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Costas Busch - RPI1 Standard Representations of Regular Languages Regular Languages DFAs NFAs Regular Expressions Regular Grammars.

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Presentation on theme: "Costas Busch - RPI1 Standard Representations of Regular Languages Regular Languages DFAs NFAs Regular Expressions Regular Grammars."— Presentation transcript:

1 Costas Busch - RPI1 Standard Representations of Regular Languages Regular Languages DFAs NFAs Regular Expressions Regular Grammars

2 Costas Busch - RPI2 When we say: We are given a Regular Language We mean:Language is in a standard representation

3 Costas Busch - RPI3 Elementary Questions about Regular Languages

4 Costas Busch - RPI4 Membership Question Question:Given regular language and string how can we check if ? Answer:Take the DFA that accepts and check if is accepted

5 Costas Busch - RPI5 DFA

6 Costas Busch - RPI6 Given regular language how can we check if is empty: ? Take the DFA that accepts Check if there is any path from the initial state to a final state Question: Answer:

7 Costas Busch - RPI7 DFA

8 Costas Busch - RPI8 Given regular language how can we check if is finite? Take the DFA that accepts Check if there is a walk with cycle from the initial state to a final state Question: Answer:

9 Costas Busch - RPI9 DFA is infinite DFA is finite

10 Costas Busch - RPI10 Given regular languages and how can we check if ? Question: Find if Answer:

11 Costas Busch - RPI11 and

12 Costas Busch - RPI12 or

13 Costas Busch - RPI13 Non-regular languages

14 Costas Busch - RPI14 Regular languages Non-regular languages

15 Costas Busch - RPI15 How can we prove that a language is not regular? Prove that there is no DFA that accepts Problem: this is not easy to prove Solution: the Pumping Lemma !!!

16 Costas Busch - RPI16 The Pigeonhole Principle

17 Costas Busch - RPI17 pigeons pigeonholes

18 Costas Busch - RPI18 A pigeonhole must contain at least two pigeons

19 Costas Busch - RPI19........... pigeons pigeonholes

20 Costas Busch - RPI20 The Pigeonhole Principle........... pigeons pigeonholes There is a pigeonhole with at least 2 pigeons

21 Costas Busch - RPI21 The Pigeonhole Principle and DFAs

22 Costas Busch - RPI22 DFA with states

23 Costas Busch - RPI23 In walks of strings:no state is repeated

24 Costas Busch - RPI24 In walks of strings:a state is repeated

25 Costas Busch - RPI25 If string has length : Thus, a state must be repeated Then the transitions of string are more than the states of the DFA

26 Costas Busch - RPI26 In general, for any DFA: String has length number of states A state must be repeated in the walk of...... walk of Repeated state

27 Costas Busch - RPI27 In other words for a string : transitions are pigeons states are pigeonholes...... walk of Repeated state


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