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ELE1110C – Tutorial 2 20-9-2006 Luk Chun Pong Outline -Basic concepts of Capacitors -RC circuits (DC) -Examples
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Capacitor -Store energy in the electric field dielectric conducting plates Q = CV Q: Total Charge C: Capacitance V: Voltage across the capacitor C: actually depends on the permittivity of the dielectric, the area of the plates and the spacing between them.
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Important Laws Capacitor in parallel C = C 1 + C 2 Capacitor in series Proof? In series, current passes through the capacitors is the same In parallel, voltage across the capacitor is the same
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Important Laws (3) Rate of change of voltage across the capacitor the current pass through the capacitor
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Time domain description (case 1) dV/dt = I/C = Constant Current Source (I is constant) dV dt Slope = dV/dt I and C are constants Not common!
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Time domain description (case 2) Constant voltage source R V0V0 VCVC I Current at time t Voltage across the capacitor at time t Remember this is a DC circuit Initial Condition, t = 0: Vc = 0
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Solving the differential equation First order differential equation Separable Differential Equations, integrate both sides Don’t forget the Constant k Substitute using the initial conditions
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General formula for charging and discharging a capacitor Charging Discharging R C V0V0 VcVc
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Charging and discharging Charging Discharging Vc(t) t
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RC circuit: Time constant RC = Resistance of the resistor x Capacitance of the capacitor –How long does it take to charge up/discharge the capacitor –The unit of RC is second t = RC, 63% t = 5RC, 99%
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Question Find out the time needed for 1)Vc = 0.5 V 0 ? 2)Vc = V 0 ? Transient state = Solving differential equations Steady state = Open circuit DC RC circuit
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Problem sheet 2 Q2 In the following circuit, prove that the energy required to charge the capacitor from 0 to V 0 volt is 0.5CV 0 2. What is the energy dissipated in discharging the capacitor from V to 0 volt? Remember this result - the energy dissipated DOES NOT depend on the resistor R!
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Charging
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Discharging
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Another Example Consider the following RC circuit 4kΩ 30V +-+- +-+- 24V 5kΩ 3kΩ 0.5mF v + - t = 0 t > 0 The circuit has been operated at the above state for a long time. At t = 0, the switch move to X, find v at t = 1s X
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Solution For t < 0, v = 15V So, v(0) = 15V Using the general formula, V 0 = 30, Vc(0) = 15, t = 1, CR = 2s Vc(1) = 20.9V
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