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A FemVariational approach to the droplet spreading over dry surfaces S.Manservisi Nuclear Engineering Lab. of Montecuccolino University of Bologna, Italy Department of mathematics Texas Tech University, USA
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Simulations of droplets impacting orthogonally over dry surfaces at Low Reynolds Numbers OUTLINE OF THE PRESENTATION - Introduction to the impact problem - Front tracking method - Variational formulation of the contact problem - Numerical experiments
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Depostion Prompt Splashd Corona Splashd INTRODUCTION
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Depostion Partial reboundd Total reboundd INTRODUCTION
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An experimental An experimental investigation..... C.D. Stow & M.G. Hadfield Spreading smooth surface v=3.65 m/s r=1.65mm INTRODUCTION
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An experimental An experimental investigation..... C.D. Stow & M.G. Hadfield Splashing rough surface v=3.65 m/s r=1.65mm INTRODUCTION
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An experimental INTRODUCTION 1) Problem : Numerical Representation of Interfaces Impact Dynamics : solid surface + liquid interface = drop surface Splash Dynamics : liquid interface -> more liquid interfaces 2) Problem : Correct Physics Impact Dynamics : solid surface + liquid interface = drop surface Splash Dynamics : liquid interface -> more liquid interfaces Hypoteses: No simulation of the impact No splash o total rebound (low Re numbers, no rough surfaces) Axisymmetric simulation Numerical Representation of Interfaces -> ok Correct Physics ?
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Some features: Behavior of the impact for: Wettable-P/Wettable N/Wettable surfaces Deposition – Partial rebound – total rebound Surface capillary waves Spreading ratio and Max spreading ratio Static/Dynamic/apparent Contact angle INTRODUCTION
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D=1.4mm v=0.77m/s Re=1000 We=10 Wettable Partially Wettable Non-Wettable Deposition Partially Wettable Non-Wettable
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INTRODUCTION
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τ= τ(μ) = Stress tensor Dynamics (incompressible. N.S.eqs) incompressible u = velocityp=pressure f_s = Surface tension f = Body force μ =viscosity = μ1 χ + (1-χ) μ2 ρ =viscosity = ρ1 χ + (1-χ) ρ2
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Kinematics (Phase eq.) Equation for χ (phase indicator) χ =0 phase 1 χ =1 phase 2 Solution: 1)Weak form (method of characteristics) 2)Geometrical algorithm
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Boundary conditions Static cos( ) =cos( s) v=0 no-slip boundary condition Non Static cos( ) =cos( s) ? v=0 no-slip boundary condition ?
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V. FORM OF THE STOKES PROBLEM gives
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CONTACT PROBLEM (NO INERTIAL FORCES) = Shape derivative in the direction u
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CONTACT PROBLEM (NO INERTIAL FORCES) Minimization gives No angle condition
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MINIMIZATION WITH PENALTY Remarks: Is a dissipation term Contact angle condition
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CONTACT PROBLEM WITH PENALTY Minimization gives
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Boundary condition over the solid surface Boundary condition Full slip boundary cond
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V.F.OF THE CONTACT PROBLEM Near the contact point otherwise
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Numerical solution Fem solution Weak form -> fem Advection equation -> integral form Density and viscosity are discountinuous -> weak f. Surface term singularity-> weak form
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ADVECTION EQUATION Surface advection Integral form Advection equation
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(2D) Reconstruction Advection ADVECTION EQUATION Markers= intersection (2markers) Conservation (2markers) Fixed mrks (if necessary)
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ADVECTION EQUATION
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Vortex tests ADVECTION EQUATION
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Fem surface tension formulation Surface form Volume form Is extended over the droplet domain
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Static: Laplace equation Solution for bubble v=0, p=p0 Spurious Currents Fem surface tension formulation
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Static: Laplace equation Solution for bubble v=0, p=p0 1)Computation of the curvature 2)Computation of the singular term Solution v=0, v=0 p=0 outside p=P0=a/R inside Fem surface tension formulation
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Casa A: exact curvature Solution Curvature=1/R Surface tens=σ V=0; p=p0 No parassitic currents Fem surface tension formulation
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Case B: Numerical curvature With exact initial shape A t=0 B t=15 C t=50 Curvature Initial velocity Final velocity Fem surface tension formulation
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Case C: Numerical curvature (ellipse) Shape time Fem surface tension formulation
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Steady solution angle=120 angle=60 angle=90
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Boundary condition over the solid surface
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Full slip boundary cond
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Re=100 We=20 =60 Deposition t=0 t=2.5 t=4 t=15 t=50 t=0 t=0.5 t=3 t=1.5 t=1
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Re=100 We=20 =60 Deposition
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Re=100 We=20 =90 partial rebound t=4 t=5 t=0 t=6 t=0 t=3 t=2 t=1.5 t=1 t=0.5 t=0
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t=7 t=9 t=8 t=10 t=11 t=14
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Re=100 We=20 =90 partial rebound
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Re=100 We=20 =120 total rebound t=.5 t=1.5 t=3t=0 t=2 t=4 t=7 t=2.5t=1
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Re=100 We=20 =120 total rebound
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DIFFERENT WETTABILITY Wettable (60) ANon-wettable (120) C partially wettable (90) B
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Re=100 We=100 =120 Re=100 We =120 u0 =120 We= 100 A 50 B 20 C 10 D u0= 2 A 1 B.5 C Different impact velocity Different We
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DYNAMICAL ANGLE Glycerin droplet impact v=1.4m/s D=1.4mm Wettable (18) Partially wettable (90)
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DYNAMICAL ANGLE Friction over the solid surface Friction over the rotation
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DYNAMICAL ANGLE MODEL Cox Blake Power law Jing
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Non-Wettable Wettable D=1.4mm u0=1.4m/s glycerin droplet A=1 B=2 C=10 A=1 B=2 C=10
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D/D0 h angle
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Conclusions - Variational contact models can be used - Open question: Can we simulate large classes of droplet impacts with a unique setting of boundary conditions ?
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Thanks
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