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1 Chapter 7 Properties of Water
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2 Structure of Water
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3 Sources of Water on Earth
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4 Properties of Water I – Freezing Point Both liquid and solid can be present together. H 2 O(s) → H 2 O(l) occurs at the same temperature as H 2 O(l) → H 2 O(s) 0 o C at normal atmospheric pressure. Heat of fusion = 334 J/g = 6.01 kJ/mol
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5 Properties of Water II – Boiling Point The temperature at which the vapor pressure becomes equal to surrounding atmospheric pressure. 100 o C at 1 atmosphere. Highly pressure-dependent. Heat of vaporization = 2257 J/g = 40.67 kJ/mol
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8 Properties of Water III – Specific Heat The amount of heat necessary to raise the temperature of one gram of a substance by 1 o C. S.H. of water = 4.184 J/gK Higher for water than nearly any other substance. Heat capacity = heat needed to raise a given mass of substance 1 o C.
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10 Example: Example: Heat Capacity Calculate the heat necessary to raise the temperature of 250 mL of water from 23 o C to 75 o C. S.H. of water = 4.184 J/gK
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11 Solution: Solution: Heat Capacity Calculate the heat necessary to raise the temperature of 250 mL of water from 23 o C to 75 o C. = 54,400 J = 54.4 kJ = 54,400 J = 54.4 kJ
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12 Water – The Universal Solvent
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13 Solubility of Selected Alcohols in Water Alcohol Solubility (g/L) Name CH 3 OH Infinite methanol C 2 H 5 OH Infinite ethanol C 3 H 7 OH Infinite 1-propanol C 4 H 9 OH79 1-butanol C 5 H 11 OH27 1-pentanol C 6 H 13 OH 5.9 1-hexanol C 7 H 15 OH 0.9 1-heptanol
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14 Colligative Properties Properties of a solution that are changed by the number of solute particles, rather than their nature. Vapor Pressure Boiling Point Elevation Freezing Point Depression Osmotic Pressure
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15 Vapor Pressure of Pure Water and Water with a Solute
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16 Boiling Point Elevation Freezing Point Depression T b = K b x m K b for water = 0.512 o C/m T f = K f x m K f for water = 1.86 o C/m
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17 Example: Example: Boiling Point Elevation Calculate the boiling point of a solution of 1.9 mol of sugar (C 12 H 22 O 11 ) dissolved in 400 g of water. T b = K b x m K b for water = 0.512 o C/m
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18 Solution: Solution: Boiling Point Elevation Calculate the boiling point of a solution of 1.9 mol of sugar (C 12 H 22 O 11 ) dissolved in 400 g of water. molality = = 4.7 5 m B.P elevation = 0.512 o C/m x 4.7 5 m = 2.4 o C Boiling Point =102.4 o C Boiling Point = 100 + 2.4 = 102.4 o C
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