (U,N) mass radius Constant density
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From Guillot, 2004
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Magnetic fields
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How are they generated? Dynamos require convection in a conductive medium Jupiter/Saturn – metallic hydrogen (deep) Uranus/Neptune - near-surface convecting ices (?) The near-surface convection explains why higher-order terms are more obvious – how? (see Stanley and Bloxham, Nature 2004)
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Summary Jupiter - mainly metallic hydrogen. Rock-ice core ~10 M E. Saturn - mix of metallic and molecular hydrogen; helium may have migrated to centre due to insolubility. Similar rock-ice core to Jupiter. Mean density lower than Jupiter because of smaller self- compression effect (pressures lower). Uranus/Neptune – thin envelope of hydrogen gas. Pressures too low to generate metallic hydrogen. Densities (and moment of inertia data) require large rock-ice cores in the interior. All four planets have large magnetic fields, presumably generated by convection in either metallic hydrogen (J,S) or conductive ices (U,N)
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Giant Planet Formation (see Week 1) Initially solid bodies (rock + ice; beyond snow line) When solid mass exceeded ~10 Me, gravitational acceleration sufficient to trap an envelope of H and He Process accelerated until nebular gas was lost So initial accretion was rapid (few Myr) Uranus and Neptune didn’t acquire so much gas because they were further out and accreted more slowly Planets will have initially been hot (gravitational energy) and subsequently cooled and contracted We can investigate how rapidly they are cooling at the present day...
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Energy budget observations Incident solar radiation much less than that at Earth So surface temperatures are lower We can compare the amount of solar energy absorbed with that emitted. It turns out that there is usually an excess. Why? 5.4 8.1 13.5 48 2.0 2.6 4.6 14 0.6 3.5 0.3 0.6 1.4 incident reflected After Hubbard, in New Solar System (1999) All units in W/m 2 Jupiter Saturn Uranus Neptune
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Sources of Energy One major one is contraction – gravitational energy converts to thermal energy. Helium sinking is another. Gravitational energy of a uniform sphere is So the rate of energy release during contraction is Where does this come from? e.g.Jupiter is radiating 3.5x10 17 W in excess of incident solar radiation. This implies it is contracting at a rate of 0.4 km / million years Another possibility is tidal dissipation in the interior. This turns out to be small. Radioactive decay is a minor contributor.
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Puzzles Why is Uranus’ heat budget so different? –Perhaps due to compositional density differences inhibiting convection at levels deeper than ~0.6R p.May explain different abundances in HCN,CO between Uranus and Neptune atmospheres. –This story is also consistent with generation of magnetic fields in the near-surface region (see earlier slide) Why is Uranus tilted on its side? –Nobody really knows, but a possible explanation is an oblique impact with a large planetesimal (c.f. Earth-Moon) –This impact might even help to explain the compositional gradients which (possibly) explain Uranus’ heat budget
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Atmospheric Structure (1) Atmosphere is hydrostatic: Gas law gives us: Combining these two (and neglecting latent heat): Here R is the gas constant, is the mass of one mole, and RT/g is the scale height of the (isothermal) atmosphere (~10 km) which tells you how rapidly pressure increases with depth
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Atmospheric Structure (2) Lower atmosphere (opaque) is dominantly heated from below and will be conductive or convective (adiabatic) Upper atmosphere intercepts solar radiation and re-radiates it There will be a temperature minimum where radiative cooling is most efficient; in giant planets, it occurs at ~0.1 bar Condensation of species will occur mainly in lower atmosphere Temperature (schematic) tropopause troposphere stratosphere mesosphere ~0.1 bar radiation adiabat CH 4 (U,N only) NH 3 NH 3 +H 2 S H2OH2O 80 K 140 K 230 K 270 K Theoretical cloud distribution clouds
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Giant planet atmospheric structure Note position and order of cloud decks
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Extra-Solar Planets A very fast-moving topic How do we detect them? What are they like? Are they what we would have expected? (No!)
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How do we detect them? The key to most methods is that the star will move (around the system’s centre of mass) in a detectable fashion if the planet is big and close enough 1) Pulsar Timing 2) Radial Velocity planet pulsar A pulsar is a very accurate clock; but there will be a variable time-delay introduced by the motion of the pulsar, which will be detected as a variation in the pulse rate at Earth Earth planet star Earth Spectral lines in star will be Doppler-shifted by component of velocity of star which is in Earth’s line-of-sight. This is easily the most common way of detecting ESP’s.
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How do we detect them? (2) 2) Radial Velocity (cont’d) The radial velocity amplitude is given by Kepler’s laws and is Earth i MsMs MpMp Does this make sense? From Lissauer and Depater, Planetary Sciences, 2001 Note that the planet’s mass is uncertain by a factor of sin i. The M s +M p term arises because the star is orbiting the centre of mass of the system. Present-day instrumental sensitivity is about 3 m/s; Jupiter’s effect on the Sun is to perturb it by about 12 m/s.
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How do we detect them? (3) 3) Occultation (transit) Planet passes directly in front of star. Very rare, but very useful because we can: 1)Obtain M (not M sin i) 2)Obtain the planetary radius 3)Obtain the planet’s spectrum (!) About a dozen examples to date. Light curve during occultation of HD209458. From Lissauer and Depater, Planetary Sciences, 2001 4) Astrometry Not yet demonstrated. 5) Microlensing Ditto. 6) Direct Imaging. Yes! But can’t determine masses...
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What are they like? Big, close, and often highly eccentric – “hot Jupiters” What are the observational biases? From Guillot, Physics Today, 2004 Jupiter Saturn HD209458b is at 0.045 AU from its star and seems to have a radius which is too large for its mass (0.7 M j ). Why? Note the absence of high eccentricities at close distances – what is causing this effect?
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What are they like (2)? Several pairs of planets have been observed, often in 2:1 resonances (Detectable) planets seem to be more common in stars which have higher proportions of “metals” (i.e. everything except H and He) Sun Mean local value of metallicity From Lissauer and Depater, Planetary Sciences, 2001 There are also claims that HD179949 has a planet with a magnetic field which is dragging a sunspot around the surface of the star...
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Exoplanet atmospheres Shorter time constant than Earth’s stratosphere (few hours vs. few days) Laughlin et al. 2009 Fortney et al. 2008 Two classes of atmospheres (depending on Ti, V absorption)
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Puzzles 1) Why so close? –Most likely explanation seems to be inwards migration due to presence of nebular gas disk (which then dissipated) –The reason they didn’t just fall into the star is because the disk is absent very close in, probably because it gets cleared away by the star’s magnetic field. An alternative is that tidal torques from the star (just like the Earth-Moon system) counteract the inwards motion 2) Why the high eccentricities? –No-one seems to know. Maybe a consequence of scattering off other planets during inwards migration? 3) How typical is our own solar system? –Not very, on current evidence
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Consequences What are the consequences of a Jupiter-size planet migrating inwards? (c.f. Triton) Systems with hot Jupiters are likely to be lacking any other large bodies So the timing of gas dissipation is crucial to the eventual appearance of the planetary system (and the possibility of habitable planets...) What controls the timing? Gas dissipation is caused when the star enters the energetic T-Tauri phase – not well understood (?) So the evolution (and habitability) of planetary systems is controlled by stellar evolution timescales – hooray for astrobiology!
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Summary Giant planets primarily composed of H,He with a ~10 M e rock-ice core which accreted first They radiate more energy than they receive due to gravitational contraction (except Uranus!) Clouds occur in the troposphere and are layered according to condensation temperature Many (~300) extra-solar giant planets known Many are close to the star or have high eccentricities – very unlike our own solar system Nebular gas probably produced inwards migration
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Key concepts Adiabat, lapse rate, scale height Hydrogen phase diagram Hydrostatic assumption Compressibility, mass-radius relationship Gravitational contraction Radial velocity Inwards migration Orbital circularization
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End of lecture
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Temperature (2) At 1 bar level on Jupiter, T=165 K, g=23 ms -2, C p ~3R, =0.002kg (H 2 ), so dT/dz = 1.4 K/km (adiabatic) We can also use the expressions on the previous page to derive how the adiabatic temperature varies with pressure This is an example of adiabatic temperature and density profiles for the upper portion of Jupiter, using the same values as above, keeping g constant and assuming =1.5 Note that density increases more rapidly than temperature – why? Slope determined by (Here T 0,P 0 are reference temp. and pressure, and c is constant defined on previous slide)
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