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EPPT M2 INTRODUCTION TO RELATIVITY K Young, Physics Department, CUHK The Chinese University of Hong Kong
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CHAPTER 6 VELOCITY, MOMENTUM and ENERGY
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Displacement Velocity Momentum, Conservation Force Newton's second law
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Objectives Momentum Collisions
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Momentum
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Newtonian momentum is wrong Should transform as 4-vector Form of p and E
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Four-velocity
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Coordinates = ( time, space ) Displacement = change of postion
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Example P travels to a star 5 ly away At a speed 0.5c
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Four velocity Displacement per unit proper time
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Example Particle is travelling at 300 m s -1
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Example Particle is travelling at 0.6c
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Case of low velocities is just ordinary velocity carries no information
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Time component carries no extra information True in general
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Three spatial components etc.
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Four-Momentum
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Momentum = mass velocity Now is more convenient
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Explicit expression
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If, = ordinary expression Recover Newtonian physics If as
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Spatial component v = c p = m v v pxpx Do not call this effective mass M!
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Time component
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Assuming mass does not change
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Apart from additive constant, which does not matter
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Provided m 0, takes E = to reach v = c Therefore can never attain v = c v E v = c E 0 = m c 2
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T here was a young fellow named Bright Who travelled much faster than light. He set off one day, in a relative way And come back the previous night! Faster than light?
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Kinetic energy
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Application to collisions "Classical" collisions / Elastic collisions
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Nuclei / Elementary particles Mass is "converted" to energy
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Analogy
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Relation between E and p Newtonian Relativistic
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System of units E :eV MeV GeV pc:eVMeV GeV p:eV/cMeV/cGeV/c mc 2 :eVMeVGeV m:eV/c 2 MeV/c 2 GeV/c 2
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ParticleMass (MeV/ c 2 ) electron0.5110 muon105.7 proton938.3 neutron939.6
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Conservation of four -momentum
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The four-momentum Recall Contains energy + momentum
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Conservation law For an isolated system, the total 4 – momentum is conserved.
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Collisions
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Example 1 1/3 2 0 2 v 1 u
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Better to analyze in terms of p p, E directly measured and quoted v = 0.999… inconvenient formulas apply to massless particles (photons)
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known
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Example Production of p at threshold
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Example P = 150 GeV M = 90 GeV Q Q Z Z e+e+ ee
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Energy in the CM frame
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I n a collision, much of the energy of the projectile is used to carry the whole system forward; only a small fraction is used to produce new particles
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Example ME Both of mass M E * in CM = ? Fixed target experiments are inefficient Colliding beams much better
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Principle of Relativity
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Conservation
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Linear transformation Principle of Relativity
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Objectives Momentum Collisions
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Acknowledgment I thank Miss HY Shik and Mr HT Fung for design
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