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APPLICATIONS OF THE DERIVATIVE
CHAPTER 3 APPLICATIONS OF THE DERIVATIVE
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3.1 Maxima & Minima Maxima: point whose function value is greater than or equal to function value of any other point in the interval Minima: point whose function value is less than or equal to function value of any other point in the interval Extrema: Either a maxima or a minima
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Where do extrema occur? Peaks or valleys (either on a smooth curve, or at a cusp or corner) f’(c)=0 or f’(c) is undefined Discontinuties Endpoints of an interval These are known as the critical points of the function Once you know you have a critical point, you can test a point on either side to determine if it’s a max or min (or maybe neither…just a leveling off point)
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3.2 Monotonicity and Concavity
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Let f be defined on an interval I (open, closed, or neither). Then f is
INCREASING on I if, DECREASING on I if, MONTONIC on I if it is ether increasing or decreasing
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Monotonicity Theorem Let f be continuous on an interval I and differentiable at every interior point of I. If f’(x)>0 for all x interior to I, then f is increasing on I If f’(x)<0 for all x interior to I, then f is decreasing on I.
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Concave UP vs. Concave DOWN
Let f be differentiable on an open interval I. If f’ is increasing on I, f is concave up (the graph appears to be curved up, as a container that would hold water) If f’ is decreasing on I, f is concave down (the graph appears to be curved down, as if a container were dumping water out)
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Point of Inflection Where concavity changes: goes from concave up to concave down (or vice versa) f’ is neither increasing or decreasing, the change in f’ = 0, thus f’’=0
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Find inflection points & determine concavity for f(x)
Inflection pts: x=-2,0,1 Concave up: (-2,0), (1,infinity) Concave dn: (-inf.,-2), (0,1)
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3.3 Local Extrema and Extrema on Open Intervals
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First Derivative Test Let f be continuous on an open interval (a,b) that contains a critical point c. If f’(x)>0 for all x in (1,c) and f’(x)<0 for all x in (c,b), then f(c) is a local max. value. If f’(x)<0 for all x in (1,c) and f’(x)>0 for all x in (c,b), then f(c) is a local min. value. If f’(x) has the same sign on both sides of c, then f(c) is not a local extreme value.
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Second Derivative Test
Let f’ and f’’ exist at every point in an open interval (a,b) containing c, and suppose that f’(c)=0. a) If f’’(c)<0, then f© is a local max. value of f. b) If f’’(c)>0, then f© is a local min. value of f.
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3.4 Practical Problems Optimization problems – finding the “best” or “least” of “most cost effective”, etc. often involves finding the extrema of the function Use either 1st or 2nd derivative test
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Example A fence is to be constructed using three lengths of fence (the 4th side of the enclosure will be the side of the barn). I have 120 yd. of fencing and the barn is 150’ long. In order to enclose the largest possible area, what dimensions of fence should be used? (continued on next slide)
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Example continued Area is to be optimized: A = l x w
Perimeter = 120 yd = 360’=2l + w w = 360’ – 2l So, 2 lengths of 90’ and a width of 180’. HOWEVER, the barn is only 150’ wide, so in order to enclose the greatest area, we won’t use a critical point of the function, rather we will evaluate the area using the endpoints of the interval, with w=150’. The length = 55’ and the area enclosed = 8250 sq. ft.
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3.5 Graphing Functions Using Calculus
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Critical points & Inflections points
If f’(x) = 0, function levels off at that point (check on either side or use 2nd deriv. test to see if max. or min.) If f’(x) is undefined: cusp, corner, discontinuity, or vertical asymptote (look at behavior and limits of function on either side) If f’’(x) = 0: inflection point, curvature changes
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3.6 Mean Value Theorem for Derivatives
If f is continuous on a closed interval [a,b] and differentiable on the open interval (a,b), then there is at least one number c in (a,b) where
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Example: Find a point within the interval (2,5) where the instantaneous velocity is the same as the average velocity between t=2 and t=5.
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If functions have the same derivatives, they differ by a constant.
If F’(x) = G’(x) for all x in (a,b), then there is a constant C such that F(x) = G(x) + C for all x in (a,b).
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3.7 Solving Equations Numerically Bisection Method Newton’s Method
Fixed-Point Algorithm
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Bisection Method Let f(x) be a continuous function, and let a and b be numbers satisfying a<b and f(a) x f(b) < 0. Let E denote the desired bound for the error (difference between the actual root and the average of a and b). Repeat steps until the solution is within the desired bound for error. Continue next slide.
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Bisection Method
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Newton’s Method Let f(x) be a differentiable function and let x(1) be an initial approximation to the root r of f(x) = 0. Let E denote a bound for the error. Repeat the following step for n = 1,2,… until the difference between successive error terms is within the error.
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Fixed-Point Algorithm
Let g(x) be a continuous function and let x(1) be an initial approximation to the root ro of x = g(x). Let E denote a bound for the error (difference between r and the approximation). Repeat the following step for n – 1,2,… until the difference between succesive approximations are within the error.
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3.8 Antiderivatives Definition: We call F an antiderivative of f on an interval if F’(x) = f(x) for all x in the interval.
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Power Rule
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Integrate = Antidifferentiate Indefinite integral = Antiderivative
Constants can be moved out of the integral Integral of a sum is the sum of the integrals Integral of a difference is the difference of the integrals
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3.9 Introduction to Differential Equations
An equation in which the unknown is a function and that involves derivates (or differentials) of this unknown function is called a differential equation. We will work with only first-order separable differential equations.
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Example Solve the differential equation and find the solution for which y = 3 when x = 1.
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Example continued If x = 1 and y = 3, solve for C.
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