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Chap 3 Linear Differential Equations
王 俊 鑫(Chun-Hsin Wang) 中華大學 資訊工程系 Fall 2002
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Outline Second-Order Homogeneous Linear Equations
Second-Order Homogeneous Equations with Constant Coefficients Modeling: Mass-Spring Systems, Electric Circuits Euler-Cauchy Equation Wronskian Second-Order Nonhomogeneous Linear Equations Higher Order Linear Differential Equations
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Outline 歐拉-柯西 微分方程 二階線性齊次 常微分方程 高階線性 常微分方程 二階線性 常微分方程 線性 常微分方程 二階
常係數 二階線性齊次 常微分方程 歐拉-柯西 微分方程 二階線性齊次 常微分方程 二階線性非齊次 常微分方程 高階線性 常微分方程 二階線性 常微分方程 線性 常微分方程 二階 常微分方程
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Second-Order ODE General Form for Second-Order Linear ODE
Implicit Form Explicit Form
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Second-Order Homogeneous Linear Equations
Second-Order Homogeneous Linear ODE p(x), q(x): coefficient functions Example
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Examples of Nonlinear differential equations
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A linear combination of Solutions for homogeneous linear equation
Example:
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Second-Order Homogeneous Linear Equations
Linear Principle (Superposition Principle) y is called the linear combination of y1 and y2 If y1 and y2 are the solutions of y = c1y1+ c2y2 is also a solution (c1, c2 arbitrary constants)
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Second-Order Homogeneous Linear Equations
Proof: Note
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Does the Linearity Principle hold for nonhomogeneous linear or nonlinear equations ?
Example: A nonhomogeneous linear differential equation Example: A nonlinear differential equation
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Initial Value Problem for Second-Order homogeneous linear equations
a general solution will be of the form , a linear combination of two solutions involving two arbitrary constants c1 and c2 An initial value problem consists two initial conditions.
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Initial Value Problem Example: Observation:
Our solution would not have been general enough to satisfy the two initial conditions and solve the problem.
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A General Solution of an Homogeneous Linear Equation
Definition: A general solution of an equation on an open interval I is a solution with y1 and y2 not proportional solutions of the equation on I and c1 ,c2 arbitrary constants. The y1 and y2 are then called a basis (or fundamental system) of the equation on I A particular solution of the equation is obtained if we assign specific values to c1 ,c2
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Linear Independent Two functions y1(x) and y2(x) are linear independent on an interval I where they are defined if Example
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How to obtain a Bass if One Solution is Known ?
Method of Reduction Order Given y1 Find y2
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Second-Order Homogeneous Linear Equations
Proof:
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Second-Order Homogeneous Linear Equations
Proof:
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Second-Order Homogeneous Linear Equations
Example 3-1: Sol:
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Second-Order Homogeneous Linear Equations
Exercise 3-1: Basic Verification and Find Particular Solution Basis Initial Condition Basis Initial Condition Basis Initial Condition
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Exercise: Reduce of order if a solution is known.
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Second-Order Homogeneous Equations with Constant Coefficients
General Form of Second-Order Homogeneous Equations with Constant Coefficients whose coefficients a and b are constant.
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Second-Order Homogeneous Equations with Constant Coefficients
Sol: Characteristic Equation
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Second-Order Homogeneous Equations with Constant Coefficients
Case 1: 兩相異實根 Case 2: 重根 Case 3: 共軛虛根
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Second-Order Homogeneous Equations with Constant Coefficients
Example 3-2: Sol: Step 1: Find General Solution
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Second-Order Homogeneous Equations with Constant Coefficients
Step 2: Find Particular Solution
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Second-Order Homogeneous Equations with Constant Coefficients
Step 3: Plot Particular Solution MATLAB Code x=[0:0.01:2]; y=exp(x)+3*exp(-2*x); plot(x,y)
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Case 2 Real Double Root = -a/2
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Second-Order Homogeneous Equations with Constant Coefficients
Example 3-3: Sol: Step 1: Find General Solution
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Second-Order Homogeneous Equations with Constant Coefficients
Step 2: Find Particular Solution
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Second-Order Homogeneous Equations with Constant Coefficients
Step 3: Plot Particular Solution MATLAB Code x=[0:0.01:2]; y=(3-5*x).*exp(2*x); plot(x,y)
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Euler Formula Euler Formula Proof: Maclaurin Series
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Euler Formula Proof:
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Euler Formula 幾何 虛數 分析 自然數 負數
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Complex Exponential Function
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Case 3
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Second-Order Homogeneous Equations with Constant Coefficients
Example 3-4: Sol: Step 1: Find General Solution
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Second-Order Homogeneous Equations with Constant Coefficients
Step 2: Find Particular Solution
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Second-Order Homogeneous Equations with Constant Coefficients
Step 3: Plot Particular Solution MATLAB Code x=[0:0.1:30]; y=exp(-0.1*x).*sin(2*x); plot(x,y)
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Second-Order Homogeneous Equations with Constant Coefficients
Exercise 3-2: Find General Solution 兩相異實根 重根 共軛虛根
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Modeling: Mass-Spring Systems
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Modeling: Electric Circuits
Capacitor (farads) Resistor (ohms) Inductor (heries)
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Modeling
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Modeling Overdamping
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Modeling Critical Damping
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Modeling Underdamping
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Euler-Cauchy Equation
The Auxiliary Equation
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Euler-Cauchy Equation
Case 1: Distinct Real Roots m1, m2 Example 3-5:
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Euler-Cauchy Equation
Case 2: Double Roots m=(1-a)/2
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Euler-Cauchy Case 2 :Example
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Euler-Cauchy Equation
Case 3: Complex Roots m = a ± bi
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Euler-Cauchy Case 3 :Example
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Existence and Uniqueness Theory
If p(x) and q(x) are continuous function on some open interval and x0 is in , then the initial value problem consisting of (1) and (3) has a unique solution y(x) on the interval .
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Wronskian A set of n functions y1(x), y2(x), …, yn(x), is said to be linearly dependent over an interval I if there exist n constants c1, c2, …, cn, not all zero, such that Otherwise the set of functions is said to be linearly independent
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Wronskian A set of n functions y1(x), y2(x), …, yn(x), is linearly independent over an interval I if and only if the determinant (Wronski determinant, or Wronskian)
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Wronskian Example 3-8: Sol: cosx, sinx are linearly independent
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Linear Dependence and Independence of Solution
Suppose that (1) has continuous coefficients p(x) and q(x) on an open interval . Then two solutions y1 and y2 of (1) on are linear dependent on if and only if their Wronskian W is zero at some x0 in . Furthermore, if W=0 for x= x0, then W=0 on ; hence if there is an x1in at which W is not zero, then y1 ,y2 are liner independent on .
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Illustration of Theorem 2
Example 1 Example 2
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A General Solution of (1) includes All Solutions
Theorem 3 (Existence of a general solution) If p(x) and q(x) are continuous on an open interval , then (1) has a general solution on . Theorem 4 (General solution) Suppose that (1) has continuous coefficients p(x) and q(x) on some open interval . Then every solution y=Y(x) of (1) is of the form where y1 , y2 form a basis of solutions of (1) on and c1, c2 are suitable constants. Hence (1) does not have singular solutions (I.e., solutions not obtainable from a general solution)
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Nonhomogeneous Equations
Theorem (a) The difference of two solutions of (1) on some open interval is a solution of (2) on (b) The sum of a solution of (1) and a solution of (2) on is a solution of (1) on
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A general solution of the nonhomogeneous equation (1) on some open interval is a solution of the form where yh(x)=c1y1(x)+c2y2(x) is a general solution of the homogeneous equation (2) on and yp(x) is any solution of (1) on containing no arbitrary constants. A particular solution of (1) on is a solution obtain from (3) by assigning specific values to the arbitrary constants c1 and c2 in yh(x).
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Practical Conclusion To solve the nonohomegeneous equation (1) or an initial value problem for (1) , we have to solve the homogeneous equation (2) and find any particular solution yp of (1)
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Initial value problem for a nonhomogeneous equation
Example
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Solution by Undetermined Coefficients
Method of Undetermined Coefficients General Solution: y = yh + yp yh : Homogeneous Solution yp : Particular Solution
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Solution by Undetermined Coefficients
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Rules for the Method of Undetermined Coefficients
Basic Rule Modification Rule Sum Rule
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Solution by Undetermined Coefficients
Example 3-9: Sol:
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Example for Modification Rule
Example 1: in the case of a simple root Example 2: in the case of a double root Example 3: sum rule.
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Second-Order Non-homogeneous Linear Equations
Method of Variation of Parameters Particular Solution: y1, y2 : Homogeneous Solutions W : Wronskian of y1 and y2
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Second-Order Non-homogeneous Linear Equations
Example 3-10: Sol:
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Higher Order Linear Differential Equations
Higher Order Homogeneous Linear ODE If y1, y2, …, yn are the solutions of y = c1y1+ c2y2 +… + cnyn will be the general solution
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Higher Order Linear Differential Equations
Higher Order Nonhomogeneous Linear ODE General Solution: y = yh + yp yh : Homogeneous Solution yp : Particular Solution
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