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CS 4700: Foundations of Artificial Intelligence
Carla P. Gomes Module: Propositional Logic: Inference (Reading R&N: Chapter 7)
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Proof Methods
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Proof methods Next module
Current module Proof methods divide into (roughly) two kinds: Application of inference rules Legitimate (sound) generation of new sentences from old Proof = a sequence of inference rule applications Can use inference rules as operators in a standard search algorithm Different types of proofs Model checking truth table enumeration (always exponential in n) (including some inference rules) heuristic search in model space (sound but incomplete) e.g., min-conflicts-like hill-climbing algorithms we’ve talked about this approach Next module
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Proof The sequence of wffs (w1, w2, …, wn) is called a proof (or deduction) of wn from a set of wffs Δ iff each wi in the sequence is either in Δ or can be inferred from a wff (or wffs) earlier in the sequence by using a valid rule of inference. If there is a proof of wn from Δ, we say that wn is a theorem of the set Δ. Δ├ wn (read: wn can be proved or inferred from Δ) The concept of proof is relative to a particular set of inference rules used. If we denote the set of inference rules used by R, we can write the fact that wn can be derived from Δ using the set of inference rules in R: Δ├ R wn (read: wn can be proved from Δ using the inference rules in R)
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Propositional logic: Rules of Inference or Methods of Proof
How to produce additional wffs (sentences) from other ones? What steps can we perform to show that a conclusion follows logically from a set of hypotheses? Example Modus Ponens P P Q ______________ Q The hypotheses are written in a column and the conclusions below the bar; The symbol denotes “therefore”. Given the hypotheses, the conclusion follows. The basis for this rule of inference is the tautology (P (P Q)) Q)
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Propositional logic: Rules of Inference or Methods of Proof
How to produce additional wffs (sentences) from other ones? What steps can we perform to show that a conclusion follows logically from a set of hypotheses? Example Modus Ponens P P Q ______________ Q The hypotheses (premises) are written in a column and the conclusions below the bar The symbol denotes “therefore”. Given the hypotheses, the conclusion follows. The basis for this rule of inference is the tautology (P (P Q)) Q) [aside: check tautology with truth table to make sure] In words: when P and P Q are True, then Q must be True also. (meaning of second implication)
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Propositional logic: Rules of Inference or Methods of Proof
Example Modus Ponens If you study the CS 4700 material You will pass You study the CS4700material ______________ you will pass Nothing “deep”, but again remember the formal reason is that ((P ^ (P Q)) Q is a tautology.
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Propositional logic: Rules of Inference or Method of Proof
Rule of Inference Tautology (Deduction Theorem) Name P P Q P (P Q) Addition P Q P (P Q) P Simplification Q P Q [(P) (Q)] (P Q) Conjunction PQ Q [(P) (P Q)] (P Q) Modus Ponens Q P Q P [(Q) (P Q)] P Modus Tollens Q R P R [(PQ) (Q R)] (PR) Hypothetical Syllogism (“chaining”) P Q P [(P Q) (P)] Q Disjunctive syllogism P R Q R [(P Q) (P R)] (Q R) Resolution
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Valid Arguments Show that (p1 p2 …pn) q is a tautology
An argument is a sequence of propositions. The final proposition is called the conclusion of the argument while the other propositions are called the premises or hypotheses of the argument. An argument is valid whenever the truth of all its premises implies the truth of its conclusion. How to show that q logically follows from the hypotheses (p1 p2 …pn)? Show that (p1 p2 …pn) q is a tautology One can use the rules of inference to show the validity of an argument.
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Proof Tree Proofs can also be based on partial orders – we can represent them using a tree structure: Each node in the proof tree is labeled by a wff, corresponding to a wff in the original set of hypotheses or be inferable from its parents in the tree using one of the rules of inference; The labeled tree is a proof of the label of the root node. Example: Given the set of wffs: P, R, PQ Give a proof of Q R
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What rules of inference
Tree Proof Given: P, P Q, R; Prove: Q R P PQ R Q Q R MP Conj. What rules of inference did we use?
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Length of Proofs Consider premises:
Why bother with inference rules? We could always use a truth table to check the validity of a conclusion from a set of premises. But, resulting proof can be much shorter than truth table method. Consider premises: p_1, p_1 p_2, p_2 p_3 … p_(n-1) p_n To prove conclusion: p_n Inference rules: Truth table: n-1 P steps 2n Key open question: Is there always a short proof for any valid conclusion? Probably not. The NP vs. co-NP question.
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Resolution in Propositional Logic
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Resolution (for CNF) Very important inference rule – several other inference rules can be seen as special cases of resolution. P Q P R Q R Soundness of rule (validity of rule): [(P Q) (P R)] (Q R) is valid Resolution for CNF – applied to a special type of wffs: conjunction of clauses. Literal – either an atom (e.g., P) or its negation (P). Clause – disjunction of of literals (e.g., (P Q R)). Note: Sometimes we use the notation of a set for a clause: e.g. {P,Q,R} corresponds to the clause (PQ R); the empty clause (sometimes written as Nil or {}) is equivalent to False;
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Soundness of Resolution: Validity of the Resolution Inference Rule
P Q P R Q R resolving on P Validity (Tautology): (P Q) (P R) (Q R) ; P Q R (PQ) (PR) (PQ)(PR) (QR) (P Q) (P R) (Q R) 1
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Resolution: Special Cases
1 – Rule of Inference: Chaining R P P Q R Q R P P Q R Q can be re-written Rule of Inference Chaining 2 – Rule of Inference: Modus Ponens P P Q Q P Q can be re-written Rule of Inference: Modus Ponens
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Resolution: Special Cases
3 – Unit Resolution P P Q Q P P Q Q
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Resolution: Caution! No duplications in the resolvent set
only one instance of Q appears in the resolvent, which is a set! P Q R S P Q W Q R S W Resolving one pair at a time DO NOT Resolve on Q and R P Q R P W Q R P R R W P Q R P W Q R P Q Q W P Q R P W Q R P W Resolving on Q Resolving on R True
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Conjunctive Normal Form (CNF)
A wff is in CNF format when it is a conjunction of disjunctions of literals. (P Q R) (S P T R) (Q S) Resolution for CNF – applied to wffs in CNF format. {λ} Σ1 { λ} Σ2 Σ1 Σ2 Σi- sets of literals i =1 ,2 λ – atom; Resolution Resolvent of the two clauses atom resolved upon
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Conversion to CNF P (Q R)
1.Eliminate , replacing α β with (α β)(β α). (P (Q R)) ((Q R) P) 2. Eliminate , replacing α β with α β. (P Q R) ((Q R) P) 3. Move inwards using de Morgan's rules and double-negation: (P Q R) ((Q R) P) 4. Apply distributivity law ( over ) and flatten: (P Q R) (Q P) (R P)
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(P S Q) (P R Q) (P P Q) (P S S)
Converting DNF (Disjunctions of conjunctions) into CNF 1 – create a table – each row corresponds to the literals in each conjunct; 2 - Select a literal in each row and make a disjunction of these literals; Example: (PQ R ) (S R P) (Q S P) P Q R S R P (P S Q) (P R Q) (P P Q) (P S S) (P R S) (P P S) (P P Q)… How many clauses?
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Resolution: Wumpus World
P31 P2,2, P2,2 P31 P?
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Resolution Refutation
Resolution is sound – but resolution is not complete – e.g., (P R) ╞ (P R) but we cannot infer (P R) using resolution we cannot use resolution directly to decide all logical entailments. Resolution is Refutation Complete: We can show that a particular wff W is entailed from a given KB, how? Proof by contradiction: Write the negation of what we are trying to prove (W) as a conjunction of clauses; Add those clauses (W) to the KB (also a set of clauses), obtaining KB’; prove inconsistency for KB’, i.e., Apply resolution to the KB’ until: No more resolvents can be added Empty clause is obtained To show that (P R) ╞Res (P R) do: (1) negate (P R), i.e.: (P) (R) ; (2) prove that (P R) (P) (R) is inconsistent ! !
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Propositional Logic: Proof by refutation or contradiction:
Satisfiability is connected to inference via the following: KB ╞ α if and only if (KB α) is unsatisfiable One assumes α and shows that this leads to a contradiction with the facts in KB
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Resolution: Robot Domain
Example: BatIsOk RobotMoves BatIsOk BlockLiftable RobotMoves Show that KB ╞ BlockLiftable KB BatIsOk BlockLiftable RobotMoves BlockLiftable BatIsOk RobotMoves BatIsOk BlockLiftable RobotMoves BlockLiftable RobotMoves KB’ BatIsOk RobotMoves BatIsOk BatIsOk Nil
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Resolution Resolution is refutation complete (Completeness of resolution refutation): If KB ╞ W, the resolution refutation procedure, i.e., applying resolution on KB’, will produce the empty clause. Decidability of propositional calculus by resolution refutation: If KB is a set of finite clauses and if KB ╞ W, then the resolution refutation procedure will terminate without producing the empty clause. Ground Resolution Theorem If a set of clauses is not satisfiable, then resolution closure of those clauses contains the empty clause. In general, resolution for propositional logic is exponential ! The resolution closure of a set of clauses W in CNF, RC(W), is the set of all clauses derivable by repeated application of the resolution rule to clauses in W or their derivatives.
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Resolution example: Wumpus World
KB = (B1,1 (P1,2 P2,1)) B1, α = P1,2
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Resolution example: Wumpus World
KB = (B1,1 (P1,2 P2,1)) B1, α = P1,2 KB = (B11 (P1,2 P2,1)) ^ ((P1,2 P2,1) B11) B1,1 =(B11 P1,2 P2,1) ^ ((P1,2 P2,1) B11) B1,1 =(B11 P1,2 P2,1) ^(( P1,2 ^ P2,1) B11)) B1,1 =(B11 P1,2 P2,1) ^( P1,2 B11) ^ ( P2,1 B11) B1,1
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Resolution example: Wumpus World
KB = (B1,1 (P1,2 P2,1)) B1, α = P1,2 KB = (B11 (P1,2 P2,1)) ^ ((P1,2 P2,1) B11) B1,1 =(B11 P1,2 P2,1) ^ ((P1,2 P2,1) B11) B1,1 =(B11 P1,2 P2,1) ^(( P1,2 ^ P2,1) B11)) B1,1 =(B11 P1,2 P2,1) ^( P1,2 B11) ^ ( P2,1 B11) B1,1
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Resolution algorithm New resolvents added at the end
Proof by contradiction, i.e., show KBα unsatisfiable New resolvents added at the end
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Resolution algorithm New resolvents added at the end
Proof by contradiction, i.e., show KBα unsatisfiable New resolvents added at the end Any complete search algorithm applying only the resolution rule, can derive any conclusion entailed by any knowledge base in propositional logic – resolution can always be used to either confirm or refute a sentence – refutation completeness (Given A, it’s true we cannot use resolution to derive A OR B; but we can use resolution to answer the question of whether A OR B is true.)
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Resolution Closure Definition
The resolution closure RC(f) of a formula f in CNF is the set of all clauses derivable by repeated application of the resolution rule to clauses in f or their derivatives.
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Resolution Theorem (Ground Resolution Theorem)
If f ( in CNF) is unsatisfiable then RC(f) contains the empty clause (that evolves from P¬P for some variable P). Proof (by contraposition) If RC(f) does not contain the empty clause then it is satisfiable. Let the variables in f be P1,..,Pn, and let us assume that RC(f) does not contain the empty clause. Therefore we can construct a model for m for f with suitable truth values for P1,..,Pn.
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Resolution (contd.) Construction procedure:
For i=1,..,n, if there exists a clause in RC(f) containing the literal ¬Pi such that all its other literals are false under the assignment chosen for P1,..,Pi-1, then assign false to Pi. . Otherwise we set Pi=True. Claim: RC(f)|m is true. I.e., m is a model for f.
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Resolution (contd.) Claim, RC(f)|m is true. I.e., m is a model for f.
Assume the opposite. Then, there exists a clause that evaluates to false under m. Consider a non-satisfied clause in RC(f) over variables P1,..Pi that minimizes i. Wlog, we may write this clause as (ab), where b is a literal over Pi and a is a formula over variables P1,.., Pi-1. Note that there cannot exist another such clause where b is negated (c¬b) as otherwise i was not minimal [consider (ac) RC(f)].
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Resolution (contd.) So we write the clause as (ab), with b a literal over Pi However, then Pi is set such that b evaluates to True, which contradicts the assumption that the clause was not satisfied. Therefore all the clauses are satisfied and m is indeed a model for RC(f). QED
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Resolution Refutation – Ordering Search Strategies
Original clauses – 0th level resolvents Breadth first strategy Generate all 1st level resolvents, then all 2nd level resolvents, etc. Depth first strategy Produce a 1st level resolvent; Resolve the 1st level resolvent with a 0th level resolvent to produce a 2nd level resolvent, etc. With a depth bound, we can use a backtrack search strategy; BlockLiftable BatIsOk BlockLiftable RobotMoves BatIsOk RobotMoves RobotMoves BatIsOk BatIsOk Nil BatIsOk RobotMoves BatIsOk BlockLiftable RobotMoves BlockLiftable 0th level resolvents Depth first strategy
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Refinement Resolution Strategies
Set-of-support Resolution Strategy Definitions: A clause γ2 is a descendant of a clause γ1 iif: Is a resolvent of γ1 with some other clause Or is a resolvent of a descendant of γ1 with some other clause; If γ2 is a descendant of γ1, γ1 is an ancestor of γ2; Set-of-support – set of clauses that are either clauses coming from the negation of the theorem to be proved or descendants of those clauses. Set-of-support Strategy – it allows only refutations in which one of the clauses being resolved is in the set of support. Set-of-support Strategy is refutation complete. BlockLiftable BatIsOk BlockLiftable RobotMoves BatIsOk RobotMoves RobotMoves BatIsOk BatIsOk Nil Set-of-support Strategy
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Refinement Strategies
Ancestry-filtered strategy – allows only resolutions in which at least one member of the clauses being resolved either is a member of the original set of clauses or is an ancestor of the other clause being resolved; The ancestry-filtered strategy is refutation complete.
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Refinement Strategies
Linear Input Resolution Strategy – at least one of the clauses being resolved is a member of the original set of clauses (including the theorem being proved). Linear Input Resolution Strategy is not refutation complete. Example: (P Q) (P Q) (P Q) (P Q) This set of clauses is inconsistent; but there is no linear-input refutation strategy; but there is a resolution refutation strategy; (P Q) (P Q) (P Q) (P Q) Q Q This is NOT Linear Input Resolution Strategy Nil
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: Resolution and Pigeon Hole Principle
Consider a formula to represent the Pigeon Hole principle: (n+1) pigeons in n holes. Pij – pigeon i goes in hole j Pij {0,1} i= 1, 2, …, n+1; j = 1, 2, …n Each pigeon has to go in a hole: Starting with pigeon 1 P11 P12 … P1n … Pn+1,1 Pn+1,2 … Pn+1,n .
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Resolution Proofs of PH
And? Two pigeons cannot go in the same hole P11 ~P21; P11 ~P31; … P11 ~Pn+1,1; ~P11 ~P21; ~P11 ~P31; … ~P11 ~Pn+1,1; …. ~Pn+1,n ~P2,n; ~Pn+1,n ~P3n; … ~Pn+1,n ~Pn,n; Resolution proofs of PH take exponentially many steps: Resolution proofs of inconsistency of PH require an exponential number of clauses, no matter in what order we resolve the clauses (Armin Haken 85). Related to NP vs. Co-NP questions
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Horn Clauses
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Horn Clauses Definition:
A Horn clause is a clause that has at most one positive literal. Examples: P; P Q; P Q; P Q R; Types of Horn Clauses: Fact – single atom – e.g., P; Rule – implication, whose antecendent is a conjunction of positive literals and whose consequent consists of a single positive literal – e.g., PQ R; Head is R; Tail is (PQ ) Set of negative literals - in implication form, the antecedent is a conjunction of positive literals and the consequent is empty. e.g., PQ ; equivalent to P Q. Inference with propositional Horn clauses can be done in linear time !
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Unit Resolution for Horn Clauses
P P Q Q Unit Resolution for Horn Clauses P P Q Q Theorem Unit resolution is refutation complete for HF, i.e. if kb¬a is a HF then unit propagation shows that kb¬a is unsatisfiable iff kb╞ a. Proof If kb¬a is not satisfiable then kb¬a must contain a clause that contains one non-negated variable only:This clause must be a unit clause. (otherwise consider the model that sets all variables to false). Using unit resolution of this variable with all other clauses essentially eliminates the variable from the formula while preserving the Horn property. Continuing this process, unit propagation hits P¬P iff the formula is not satisfiable.
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Forward chaining HORN (Expert Systems and Logic Programming)
Horn Form (restricted) KB = conjunction of Horn clauses Horn clause = proposition symbol; or (conjunction of symbols) symbol E.g., C (B A) (C D B) Modus Ponens (for Horn Form): complete for Horn KBs α1, … ,αn, α1 … αn β β Deciding entailment with Horn clauses can be done in linear time, in the size of the KB !
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Forward Chaining: Diagnosis systems
Example: diagnostic system IF the engine is getting gas and the engine turns over THEN the problem is spark plugs IF the engine does not turn over and the lights do not come on THEN the problem is battery or cables IF the engine does not turn over and the lights come on THEN the problem is starter motor IF there is gas in the fuel tank and there is gas in the carburator THEN the engine is getting gas
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Forward chaining (Data driven reasoning)
Idea: fire any rule whose premises are satisfied in the KB, add its conclusion to the KB, until query is found AND-OR graph
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Forward Chaining Algorithm
Forward chaining is sound and complete for Horn KB Count P => Q 1 L and M => P 2 B and L => M 2 A and P => L 2 A and B => L 2 Inferred P F L F M F B F A F Agenda A B
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Forward chaining example
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Forward chaining example
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Forward chaining example
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Forward chaining example
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Forward chaining example
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Forward chaining example
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Forward chaining example
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Forward chaining example
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Forward Chaining Algorithm
Forward chaining is sound and complete for Horn KB Count P => Q 1 L and M => P 2 B and L => M 2 A and P => L 2 A and B => L 2 Inferred P F L F M F B F A F Agenda A B
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Proof of completeness FC derives every atomic sentence that is entailed by KB FC reaches a fixed point where no new atomic sentences are derived Consider the final state as a model m, assigning true/false to symbols Every clause in the original KB is true in m a1 … ak b Hence m is a model of KB If KB╞ q, q is true in every model of KB, including m
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Backward chaining Idea: work backwards from the query q:
to prove q by BC, check if q is known already, or prove by BC all premises of some rule concluding q Avoid loops: check if new subgoal is already on the goal stack Avoid repeated work: check if new subgoal has already been proved true, or has already failed
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Backward chaining example
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Backward chaining example
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Backward chaining example
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Backward chaining example
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Backward chaining example
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Backward chaining example
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Backward chaining example
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Backward chaining example
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Backward chaining example
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Backward chaining example
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Forward vs. backward chaining
FC is data-driven, automatic, unconscious processing, e.g., object recognition, routine decisions May do lots of work that is irrelevant to the goal BC is goal-driven, appropriate for problem-solving, e.g., Where are my keys? How do I get into a PhD program? Complexity of BC can be much less than linear in size of KB in pactice.
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Prominent expert systems
CADUCEUS (expert system)- Blood-borne infectious bacteria Dendral- Analysis of mass spectra Jess- Java Expert System Shell. A CLIPS engine implemented in Java used in the development of expert systems LogicNets- Web based expert system modeling environment to create expert systems (in collaboration with NASA) Mycin - Diagnose infectious blood diseases and recommend antibiotics (by Stanford University) NEXPERT Object- An early general-purpose commercial backwards-chaining inference engine used in the development of expert systems Prolog- Programming language used in the development of expert systems R1 (expert system)/XCon Order processing STD Wizard - Expert system for recommending medical screening tests PyKe- Pyke is a knowledge-based inference engine (expert system)
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