1. Tutorial for CIVL252 Hydraulics
By DUAN Huanfeng

2. Example 1 Problem rectangular channel with 6ft width.
y0, y1 are 65ft and 1ft, respectively
horsepower lost =? in the hydraulic jump y0 y1

3. Solution
From section 0 to 1
From section 1 to 2
Head loss (Method 1)

4. head loss (Method 2) For section 1 and 2: V1=64.2ft/s; y1=1ft;
V2=?; y2=15.5ft;
According to continuity EQ:
V2=64.2*1/15.5=4.142ft/s
According to Energy EQ:
HL = (y1+V12/2g) - (y2+V22/2g)=49.2ft

5. Example 2
Problem
Water flows at a steady rate of 12 cfs per foot of width in the wide rectangular concrete channel shown. Pls determine the water surface profile from section 1 to section 2. 1
q=12 cfs/(s*ft)
Slope = 0.04
Rectangular weir 2
3ft

6. Solution First, determine type of the flow regime.
Assume n =0.015; the depth is h1.

7. Second, determine whether a water jump occurs upstream of the weir.

8. Furthermore, determine the distance from the weir to where the hydraulic jump occurs.

9. Complete the water surface profile
0.74ft
3.13ft
5.26ft
57.0ft